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Question Number 212239 by Spillover last updated on 07/Oct/24 Answered by Ghisom last updated on 08/Oct/24 $$\int\frac{\mathrm{e}^{−{x}/\mathrm{2}} \sqrt{\mathrm{1}−\mathrm{sin}\:{x}}}{\mathrm{1}+\mathrm{cos}\:{x}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\mathrm{tan}\:\frac{{x}}{\mathrm{2}}\right] \\ $$$$=\int\frac{\mathrm{e}^{−\mathrm{arctan}\:{t}} \left({t}−\mathrm{1}\right)}{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}}{dt}= \\…
Question Number 212209 by efronzo1 last updated on 06/Oct/24 $$\:\:\:\cancel{\underbrace{\gtrdot}}\: \\ $$ Answered by som(math1967) last updated on 06/Oct/24 $$\:{let}\:{no}\:{of}\:{solders}\:{in}\:{A},{B},{C}\:{are} \\ $$$${x},{y},{z} \\ $$$$\therefore\mathrm{37}{x}+\mathrm{23}{y}=\mathrm{29}{x}+\mathrm{29}{y} \\…
Question Number 211018 by peter frank last updated on 26/Aug/24 Commented by peter frank last updated on 27/Aug/24 $$\mathrm{thank}\:\mathrm{you}\:\mathrm{mr}\:\mathrm{frix} \\ $$ Answered by Frix last…
Question Number 208526 by Tawa11 last updated on 17/Jun/24 Commented by Tawa11 last updated on 17/Jun/24 $$\mathrm{Find}\:\:\mid\mathrm{SP}\mid \\ $$$$\mathrm{Is}\:\mathrm{this}\:\mathrm{question}\:\mathrm{correct}\:\mathrm{like}\:\mathrm{this}? \\ $$ Commented by Tawa11 last…
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Question Number 206808 by mustafazaheen last updated on 26/Apr/24 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{10}^{\mathrm{x}} −\mathrm{1}}{\mathrm{x}^{\mathrm{10}} } \\ $$ Answered by mr W last updated on 26/Apr/24 $$\mathrm{10}^{{x}} ={e}^{{x}\mathrm{ln}\:\mathrm{10}}…
Question Number 206294 by sniper237 last updated on 11/Apr/24 $${Solve}\:{the}\:{system} \\ $$$$\left({a}+{b}\right)^{−\mathrm{1}} +{c}^{−\mathrm{1}} =\mathrm{2}^{−\mathrm{1}} \\ $$$$\left({c}+{b}\right)^{−\mathrm{1}} +{a}^{−\mathrm{1}} =\mathrm{3}^{−\mathrm{1}} \\ $$$$\left({a}+{c}\right)^{−\mathrm{1}} +{b}^{−\mathrm{1}} =\mathrm{4}^{−\mathrm{1}} \\ $$ Commented…
Question Number 206212 by cortano21 last updated on 09/Apr/24 Commented by Frix last updated on 09/Apr/24 $${f}'\left(\mathrm{0}\right)={c}\:\mathrm{which}\:\mathrm{is}\:\mathrm{independent}\:\mathrm{of}\:{a} \\ $$ Commented by TheHoneyCat last updated on…
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