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Question Number 109240 by bemath last updated on 22/Aug/20 $$\:\:\frac{\flat{emath}}{\bullet\bullet\bullet\bullet\bullet} \\ $$$${use}\:{cayley}\:−\:{hamilton}\:{theorem} \\ $$$${to}\:{calculate}\:{A}^{−\mathrm{1}} \:{for}\:{A}=\begin{pmatrix}{\mathrm{1}\:\:\:\:\:\mathrm{2}\:\:\:\:\:\mathrm{2}}\\{\mathrm{1}\:\:\:\:\:\:\mathrm{2}\:\:−\mathrm{1}}\\{−\mathrm{1}\:\:\mathrm{1}\:\:\:\:\mathrm{4}}\end{pmatrix} \\ $$ Answered by bobhans last updated on 22/Aug/20 $$\:\:\:\:\frac{\flat{o}\flat{hans}}{\leqslant\geqslant\equiv\bullet°#}…
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Question Number 42639 by poojamittal94 last updated on 30/Aug/18 $$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\mathrm{Find}\:\mathrm{LCM}\:\left[\frac{\mathrm{13}}{\mathrm{2}},\frac{\mathrm{2}}{\mathrm{13}},\frac{\mathrm{4}}{\mathrm{7}}\right] \\ $$$$\begin{bmatrix}{\mathrm{57}}\\{\mathrm{0}}\end{bmatrix}× \\ $$ Terms…
JS-js-Given-a-matrix-A-3-2-5-4-and-A-2-A-2I-0-where-is-a-constant-I-1-0-0-1-If-B-3-2-5-1-then-A-1-B-
Question Number 108059 by john santu last updated on 14/Aug/20 $$\:\:\:\frac{\heartsuit{JS}\heartsuit}{°{js}°} \\ $$$${Given}\:{a}\:{matrix}\:{A}=\begin{pmatrix}{\:\:\:\mathrm{3}\:\:\:\:\:\:\:\mathrm{2}}\\{−\mathrm{5}\:\:\:−\mathrm{4}}\end{pmatrix} \\ $$$${and}\:{A}^{\mathrm{2}} +\flat{A}−\mathrm{2}{I}=\mathrm{0}\:{where}\:\flat\:{is}\:{a} \\ $$$${constant}\:,\:{I}=\begin{pmatrix}{\mathrm{1}\:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\mathrm{1}}\end{pmatrix}.\:{If}\:{B}\:= \\ $$$$\begin{pmatrix}{−\mathrm{3}\flat\:\:\:\:\:\:\mathrm{2}}\\{\:\:\:\mathrm{5}\flat\:\:\:\:−\mathrm{1}}\end{pmatrix}\:,\:{then}\:{A}^{−\mathrm{1}} {B}\:=\: \\ $$ Answered by…
Question Number 107547 by hgrocks last updated on 11/Aug/20 Commented by hgrocks last updated on 11/Aug/20 Can anyone solve this Q without using eigen values Commented by bemath last updated on 11/Aug/20 $${tr}\left({M}\right)\:=\:{trace}\left({M}\right)?…
Question Number 107196 by mr W last updated on 09/Aug/20 $${How}\:{many}\:{different}\:{words}\:{can}\:{be} \\ $$$${formed}\:{with}\:{the}\:{same}\:{letters}\:{as}\:{in} \\ $$$${TINKUTARA}\:{if}\:{no}\:{two}\:{same}\:{letters} \\ $$$${are}\:{next}\:{to}\:{each}\:{other}. \\ $$ Commented by john santu last updated…
Question Number 41447 by rahul 19 last updated on 07/Aug/18 Answered by tanmay.chaudhury50@gmail.com last updated on 08/Aug/18 Commented by tanmay.chaudhury50@gmail.com last updated on 08/Aug/18 Terms…
Question Number 41392 by rahul 19 last updated on 06/Aug/18 $$\mathrm{If}\:\mathrm{both}\:\mathrm{A}−\:\frac{\mathrm{I}}{\mathrm{2}}\:\mathrm{and}\:\mathrm{A}+\frac{\mathrm{I}}{\mathrm{2}}\:\mathrm{are}\:\mathrm{orthogonal} \\ $$$$\mathrm{matrices},\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\: \\ $$$$\mathrm{A}^{\mathrm{2}} =\:−\frac{\mathrm{3}}{\mathrm{4}}\:\mathrm{I}. \\ $$ Commented by rahul 19 last updated on…