Question Number 41332 by rahul 19 last updated on 05/Aug/18 $$\mathrm{In}\:\mathrm{Matrices},\: \\ $$$$\mathrm{Is}\:\left(\mathrm{A}^{−\mathrm{1}} \right)\mathrm{B}\:=\:\mathrm{B}\left(\mathrm{A}^{−\mathrm{1}} \right)\:? \\ $$ Commented by rahul 19 last updated on 06/Aug/18…
Question Number 41321 by rahul 19 last updated on 05/Aug/18 $$\mathrm{If}\:\mathrm{A}\:\mathrm{is}\:\mathrm{a}\:\mathrm{square}\:\mathrm{matrix}\:\mathrm{of}\:\mathrm{order}\:\mathrm{3},\:\mathrm{then} \\ $$$$\:\mid\left(\mathrm{A}−\mathrm{A}^{\mathrm{T}} \right)^{\mathrm{2011}} \mid\:=\:? \\ $$ Commented by rahul 19 last updated on 05/Aug/18…
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Question Number 172005 by Mikenice last updated on 23/Jun/22 $${find}\:{x}:\:\left({log}_{\mathrm{10}} {x}\right)^{\mathrm{2}} −{log}_{\mathrm{10}} {x}=\mathrm{0} \\ $$ Answered by puissant last updated on 23/Jun/22 $${X}={log}_{\mathrm{10}} {x}\:\:\:\Rightarrow\:\:{X}^{\mathrm{2}} −{X}=\mathrm{0}…
Question Number 40910 by rahul 19 last updated on 29/Jul/18 Answered by tanmay.chaudhury50@gmail.com last updated on 29/Jul/18 $${let}\:{the}\:{required}\:{eqn}\:{is} \\ $$$$\left({x}−{A}\right)\left({x}−{B}\right)\left({x}−{C}\right)=\mathrm{0} \\ $$$${A}=\alpha+\beta+\gamma−\mathrm{2}\gamma \\ $$$$\:\:{A}=\frac{−{b}}{{a}}−\mathrm{2}\gamma\:\:\:{B}=\frac{−{b}}{{a}}−\mathrm{2}\alpha\:\:\:{C}=\frac{−{b}}{{a}}−−\mathrm{2}\beta \\…
Question Number 40418 by Tinkutara last updated on 21/Jul/18 Commented by tanmay.chaudhury50@gmail.com last updated on 21/Jul/18 $${pls}\:{check}\:{the}\:{question}… \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
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Question Number 171441 by alcohol last updated on 15/Jun/22 $${I}_{{n}} \:=\:−\frac{\mathrm{2}{n}}{\mathrm{2}{n}\:+\:\mathrm{1}}\:{I}_{{n}−\mathrm{1}} \\ $$$${I}_{\mathrm{0}} \:=\:\mathrm{1} \\ $$$${Show}\:{that}\:{I}_{{n}} \:=\:\frac{\left(−\mathrm{4}\right)^{{n}} \left({n}!\right)^{\mathrm{2}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!} \\ $$ Commented by infinityaction last…
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Question Number 171064 by 119065 last updated on 07/Jun/22 $${When}\:\:{A}^{−\mathrm{1}} =\begin{bmatrix}{\mathrm{3}}&{\mathrm{1}}\\{\mathrm{8}}&{\mathrm{4}}\end{bmatrix} \\ $$$${find}\:{the}\:\:{A}=?\:,\mid{A}^{−\mathrm{1}} \mid\centerdot{A}=? \\ $$ Answered by som(math1967) last updated on 07/Jun/22 $$\:{Adj}\:{A}^{−\mathrm{1}} =\begin{bmatrix}{\mathrm{4}}&{−\mathrm{8}}\\{−\mathrm{1}}&{\mathrm{3}}\end{bmatrix}^{{T}}…