Matrices and Determinants – Page 2

A-M-2-2-and-det-A-0-A-3-A-2-A-det-A-2I-

Tinku Tara November 5, 2024 Matrices and Determinants 0 Comments

Question Number 213435 by mnjuly1970 last updated on 14/Nov/24 $A \in M_{2 \times 2}, a n d, d e t (A) \neq 0 : A^{3} = A^{2} + A$ $\Rightarrow d e t (A - 2 I) = ?$ Terms of Service Privacy…

Question-212844

Tinku Tara October 25, 2024 Matrices and Determinants 0 Comments

Question Number 212844 by efronzo1 last updated on 25/Oct/24 $⇃ \underset{―}{}$ Commented by AlagaIbile last updated on 29/Oct/24 $d e t (S^{2}) = {d e t}^{2} (S) = 36$ $$\:{det}\left({S}\right)\:=\:\pm\:\mathrm{6} \…

Question-211902

Tinku Tara September 23, 2024 Matrices and Determinants 0 Comments

Question Number 211902 by Gangadhar last updated on 23/Sep/24 Commented by BHOOPENDRA last updated on 24/Sep/24 $3$ Answered by BHOOPENDRA last updated on…

Question-208624

Tinku Tara June 19, 2024 Matrices and Determinants 0 Comments

Question Number 208624 by vipin last updated on 19/Jun/24 Answered by Berbere last updated on 19/Jun/24 $\frac{1}{{c o s e c}^{-} (- \sqrt{2})} = \sin^{- 1} (- \frac{1}{\sqrt{2}}) = - \frac{π}{4}$ $f (x) . \tan^{- 1} (\frac{\sqrt{1 + x} - \sqrt{1 - x}}{\sqrt{1 + x} + \sqrt{1 - x}}) = \tan^{- 1} (\frac{1 - \sqrt{\frac{1 - x}{1 + x}}}{1 + \sqrt{\frac{1 - x}{1 + x}}}) \dots E$ $${g}\left({y}\right)=\mathrm{tan}^{−\mathrm{1}}…

Question-208359

Tinku Tara June 13, 2024 Matrices and Determinants 0 Comments

Question Number 208359 by alcohol last updated on 13/Jun/24 Commented by alcohol last updated on 13/Jun/24 $p l e a s e h e l p$ Answered by Berbere last updated on…

Question-207931

Tinku Tara May 31, 2024 Matrices and Determinants 0 Comments

Question Number 207931 by efronzo1 last updated on 31/May/24 Answered by Lochinbek last updated on 31/May/24 Answered by mr W last updated on 31/May/24 Commented…

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Tinku Tara March 25, 2024 Matrices and Determinants 0 Comments

Question Number 205586 by necx122 last updated on 25/Mar/24 $G i v e m t h a t t h e m a t r i x A = (\begin{matrix} 3 & 1 & 5 \\ 2 & 3 & 5 \\ 5 & 1 & 6 \end{matrix}) .$ $I f A d j . A = (\begin{matrix} 13 & - 1 & - 10 \\ 13 & - 7 & - 5 \\ - 13 & 2 & 7 \end{matrix})$ $(i) f i n d A^{- 1}$ $(i i) U s e t h e r e s u l t i n (i) t o f i n d t h e$ $v a l u e s o f x, y a n d z t h a t w i l l s a t i s f y t h e$ $e q u a t i o n s :$ $3 x + y + 5 z = 8$ $$\mathrm{2}{x}\:+\mathrm{3}{y}\:+\:\mathrm{5}{z}\:=\:\mathrm{0} \…

Question-205306

Tinku Tara March 15, 2024 Matrices and Determinants 0 Comments

Question Number 205306 by peter frank last updated on 15/Mar/24 Answered by A5T last updated on 15/Mar/24 $2 (3 x^{2} + 4 x y) = 450 \Rightarrow 3 x^{2} + 4 x y = 225$ $$\Rightarrow{y}=\frac{\mathrm{225}−\mathrm{3}{x}^{\mathrm{2}} }{\mathrm{4}{x}}\Rightarrow{v}=\mathrm{3}{x}^{\mathrm{2}} {y}=\frac{\mathrm{3}{x}\left(\mathrm{225}−\mathrm{3}{x}^{\mathrm{2}} \right)}{\mathrm{4}}…