Question Number 176371 by SLVR last updated on 17/Sep/22 Commented by SLVR last updated on 17/Sep/22 $${kindly}\:{tell}\:{me}\:{plese} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 45211 by Tip Top last updated on 10/Oct/18 $$\mathrm{Let}\:\mathrm{A}=\begin{pmatrix}{\mathrm{1}\:\:\:\:\:\mathrm{3}}\\{\mathrm{2}\:\:\:\:\:\mathrm{5}}\end{pmatrix}.\:\mathrm{Find}\:\mathrm{an}\:\mathrm{expression}\: \\ $$$$\mathrm{for}\:\mathrm{the}\:\mathrm{enteries}\:\mathrm{of}\:\mathrm{A}^{\mathrm{n}} . \\ $$ Answered by kaivan.ahmadi last updated on 15/Dec/18 Terms of…
Question Number 44737 by rahul 19 last updated on 04/Oct/18 $${A}\:{and}\:{B}\:{are}\:{two}\:{non}−{singular}\:{matrices} \\ $$$${such}\:{that}\:{A}^{\mathrm{6}} ={I}\:{and}\:{AB}^{\mathrm{2}} ={BA}\left({B}\neq{I}\right). \\ $$$${Then}\:{value}\:{of}\:{K}\:{for}\:{which}\:{B}^{{K}} ={I}. \\ $$ Terms of Service Privacy Policy…
Question Number 44708 by rahul 19 last updated on 03/Oct/18 $${Let}\:{A},{B}\:{be}\:{two}\:{n}×{n}\:{matrices}\:{such} \\ $$$${that}\:{A}+{B}={AB}\:{then}\:{prove}\:: \\ $$$${AB}={BA}\:? \\ $$ Answered by arcana last updated on 03/Oct/18 $$\mathrm{B}=\mathrm{A}\left(\mathrm{B}−\mathrm{I}\right)…
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Question Number 44610 by rahul 19 last updated on 02/Oct/18 $${Let}\:{A}\:{be}\:\mathrm{2}×\mathrm{3}\:{matrix}\:,\:{whereas}\:{B}\:{be} \\ $$$$\mathrm{3}×\mathrm{2}\:{matrix}.\:{If}\:{determinant}\left({AB}\right)=\mathrm{4}, \\ $$$${then}\:{the}\:{value}\:{of}\:{determinant}\:\left({BA}\right)\:? \\ $$ Commented by rahul 19 last updated on 02/Oct/18…
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Question Number 175265 by oustmuchiya@gmail.com last updated on 25/Aug/22 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{matrix}\: \\ $$$$\mathrm{B}=\begin{cases}{\:\:\sqrt{\mathrm{3}}}\\{-\sqrt{\mathrm{5}}}\end{cases}\left.\begin{matrix}{\:\:\:\:\sqrt{\mathrm{2}}}\\{\:\:\:\:\sqrt{\mathrm{7}}}\end{matrix}\right\}\:\mathrm{find}\: \\ $$$$\mathrm{B}^{-\mathrm{1}} \:\mathrm{using}\:\mathrm{row}\:\mathrm{operation} \\ $$ Answered by CElcedricjunior last updated on 25/Aug/22 $$\boldsymbol{{det}}\left(\boldsymbol{{B}}\right)=\sqrt{\mathrm{21}}+\sqrt{\mathrm{10}}…
Question Number 175266 by oustmuchiya@gmail.com last updated on 25/Aug/22 $$\mathrm{Find}\:\mathrm{matrix}\:\mid\mathrm{A}\mid\mathrm{A}^{-\mathrm{1}} \: \\ $$$$\mathrm{given}\:\mathrm{that}\:\mathrm{matrix}\: \\ $$$$\mathrm{A}=\begin{pmatrix}{\sqrt{\mathrm{2}}}&{-\mathrm{1}}&{\mathrm{1}}&{\:\mathrm{0}}\\{\mathrm{4}}&{\mathrm{3}}&{\mathrm{2}}&{-\mathrm{1}}\\{\mathrm{0}}&{\mathrm{2}}&{\mathrm{3}}&{\:\mathrm{1}}\\{\mathrm{1}}&{-\mathrm{1}}&{\mathrm{0}}&{\:\mathrm{1}}\end{pmatrix} \\ $$$$\mathrm{using}\:\mathrm{row}\:\mathrm{operations} \\ $$ Commented by kaivan.ahmadi last updated on…
Question Number 175110 by nadovic last updated on 19/Aug/22 $$\mathrm{Prove}\:\mathrm{that}\begin{vmatrix}{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}\\{{a}}&{{b}}&{{c}}\\{{a}^{\mathrm{2}} }&{{b}^{\mathrm{2}} }&{{c}^{\mathrm{2}} }\end{vmatrix}=\:\left({a}−{b}\right)\left({b}−{c}\right)\left({c}−{a}\right) \\ $$ Commented by kaivan.ahmadi last updated on 19/Aug/22 $$\begin{vmatrix}{\mathrm{1}\:\:\:\:\:\mathrm{1}\:\:\:\:\:\mathrm{1}}\\{{a}\:\:\:\:\:{b}\:\:\:\:\:{c}}\\{{a}^{\mathrm{2}} \:\:\:{b}^{\mathrm{2}} \:\:\:{c}^{\mathrm{2}}…