Question Number 49111 by Pk1167156@gmail.com last updated on 03/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 03/Dec/18 Commented by Pk1167156@gmail.com last updated on 03/Dec/18 Very nice sir Commented…
Question Number 114638 by bobhans last updated on 20/Sep/20 $${Given}\:{a}\:=\:\frac{\mathrm{1}^{\mathrm{2}} +\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +…+\mathrm{16}^{\mathrm{2}} −\mathrm{16}}{\mathrm{1}.\mathrm{3}+\mathrm{2}.\mathrm{4}+\mathrm{3}.\mathrm{5}+…+\mathrm{15}.\mathrm{17}} \\ $$$$\:\:\:{c}\:=\:\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\right).\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}\right).\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}\right).\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}}\right). \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{5}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}\right)\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}\right). \\ $$$${find}\:{a}×{c}\:=\: \\ $$ Answered by bemath…
Question Number 48984 by peter frank last updated on 30/Nov/18 Commented by mr W last updated on 01/Dec/18 $${director}\:{circle}\:{of}\:{a}\:{circle}\:{is} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\left(\sqrt{\mathrm{2}}{a}\right)^{\mathrm{2}} \\ $$$${or}…
Question Number 48982 by peter frank last updated on 30/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 01/Dec/18 $$\left.\mathrm{2}\right)\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}={sin}\left(\frac{\pi}{\mathrm{6}}\right)\:\:\:\frac{\mathrm{1}}{\mathrm{2}}={cos}\left(\frac{\pi}{\mathrm{6}}\right) \\ $$$${e}^{{i}\theta} ={cos}\theta+{isin}\theta\:\leftarrow{demoivers}\:{theorem} \\ $$$${e}^{−{i}\theta} ={cos}\theta−{isin}\theta \\…
Question Number 48920 by peter frank last updated on 30/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 30/Nov/18 $${y}={e}^{−\mathrm{2}{mx}} {sin}\mathrm{4}{mx} \\ $$$$\frac{{dy}}{{dx}}={e}^{−\mathrm{2}{mx}} ×\mathrm{4}{mcos}\mathrm{4}{mx}−\mathrm{2}{me}^{−\mathrm{2}{mx}} {sin}\mathrm{4}{mx} \\ $$$$\frac{{dy}}{{dx}}=\mathrm{4}{me}^{−\mathrm{2}{mx}}…
Question Number 114447 by bemath last updated on 19/Sep/20 Commented by bemath last updated on 19/Sep/20 $${gave}\:{kudos}\:{all}\:{master}\: \\ $$ Answered by abdullahquwatan last updated on…
Question Number 114071 by bobhans last updated on 17/Sep/20 $${Find}\:{the}\:{solution}\:{set}\: \\ $$$$\sqrt{{x}^{\mathrm{2}} −\mathrm{4}{x}−\mathrm{5}}\:\geqslant\:{x} \\ $$ Commented by prakash jain last updated on 17/Sep/20 $$ \\…
Question Number 48517 by ajfour last updated on 24/Nov/18 Commented by ajfour last updated on 25/Nov/18 $${Find}\:{ratio}\:{of}\:{maximum}\:{triangle} \\ $$$${area}\:\left({with}\:{A}\:{and}\:{B}\:{fixed}\right)\:{to} \\ $$$${ellipse}\:{area}. \\ $$ Answered by…
Question Number 48501 by peter frank last updated on 24/Nov/18 Answered by Abdulhafeez Abu qatada last updated on 25/Nov/18 $$ \\ $$$$\left(\frac{{df}}{{dx}}\right)_{{y}} \:=\:\mathrm{sin}{x}\left(\mathrm{sin}\left({x}+{y}\right)\mathrm{cos}{y}\:+\:\mathrm{cos}\left({x}+{y}\right)\mathrm{sin}{y}\right) \\ $$$$\left(\frac{{df}}{{dx}}\right)_{{y}}…
Question Number 48338 by ajfour last updated on 22/Nov/18 Commented by mr W last updated on 23/Nov/18 $${nice}\:{working}! \\ $$ Commented by ajfour last updated…