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Category: Mensuration

Question-100387

Question Number 100387 by bemath last updated on 26/Jun/20 Answered by smridha last updated on 26/Jun/20 $$\boldsymbol{{A}}\rightarrow\boldsymbol{{D}}\rightarrow\boldsymbol{{C}}\rightarrow\boldsymbol{{E}}\rightarrow\boldsymbol{{A}}\rightarrow\boldsymbol{{B}}\rightarrow\boldsymbol{{F}}\rightarrow\boldsymbol{{C}}\rightarrow\boldsymbol{{B}}\rightarrow\boldsymbol{{E}}\rightarrow\boldsymbol{{D}} \\ $$ Terms of Service Privacy Policy Contact:…

lim-n-1-2-3-4-5-6-n-1-2-1-2-1-2-1-2-1-2-1-2-1-2-

Question Number 99793 by bachamohamed last updated on 23/Jun/20 $$\:\:\boldsymbol{{li}}\underset{\boldsymbol{{n}}\rightarrow\infty} {\boldsymbol{{m}}}\:\left(\mathrm{1}\left(\mathrm{2}\left(\mathrm{3}\left(\mathrm{4}\left(\mathrm{5}\left(\mathrm{6}\left(….\left(\mathrm{n}.\right)^{\frac{\mathrm{1}}{\mathrm{2}}} ..\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} =?\:\:\:\right. \\ $$ Commented by Dwaipayan Shikari last…

Question-98919

Question Number 98919 by  M±th+et+s last updated on 17/Jun/20 Commented by  M±th+et+s last updated on 17/Jun/20 $${let}\:\bigtriangleup{ABC}\:{is}\:{an}\:{equilateral}\:{triangle} \\ $$$${then}\:{find}\: \\ $$$$ \\ $$$${i}.\:\:\:{arg}\left(\frac{{Z}_{\mathrm{2}} −{Z}_{\mathrm{3}} }{{Z}_{\mathrm{3}}…