Category: Matrices and Determinants

Question Number 141974 by 676597498 last updated on 25/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 76326 by Master last updated on 26/Dec/19 Answered by benjo last updated on 26/Dec/19 $$\mathrm{using}\:\mathrm{determinan}\:\mathrm{Vandermon}\:\mathrm{de}\:\mathrm{method}\: \\ $$ Commented by Master last updated on…

Question Number 141400 by Raffaqet last updated on 18/May/21 $${fjnd}\:{inverse}\:{of}\:{matrix}\begin{bmatrix}{\mathrm{2}}&{−\mathrm{5}}\\{\mathrm{1}}&{\mathrm{3}}\end{bmatrix} \\ $$ Answered by iloveisrael last updated on 18/May/21 $$\:{A}^{−\mathrm{1}} \:=\:\frac{\mathrm{1}}{\mathrm{6}−\left(−\mathrm{5}\right)}\:\begin{bmatrix}{\:\:\:\:\mathrm{3}\:\:\:\:\:\mathrm{5}}\\{−\mathrm{1}\:\:\:\:\:\mathrm{2}}\end{bmatrix} \\ $$$${A}^{−\mathrm{1}} \:=\:\begin{bmatrix}{\mathrm{3}/\mathrm{11}\:\:\:\:\:\:\:\:\:\mathrm{5}/\mathrm{11}}\\{−\mathrm{1}/\mathrm{11}\:\:\:\:\:\mathrm{2}/\mathrm{11}}\end{bmatrix} \\…

Question Number 10268 by j.masanja06@gmail.com last updated on 01/Feb/17 Answered by sandy_suhendra last updated on 01/Feb/17 $$\left(\mathrm{x}−\mathrm{3}\right)\left(\mathrm{x}+\mathrm{5}\right)\left(\mathrm{x}−\mathrm{1}\right)+\mathrm{6}+\mathrm{42}−\mathrm{6}\left(\mathrm{x}+\mathrm{5}\right)+\mathrm{6}\left(\mathrm{x}−\mathrm{3}\right)+\mathrm{7}\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{0} \\ $$$$\mathrm{x}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} −\mathrm{10x}+\mathrm{8}=\mathrm{0} \\ $$$$\left(\mathrm{x}−\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{8}\right)=\mathrm{0} \\…

Question Number 10243 by j.masanja06@gmail.com last updated on 31/Jan/17 $$\mathrm{solve}\:\mathrm{the}\:\mathrm{eqution} \\ $$$$\:\:\:\:\:\begin{vmatrix}{\mathrm{x}−\mathrm{3}}&{\mathrm{1}}&{−\mathrm{1}}\\{−\mathrm{7}}&{\mathrm{x}+\mathrm{5}}&{−\mathrm{1}}\\{−\mathrm{6}}&{\mathrm{6}}&{\mathrm{x}−\mathrm{1}}\end{vmatrix}=\mathrm{0} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com