Question Number 45284 by ajfour last updated on 11/Oct/18 Commented by ajfour last updated on 11/Oct/18 $${DP}\:=\:{DT}\:=\:{b}−\mathrm{1}\:\:;\:\:\:\:{BT}\:=\:{a}−\mathrm{1} \\ $$$${BD}={DT}+{BT} \\ $$$$\Rightarrow\:\:\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }\:=\:{a}+{b}−\mathrm{2}\:\:\: \\ $$$$\Rightarrow\:\mathrm{2}{ab}−\mathrm{4}{a}−\mathrm{4}{b}+\mathrm{4}=\mathrm{0}…
Question Number 176354 by BaliramKumar last updated on 16/Sep/22 Answered by Frix last updated on 16/Sep/22 $$\mathrm{in}\:\bigtriangleup\:\mathrm{with}\:\mathrm{sides}\:{a},\:{b},\:{c} \\ $$$${r}=\frac{\sqrt{\left({a}+{b}+{c}\right)\left(−{a}+{b}+{c}\right)\left({a}−{b}+{c}\right)\left({a}+{b}−{c}\right)}}{\mathrm{2}\left({a}+{b}+{c}\right)} \\ $$$$\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:{r}=\mathrm{15} \\ $$ Commented by…
Question Number 176281 by BaliramKumar last updated on 15/Sep/22 Commented by amin96 last updated on 15/Sep/22 Commented by BaliramKumar last updated on 16/Sep/22 $${thanks}\:{Sir} \\…
Question Number 44749 by ajfour last updated on 04/Oct/18 Commented by ajfour last updated on 04/Oct/18 $${An}\:{overlap}\:{of}\:{square}\:{and}\:{cicle}, \\ $$$${such}\:{that}\:{the}\:{three}\:{coloured}\:{areas} \\ $$$${are}\:{equal};\:{Relate}\:\boldsymbol{{a}}\:{and}\:\boldsymbol{{R}}. \\ $$ Answered by…
Question Number 109834 by 675480065 last updated on 25/Aug/20 Commented by 675480065 last updated on 25/Aug/20 $$\mathrm{Greetings}. \\ $$$$\mathrm{please}\:\mathrm{i}\:\mathrm{need}\:\mathrm{help} \\ $$ Answered by mathmax by…
Question Number 43992 by ajfour last updated on 19/Sep/18 Commented by ajfour last updated on 19/Sep/18 $${If}\:{square}\:{has}\:{as}\:{much}\:{area}\: \\ $$$${outside}\:{circle}\:{as}\:{circle}\:{has} \\ $$$${outside}\:{square},\:{relate}\:\boldsymbol{{a}},\:{and}\:\boldsymbol{{R}}. \\ $$ Answered by…
Question Number 43728 by Cheyboy last updated on 14/Sep/18 Commented by A.Haq.Soomro last updated on 15/Sep/18 $$\mathrm{See}\:\mathrm{Q}#\mathrm{6852} \\ $$ Answered by MrW3 last updated on…
Question Number 43531 by pieroo last updated on 11/Sep/18 $$\mathrm{the}\:\mathrm{circumference}\:\mathrm{of}\:\mathrm{a}\:\mathrm{circular}\:\mathrm{track}\:\mathrm{is}\:\mathrm{9}\:\mathrm{km}.\:\mathrm{A}\:\mathrm{cyclist} \\ $$$$\mathrm{rides}\:\mathrm{round}\:\mathrm{it}\:\mathrm{a}\:\mathrm{number}\:\mathrm{of}\:\mathrm{times}\:\mathrm{and}\:\mathrm{stops}\:\mathrm{after} \\ $$$$\mathrm{covering}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{302}\:\mathrm{km}.\:\mathrm{How}\:\mathrm{far}\:\mathrm{is}\:\mathrm{the}\:\mathrm{cyclist} \\ $$$$\mathrm{from}\:\mathrm{the}\:\mathrm{starting}\:\mathrm{point}?\:\left[\mathrm{take}\:\Pi=\frac{\mathrm{22}}{\mathrm{7}}\right] \\ $$ Commented by pieroo last updated on 12/Sep/18…
Question Number 108987 by bobhans last updated on 20/Aug/20 Answered by bemath last updated on 20/Aug/20 $$\:\:\:\:\frac{\mathcal{B}{e}\mathcal{M}{ath}}{\blacksquare\mathcal{C}\square\square\mathcal{L}\blacksquare} \\ $$$${because}\:\mid{x}−\mathrm{3}\mid\:+\:\mathrm{2}\:>\:\mathrm{0}\:{for}\:{x}\:\in\:\mathbb{R} \\ $$$${then}\:\mathrm{3}−\mid{x}−\mathrm{3}\mid\:<\:\mathrm{4}\mid{x}−\mathrm{3}\mid\:+\:\mathrm{8} \\ $$$$\Rightarrow−\mathrm{5}\mid{x}−\mathrm{3}\mid\:<\:\mathrm{5}\: \\ $$$$\Rightarrow\mid{x}−\mathrm{3}\mid\:>\:−\mathrm{2}\:\Rightarrow\:\forall{x}\in\mathbb{R}…
Question Number 43252 by ajfour last updated on 08/Sep/18 Commented by MJS last updated on 08/Sep/18 $$\mathrm{circle}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{1} \\ $$$${y}=\sqrt{\mathrm{1}−{x}^{\mathrm{2}} } \\ $$$$\mathrm{parabola}\:{x}={ay}^{\mathrm{2}} −\mathrm{1}…