Question Number 191062 by Mingma last updated on 17/Apr/23 Answered by mr W last updated on 17/Apr/23 Commented by mr W last updated on 17/Apr/23…
Question Number 125491 by ajfour last updated on 11/Dec/20 Commented by ajfour last updated on 11/Dec/20 $${If}\:{outermost}\:{triangle}\:{is}\:{equilateral} \\ $$$${and}\:{radius}\:{of}\:{circle}\:{is}\:{unity},\:{find} \\ $$$${maximum}\:{brown}\:{shaded}\:{area}. \\ $$ Answered by…
Question Number 125444 by ajfour last updated on 11/Dec/20 Commented by ajfour last updated on 11/Dec/20 $${Find}\:{radius}\:{of}\:{the}\:{quarter}\:{circle}. \\ $$ Answered by ajfour last updated on…
Question Number 125337 by ajfour last updated on 10/Dec/20 Commented by ajfour last updated on 10/Dec/20 $${If}\:{all}\:{coloured}\:{areas}\:{are}\:\mathrm{10}\:{units} \\ $$$${each},\:{find}\:{coordinates}\:{of}\:{G}. \\ $$$$\left({FGE}\:\:\:{and}\:{CGD}\:{are}\:{straight}\right. \\ $$$$\left.{segments}\right) \\ $$…
Question Number 190845 by Rupesh123 last updated on 13/Apr/23 Answered by som(math1967) last updated on 13/Apr/23 Commented by som(math1967) last updated on 13/Apr/23 $${ar}\bigtriangleup{ABC}=\frac{\mathrm{1}}{\mathrm{2}}{ADEB}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{10}=\mathrm{5}{squ} \\…
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Question Number 190790 by Rupesh123 last updated on 11/Apr/23 Commented by Frix last updated on 11/Apr/23 $$\frac{{a}}{{b}}=\pi−\mathrm{1}+\sqrt{\pi^{\mathrm{2}} −\mathrm{2}\pi} \\ $$ Terms of Service Privacy Policy…
Question Number 125215 by ajfour last updated on 09/Dec/20 Commented by ajfour last updated on 09/Dec/20 $${A}\:{cylindrical}\:{hole}\:{of}\:{radius}\:{half} \\ $$$${that}\:{of}\:{the}\:{sphere}\:{is}\:{drilled}\:{out}\:, \\ $$$${touching}\:{the}\:{equatorial}\:{plane}\:{of} \\ $$$${sphere}.\:{Find}\:{fraction}\:{of}\:{volume} \\ $$$${drilled}\:{out}.…
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Question Number 125108 by peter frank last updated on 08/Dec/20 Commented by mr W last updated on 08/Dec/20 $${where}\:{did}\:{you}\:{get}\:{these}\:{questions}? \\ $$$${they}\:{are}\:{wrong},\:{i}.{e}.\:{there}\:{is}\:{no} \\ $$$${solution}. \\ $$$${the}\:{last}\:{digit}\:{of}\:\mathrm{2}^{{any}\:{integer}}…