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Category: Mensuration

Question-105883

Question Number 105883 by bemath last updated on 01/Aug/20 Answered by mr W last updated on 01/Aug/20 $${AG}=\sqrt{\mathrm{3}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} −\mathrm{2}×\mathrm{3}×\mathrm{6}×\mathrm{cos}\:\mathrm{120}°}=\mathrm{3}\sqrt{\mathrm{7}} \\ $$$$\frac{\mathrm{sin}\:\angle{AGF}}{\mathrm{3}}=\frac{\mathrm{sin}\:\mathrm{120}°}{\mathrm{3}\sqrt{\mathrm{7}}} \\ $$$$\mathrm{sin}\:\angle{AGF}=\frac{\sqrt{\mathrm{21}}}{\mathrm{14}} \\…

Cube-ABCD-EFGH-with-length-side-2-cm-Point-P-is-the-center-of-ABFE-plane-The-distance-of-HP-line-and-the-BG-line-is-

Question Number 105404 by bemath last updated on 28/Jul/20 $${Cube}\:{ABCD}.{EFGH}\:{with} \\ $$$${length}\:{side}\:\mathrm{2}\:{cm}.\:{Point}\:{P}\:{is}\:{the} \\ $$$${center}\:{of}\:{ABFE}\:{plane}.\:{The} \\ $$$${distance}\:{of}\:{HP}\:{line}\:{and}\:{the}\:{BG} \\ $$$${line}\:{is}\:\_\_\: \\ $$ Answered by john santu last…

Question-104841

Question Number 104841 by bramlex last updated on 24/Jul/20 Commented by 1549442205PVT last updated on 24/Jul/20 $$\mathrm{please},\mathrm{who}\:\mathrm{can}\:\mathrm{translate}\:\mathrm{this} \\ $$$$\mathrm{language}\:\mathrm{to}\:\mathrm{English}\:\mathrm{or}\:\mathrm{tell}\:\mathrm{me}\:\mathrm{it}\:\mathrm{is} \\ $$$$\mathrm{what}\:\:\mathrm{language}\:\mathrm{so}\:\mathrm{i}\:\mathrm{can}\:\mathrm{get}\:\mathrm{help}\:\mathrm{from} \\ $$$$\mathrm{other}\:\mathrm{person}. \\ $$…