Question Number 188981 by Mingma last updated on 10/Mar/23 Answered by HeferH last updated on 10/Mar/23 Commented by HeferH last updated on 13/Mar/23 $$\:\frac{{r}+\mathrm{1}}{\:\sqrt{\mathrm{5}}+\mathrm{1}}\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}−\mathrm{1}} \\…
Question Number 188980 by Mingma last updated on 10/Mar/23 Answered by HeferH last updated on 10/Mar/23 Commented by HeferH last updated on 10/Mar/23 $${x}\:=\:\mathrm{55}° \\…
Question Number 188901 by Mingma last updated on 08/Mar/23 Answered by Frix last updated on 08/Mar/23 $${AB}=\sqrt{\mathrm{8}^{\mathrm{2}} +\left(\mathrm{10}−\mathrm{4}\right)^{\mathrm{2}} }=\mathrm{10} \\ $$$${BC}=\sqrt{\mathrm{8}^{\mathrm{2}} +\mathrm{10}^{\mathrm{2}} }=\mathrm{2}\sqrt{\mathrm{41}} \\ $$$${R}_{{ABC}}…
Question Number 123302 by peter frank last updated on 24/Nov/20 Answered by MJS_new last updated on 24/Nov/20 $${y}={a}\left({x}−\mathrm{2}\right)\left({x}+\mathrm{2}\right)={ax}^{\mathrm{2}} −\mathrm{4}{a} \\ $$$$\mathrm{3}=−\mathrm{3}{a}\:\Rightarrow\:{a}=−\mathrm{1} \\ $$$${y}=\mathrm{4}−{x}^{\mathrm{2}} \\ $$$$\mathrm{the}\:\mathrm{rest}\:\mathrm{is}\:\mathrm{easy}…
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Question Number 188759 by Rupesh123 last updated on 06/Mar/23 Answered by a.lgnaoui last updated on 06/Mar/23 $$\left.\mathrm{D}\right)\:\mathrm{22} \\ $$ Answered by a.lgnaoui last updated on…
Question Number 123212 by 676597498 last updated on 24/Nov/20 Commented by 676597498 last updated on 24/Nov/20 $${pls}\:{i}\:{need}\:{help} \\ $$ Answered by MJS_new last updated on…
Question Number 123141 by ajfour last updated on 23/Nov/20 Commented by ajfour last updated on 23/Nov/20 $${Find}\:{side}\:{length}\:{of}\:{the}\:{congruent} \\ $$$${squares}\:{if}\:{BC}=\mathrm{1}\:{and}\:{AC}\:{such} \\ $$$${that}\:{two}\:{such}\:{congruent}\:{squares} \\ $$$${be}\:{possible}.\:\angle{B}\:=\:\mathrm{90}°. \\ $$…
Question Number 188669 by Rupesh123 last updated on 04/Mar/23 Answered by HeferH last updated on 04/Mar/23 $$\mathrm{9}−\left({r}−\frac{\mathrm{7}}{\mathrm{2}}\right)^{\mathrm{2}} =\:{r}^{\mathrm{2}} −\left(\frac{\mathrm{7}}{\mathrm{2}}\right)^{\mathrm{2}} \\ $$$${r}\:=\:\frac{\mathrm{9}}{\mathrm{2}} \\ $$ Answered by…
Question Number 123131 by ajfour last updated on 23/Nov/20 Commented by ajfour last updated on 23/Nov/20 $${Find}\:{x}\:{in}\:{terms}\:{of}\:{c}\:<\:\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}\:\centerdot \\ $$ Terms of Service Privacy Policy Contact:…