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Category: Mensuration

Question-48501

Question Number 48501 by peter frank last updated on 24/Nov/18 Answered by Abdulhafeez Abu qatada last updated on 25/Nov/18 $$ \\ $$$$\left(\frac{{df}}{{dx}}\right)_{{y}} \:=\:\mathrm{sin}{x}\left(\mathrm{sin}\left({x}+{y}\right)\mathrm{cos}{y}\:+\:\mathrm{cos}\left({x}+{y}\right)\mathrm{sin}{y}\right) \\ $$$$\left(\frac{{df}}{{dx}}\right)_{{y}}…

Question-179088

Question Number 179088 by cortano1 last updated on 24/Oct/22 Answered by mr W last updated on 24/Oct/22 $$\boldsymbol{{Method}}\:\mathrm{1} \\ $$$$\mathrm{cos}\:\alpha=\frac{\mathrm{7}}{{R}} \\ $$$${R}^{\mathrm{2}} −\mathrm{7}^{\mathrm{2}} =\mathrm{58}^{\mathrm{2}} +\mathrm{92}^{\mathrm{2}}…

Question-178839

Question Number 178839 by ARUNG_Brandon_MBU last updated on 22/Oct/22 Answered by HeferH last updated on 22/Oct/22 $$\:{Side}\:{of}\:{the}\:{square}\:=\:\sqrt{\mathrm{8}}\:=\:\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\:{l}_{\mathrm{1}} =\:\mathrm{2}\sqrt{\mathrm{2}}\:−\left(\:\frac{\sqrt{\mathrm{6}}\:+\:\sqrt{\mathrm{2}}}{\mathrm{2}}\right)=\:\frac{\mathrm{3}\sqrt{\mathrm{2}}\:−\sqrt{\mathrm{6}}}{\mathrm{2}} \\ $$$$\:{l}_{\mathrm{2}} =\:\mathrm{2}\sqrt{\mathrm{2}}\:+\:\left(\frac{\sqrt{\mathrm{6}}\:−\:\sqrt{\mathrm{2}}}{\mathrm{2}}\right)=\:\frac{\mathrm{3}\sqrt{\mathrm{2}}\:+\:\sqrt{\mathrm{6}}\:}{\mathrm{2}} \\ $$$$\:{l}_{\mathrm{1}}…