Category: Mensuration

Question Number 200249 by Calculusboy last updated on 16/Nov/23 $$\boldsymbol{{Solve}}:\:\:\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{distance}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{point}}\:\boldsymbol{{P}}\left(\mathrm{3},\mathrm{4}\right)\:\boldsymbol{{from}}\:\boldsymbol{{the}}\:\boldsymbol{{line}}\:\boldsymbol{{y}}=−\mathrm{2}\boldsymbol{{x}}+\mathrm{3} \\ $$ Commented by mr W last updated on 18/Nov/23 Answered by Frix last updated…

Question Number 198532 by Hridiana last updated on 21/Oct/23 $${forum}\:{fast} \\ $$$${symbols}\:{acquired}.\: \\ $$$${x\%x\%x\%x}\:{is}\:{x\%}^{\mathrm{4}} {x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 197950 by York12 last updated on 05/Oct/23 $${Let}\:{x},{y},{z}>\mathrm{0}\:,\:{x}+{y}+{z}=\mathrm{3}\:{Prove}\:{That}\:: \\ $$$$\frac{\mathrm{1}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}}}+\frac{\mathrm{1}}{\:\sqrt{{z}^{\mathrm{2}} +\mathrm{2}{z}}}+\sqrt{\mathrm{3}}\left(\frac{\mathrm{1}}{{y}+\mathrm{2}}−\frac{{y}}{\mathrm{9}}\right)+\frac{\sqrt[{\mathrm{3}}]{\sqrt{{x}}+\sqrt{{y}}+\sqrt{{z}}+\mathrm{24}}}{\:\sqrt{\mathrm{3}}}\geqslant\frac{\mathrm{17}}{\mathrm{3}\sqrt{\mathrm{3}}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 197569 by Amidip last updated on 22/Sep/23 Commented by a.lgnaoui last updated on 23/Sep/23 $$\boldsymbol{\mathrm{I}}\:\:\mathrm{think}\:\mathrm{the}\:\mathrm{question}\:\mathrm{is}\:\mathrm{to}\:\mathrm{find}\:\boldsymbol{\mathrm{DG}}\:? \\ $$ Commented by mr W last updated…

Question Number 196571 by cortano12 last updated on 27/Aug/23 Answered by som(math1967) last updated on 27/Aug/23 $$\:{x}=\sqrt{\mathrm{6}^{\mathrm{2}} +\mathrm{7}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} }=\sqrt{\mathrm{121}}=\mathrm{11}{cm} \\ $$ Answered by hafeez…