Question Number 57044 by mr W last updated on 29/Mar/19 Commented by mr W last updated on 29/Mar/19 $${reposted} \\ $$$${Question}\:{from}\:{Tinkutara}\:{sir} \\ $$ Answered by…
Question Number 56510 by Tawa1 last updated on 17/Mar/19 Commented by MJS last updated on 17/Mar/19 $$\mathrm{well},\:\mathrm{the}\:\mathrm{determinant}\:\mathrm{is} \\ $$$$\mathrm{2}{a}^{\mathrm{4}} {bc}+\mathrm{2}{ab}^{\mathrm{4}} {c}+\mathrm{2}{abc}^{\mathrm{4}} +\mathrm{6}{a}^{\mathrm{3}} {b}^{\mathrm{2}} {c}+\mathrm{6}{a}^{\mathrm{3}} {bc}^{\mathrm{2}}…
Question Number 56339 by Tinkutara last updated on 14/Mar/19 Answered by tanmay.chaudhury50@gmail.com last updated on 15/Mar/19 $${x}={a}_{\mathrm{3}} {y}+{a}_{\mathrm{2}} \left({a}_{\mathrm{2}} {x}+{a}_{\mathrm{1}} {y}\right) \\ $$$${x}−{a}_{\mathrm{2}} ^{\mathrm{2}} {x}={y}\left({a}_{\mathrm{3}}…
Question Number 56090 by Tawa1 last updated on 10/Mar/19 Commented by math1967 last updated on 10/Mar/19 $${pls}\:{check}\:{I}\:{think}\:{it}\:{should}\:{be} \\ $$$$\begin{vmatrix}{{bc}}&{{ca}}&{{ab}}\\{{a}}&{{b}}&{{c}}\\{{a}^{\mathrm{2}} }&{{b}^{\mathrm{2}} }&{{c}^{\mathrm{2}} }\end{vmatrix} \\ $$ Commented…
Question Number 121523 by benjo_mathlover last updated on 09/Nov/20 $$\mathrm{Given}\:\mathrm{A}\:\mathrm{a}\:\mathrm{3×3}\:\mathrm{matrix}\:\mathrm{satisfy}\: \\ $$$$\rightarrow\begin{cases}{\mathrm{A}\begin{pmatrix}{\mathrm{1}}\\{\mathrm{2}}\\{\mathrm{3}}\end{pmatrix}\:=\:\begin{pmatrix}{\mathrm{3}}\\{\mathrm{4}}\\{\mathrm{2}}\end{pmatrix}}\\{\mathrm{A}\begin{pmatrix}{\mathrm{5}}\\{\mathrm{9}}\\{\mathrm{7}}\end{pmatrix}\:=\:\begin{pmatrix}{\mathrm{3}}\\{\mathrm{1}}\\{\mathrm{2}}\end{pmatrix}}\end{cases} \\ $$$$.\:\mathrm{Find}\:\mathrm{A}\begin{pmatrix}{\mathrm{10}}\\{\mathrm{18}}\\{\mathrm{14}}\end{pmatrix}\:?\: \\ $$ Commented by liberty last updated on 09/Nov/20 $$\Leftrightarrow\:\mathrm{A}\begin{pmatrix}{\mathrm{10}}\\{\mathrm{18}}\\{\mathrm{14}}\end{pmatrix}\:=\:\mathrm{2A}\begin{pmatrix}{\mathrm{5}}\\{\mathrm{9}}\\{\mathrm{7}}\end{pmatrix}\:=\:\mathrm{2}\begin{pmatrix}{\mathrm{3}}\\{\mathrm{1}}\\{\mathrm{2}}\end{pmatrix}\:=\:\begin{pmatrix}{\mathrm{6}}\\{\mathrm{2}}\\{\mathrm{4}}\end{pmatrix} \\…
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Question Number 55663 by peter frank last updated on 01/Mar/19 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Mar/19 $${b}_{\mathrm{1}} \:{b}_{\mathrm{2}\:} \:{b}_{\mathrm{3}} \:{b}_{\mathrm{4}} \:{b}_{\mathrm{5}} \:{b}_{\mathrm{6}} \:{b}_{\mathrm{7}} \:{b}_{\bigstar}…
Question Number 55422 by Tinkutara last updated on 23/Feb/19 $${Please}\:{see}\:{these}\:{questions}: \\ $$ Commented by Tinkutara last updated on 23/Feb/19 https://goiit.com/uploads/default/original/3X/0/8/0852a69d881889ef7f6f41a47072adf1af91cda4.JPG Terms of Service Privacy Policy…
Question Number 55374 by gunawan last updated on 23/Feb/19 $$\mathrm{Given}\:\mathrm{matrices}\:{A}\left({x}\right)=\begin{bmatrix}{{x}−\mathrm{1}}&{\mathrm{3}}\\{\mathrm{4}}&{{x}+\mathrm{3}}\end{bmatrix}\in\:{M}_{\mathrm{2}} \left(\mathbb{R}\right). \\ $$$$\mathrm{The}\:\mathrm{smallest}\:\mathrm{det}\left({A}\left({x}\right)\right)\:\mathrm{is}.. \\ $$ Answered by Joel578 last updated on 23/Feb/19 $$\mid{A}\left({x}\right)\mid\:=\:\left({x}\:−\:\mathrm{1}\right)\left({x}\:+\:\mathrm{3}\right)\:−\:\mathrm{12} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:{x}^{\mathrm{2}}…