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Category: Logic

2y-y-12-y-1-or-y-12-2y-2-2y-both-are-same-

Question Number 26721 by shiv15031973@gmail.com last updated on 02/Jan/18 $$−\mathrm{2}{y}\left({y}−\mathrm{12}\right)\left({y}−\mathrm{1}\right){or}\left({y}−\mathrm{12}\right)\left(−\mathrm{2}{y}^{\mathrm{2}} −\mathrm{2}{y}\right)\:\:{both}\:{are}\:{same}. \\ $$ Commented by Rasheed.Sindhi last updated on 28/Dec/17 $$\mathrm{Do}\:\mathrm{you}\:\mathrm{mean}\:\frac{−\mathrm{2}{y}\left({y}−\mathrm{12}\right)\left({y}−\mathrm{1}\right)}{\left({y}−\mathrm{12}\right)\left(−\mathrm{2}{y}^{\mathrm{2}} −\mathrm{2}{y}\right)}\:? \\ $$$$\mathrm{If}\:\mathrm{you}\:\mathrm{mean}\:\mathrm{so} \\…

what-are-the-next-two-number-of-this-series-4-7-9-2-5-6-3-8-

Question Number 90801 by john santu last updated on 26/Apr/20 $${what}\:{are}\:{the}\:{next}\:{two}\:{number}\: \\ $$$${of}\:{this}\:{series}\:\mathrm{4},\mathrm{7},\mathrm{9},\mathrm{2},\mathrm{5},\mathrm{6},\mathrm{3},\mathrm{8}\:? \\ $$ Commented by MJS last updated on 26/Apr/20 $${a}_{{n}} =−\frac{\mathrm{17}}{\mathrm{630}}{n}^{\mathrm{7}} +\frac{\mathrm{643}}{\mathrm{720}}{n}^{\mathrm{6}}…

26-R-1-37-1-R-2-3-2-R-3-5-Find-R-1-R-2-and-R-3-

Question Number 90200 by Ar Brandon last updated on 21/Apr/20 $$\mathrm{26}\equiv\mathrm{R}_{\mathrm{1}} \left[\mathrm{37}\right] \\ $$$$\mathrm{1}\:\:\equiv\mathrm{R}_{\mathrm{2}} \left[\mathrm{3}\right] \\ $$$$\mathrm{2}\equiv\mathrm{R}_{\mathrm{3}} \left[\mathrm{5}\right] \\ $$$$\mathrm{Find}\:\mathrm{R}_{\mathrm{1}} ,\:\mathrm{R}_{\mathrm{2}} \mathrm{and}\:\mathrm{R}_{\mathrm{3}} \\ $$ Commented…

Question-24211

Question Number 24211 by Physics lover last updated on 14/Nov/17 Commented by Physics lover last updated on 14/Nov/17 $${The}\:{figure}\:{shows}\:{a}\:{mercury} \\ $$$${barometer}. \\ $$$${find}\:{reading}\:{of}\:{the}\:{weighing}\: \\ $$$${machine}.\:{Density}\:{of}\:{mercury}…

Question-88940

Question Number 88940 by jagoll last updated on 14/Apr/20 Answered by john santu last updated on 14/Apr/20 $$\mathrm{3}^{\mathrm{3}} \:+\:\frac{\mathrm{1}}{\mathrm{4}}\:\left[\mathrm{3}×\mathrm{9}+\mathrm{3}×\mathrm{7}\:\right]\:=\: \\ $$$$\mathrm{27}\:+\:\mathrm{12}\:=\:\mathrm{39}\: \\ $$$$\Rightarrow\mathrm{4}^{\mathrm{3}} \:+\:\frac{\mathrm{1}}{\mathrm{4}}\:\left[\:\mathrm{4}×\mathrm{5}+\mathrm{4}×\mathrm{3}\right]\:=\: \\…

Question-88943

Question Number 88943 by jagoll last updated on 14/Apr/20 Commented by john santu last updated on 14/Apr/20 $$\left.\mathrm{1}\right)\:\mathrm{20}+\mathrm{22}−\mathrm{39}\:=\:\mathrm{3} \\ $$$$\Rightarrow\mathrm{3}^{\mathrm{4}−\mathrm{1}} \:=\:\mathrm{3}^{\mathrm{3}} \:=\:\mathrm{27} \\ $$$$\left.\mathrm{2}\right)\mathrm{7}+\mathrm{7}−\mathrm{13}\:=\:\mathrm{1} \\…