Question Number 148446 by puissant last updated on 28/Jul/21 $$\mathrm{Soit}\:\mathrm{a},\mathrm{b},\mathrm{c}\:\mathrm{et}\:\alpha\:\mathrm{4}\:\mathrm{nombres}\:\mathrm{rationnels} \\ $$$$\mathrm{telque}\:\sqrt[{\mathrm{3}}]{\alpha}\:\mathrm{est}\:\mathrm{irrationnel}.. \\ $$$$\mathrm{Demontrer}\:\mathrm{que}\:: \\ $$$$\left(\mathrm{a}\sqrt[{\mathrm{3}}]{\alpha}+\mathrm{b}\sqrt[{\mathrm{3}}]{\alpha}=\mathrm{c}\right)\:\Rightarrow\:\left(\mathrm{a}=\mathrm{b}=\mathrm{c}\right).. \\ $$ Commented by Olaf_Thorendsen last updated on 28/Jul/21…
Question Number 82101 by legocole last updated on 18/Feb/20 $${Make}\:\mathrm{2}\:\mathrm{3}×\mathrm{3}\:{matrices}\:{i}\:{and}\:{j} \\ $$$${such}\:{that} \\ $$$${i}^{\mathrm{2}} ={j} \\ $$$${j}^{\mathrm{2}} ={i} \\ $$$${ij}=−\mathrm{1} \\ $$ Commented by Kunal12588…
Question Number 81906 by ahmadshahhimat775@gmail.com last updated on 16/Feb/20 Commented by mr W last updated on 16/Feb/20 $$\left.{w}\left.{hat}'{s}\:{the}\:{difference}\:{between}\:\mathrm{2}\right)\:{and}\:\mathrm{4}\right)? \\ $$ Terms of Service Privacy Policy…
Question Number 146687 by gflood92 last updated on 14/Jul/21 $${E}\:=\:{MC}^{\mathrm{2}\:} \:\:\:\:\:\:\:\:\:\int{requency}\:=\:{E}/{M} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 80830 by jagoll last updated on 07/Feb/20 $${given}\:{A}\:{a}\:{square}\:{matrix}\:{non} \\ $$$${singular}\:{A}\neq\:{I}. \\ $$$${find}\:{A}\:{such}\:{that}\:{A}^{\mathrm{3}} \:=\:{I} \\ $$ Answered by ~blr237~ last updated on 07/Feb/20 $${M}={diag}\left(\mathrm{1},{j},\overset{−}…
Question Number 145101 by alcohol last updated on 02/Jul/21 Commented by alcohol last updated on 02/Jul/21 $${Correction}\:{please} \\ $$$${A}\:=\begin{pmatrix}{\mathrm{1}}&{\mathrm{1}}\\{\mathrm{3}}&{−\mathrm{1}}\end{pmatrix} \\ $$$${please}\:{help}\:{me}\:{solve}\:{it}\: \\ $$ Terms of…
Question Number 78670 by berket last updated on 19/Jan/20 $${let}\:{A}=\begin{bmatrix}{{a}\:\:{b}}\\{{c}\:\:{d}}\end{bmatrix}{use}\:{the}\:{augmented}\:{matrix}\left[{A}\:{I}\right]\:{and}\:{elementary}\:{row}\:{operation}\:{to}\:{show}\:{A}^{−\mathrm{1}} =\:\frac{\mathrm{1}}{{ad}\:{bc}}\begin{bmatrix}{{a}\:\:{b}}\\{{c}\:\:\:{d}}\end{bmatrix}{and}\:{show}\:{that}\:{det}\left({A}^{−\mathrm{1}} \right)=\frac{\mathrm{1}}{{det}\left({A}\right)} \\ $$$$ \\ $$ Commented by abdomathmax last updated on 20/Jan/20 $${Pc}\left({A}\right)={det}\left({A}−{xI}\right)\:=\begin{vmatrix}{{a}−{x}\:\:\:\:\:\:\:{b}}\\{{c}\:\:\:\:\:\:\:\:\:\:{d}−{x}}\end{vmatrix} \\…
Question Number 358 by 123456 last updated on 25/Jan/15 $$\mathrm{A}=\begin{bmatrix}{{x}}&{−{y}}\\{{y}}&{{x}}\end{bmatrix} \\ $$$$\mathrm{X}=\begin{bmatrix}{{x}}\\{{y}}\end{bmatrix} \\ $$$$\mathrm{Y}=\mathrm{AX} \\ $$ Answered by prakash jain last updated on 24/Dec/14 $${AX}=\begin{bmatrix}{{x}^{\mathrm{2}}…
Question Number 346 by 123456 last updated on 25/Jan/15 $$\Gamma\left(\theta\right)=\begin{bmatrix}{\mathrm{cos}\:\theta}&{\mathrm{sin}\:\theta}\\{−\mathrm{sin}\:\theta}&{\mathrm{cos}\:\theta}\end{bmatrix} \\ $$$$\Lambda\left(\theta,{t}\right)=\begin{bmatrix}{\mathrm{cos}\:\theta}&{\mathrm{sinh}\:{t}\:\mathrm{sin}\:\theta}\\{\mathrm{sin}\:\theta}&{\mathrm{cosh}\:{t}\:\mathrm{cos}\:\theta}\end{bmatrix} \\ $$$$\zeta\left(\theta,{t}\right)=\Gamma\left(\theta\right)×\Lambda\left(\theta,{t}\right)+\Lambda\left(\theta,{t}\right)×\Gamma\left(\theta\right) \\ $$$$\zeta\left(\theta,\mathrm{0}\right)=? \\ $$$$\mathrm{det}\:\zeta\left(\theta,\mathrm{0}\right)=? \\ $$ Answered by prakash jain last…
Question Number 275 by shahid.ansari56@yahoo.com last updated on 25/Jan/15 $$\mathrm{6867865396}\boldsymbol{\div}\mathrm{678} \\ $$$$ \\ $$ Answered by ssahoo last updated on 18/Dec/14 $$=\mathrm{10129594}.\mathrm{979351} \\ $$ Terms…