Question Number 30233 by ajfour last updated on 18/Feb/18 Commented by ajfour last updated on 18/Feb/18 $${Find}\:{maximum}\:{area}\:{of}\:{quadrilateral} \\ $$$${ABCD}\:\:{if}\:\:{sides}\:{AB},\:{BC},\:{CD},\:{DA} \\ $$$${be}\:{a},\:{b},\:{c},\:{d}\:\:{respectively},\:{with} \\ $$$$\:\:{a}\:<\:{b}\:<\:{c}\:<\:{d}\:. \\ $$…
Question Number 95707 by john santu last updated on 27/May/20 Commented by john santu last updated on 27/May/20 $$\mathrm{find}\:\mathrm{the}\:\mathrm{shaded}\:\mathrm{area}\: \\ $$ Commented by john santu…
Question Number 30120 by ajfour last updated on 16/Feb/18 Commented by ajfour last updated on 16/Feb/18 $${Determine}\:\boldsymbol{\rho},\:\boldsymbol{\eta},\:\boldsymbol{\sigma},\:\boldsymbol{\epsilon}\:\:\:{in}\:{terms} \\ $$$${of}\:\boldsymbol{\lambda}\:{and}\:\boldsymbol{\mu}\:. \\ $$ Answered by mrW2 last…
Question Number 29723 by ajfour last updated on 11/Feb/18 Commented by ajfour last updated on 11/Feb/18 $${Express}\:\boldsymbol{{c}}\:{in}\:{terms}\:{of}\:\boldsymbol{{a}},\:\boldsymbol{{b}}\:. \\ $$ Answered by mrW2 last updated on…
Question Number 95246 by Crabby89p13 last updated on 24/May/20 Answered by mr W last updated on 24/May/20 Commented by mr W last updated on 24/May/20…
Question Number 29627 by ajfour last updated on 10/Feb/18 Commented by ajfour last updated on 10/Feb/18 $${Also}\:{find}\:\frac{\boldsymbol{{a}}}{\boldsymbol{{R}}}\:{if}\:{length}\:{of}\:{AB}\:{is} \\ $$$${equal}\:{to}\:\boldsymbol{{a}}\:. \\ $$ Answered by mrW2 last…
Question Number 94706 by i jagooll last updated on 20/May/20 Answered by john santu last updated on 20/May/20 $${x}\:=\:\mathrm{42}\:{m}^{\mathrm{2}} \\ $$ Commented by i jagooll…
Question Number 29107 by ajfour last updated on 04/Feb/18 Commented by ajfour last updated on 04/Feb/18 $${Find}\:{blue}\:{area}\:{in}\:{terms}\:{of}\:\boldsymbol{{a}},\boldsymbol{\theta},\boldsymbol{\phi}\:. \\ $$ Answered by mrW2 last updated on…
Question Number 94613 by i jagooll last updated on 20/May/20 Commented by Tinku Tara last updated on 20/May/20 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{please}\:\mathrm{resize}\:\mathrm{image}\:\mathrm{appropriately} \\ $$$$\mathrm{before}\:\mathrm{posting}.\:\mathrm{This}\:\mathrm{looks}\:\mathrm{too}\:\mathrm{small} \\ $$$$\mathrm{width}\:\mathrm{and}\:\mathrm{shown}\:\mathrm{as}\:\mathrm{zoomed}\:\mathrm{in}. \\ $$$$\mathrm{Can}\:\mathrm{you}\:\mathrm{please}\:\mathrm{check}\:\mathrm{size}\:\mathrm{of}\:\mathrm{created}…
Question Number 94508 by john santu last updated on 19/May/20 Answered by mr W last updated on 19/May/20 $${OD}={DB}=\frac{\mathrm{6}}{\:\sqrt{\mathrm{2}}}=\mathrm{3}\sqrt{\mathrm{2}} \\ $$$${OE}={ED}={OA}=\mathrm{6} \\ $$$$\mathrm{cos}\:\angle{ODE}=\frac{{OD}}{\mathrm{2}{ED}}=\frac{\sqrt{\mathrm{2}}}{\mathrm{4}} \\ $$$${OC}^{\mathrm{2}}…