Question Number 194967 by Rupesh123 last updated on 21/Jul/23 Answered by a.lgnaoui last updated on 23/Jul/23 $$\mathrm{4}\:\mathrm{cercles}\:\mathrm{disposes}\:\mathrm{comme}\:\mathrm{suit} \\ $$$$\left.\bullet\mathrm{1}\right)\:\:\mathrm{cercle}\:\boldsymbol{\mathrm{R}}\mathrm{ouge}\:\boldsymbol{\mathrm{C}}\mathrm{1}\left(\mathrm{Rayon}\:\boldsymbol{\mathrm{R}}\mathrm{1}\right) \\ $$$$\:\:\:\:\:\:\mathrm{2}\boldsymbol{\mathrm{R}}\mathrm{1}=\boldsymbol{\mathrm{AB}}=\mathrm{12}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{R}}\mathrm{1}=\mathrm{6} \\ $$$$\left.\bullet\mathrm{2}\right)\:\mathrm{cercle}\:\boldsymbol{\mathrm{V}}\mathrm{ert}\:\boldsymbol{\mathrm{C}}\mathrm{2}\left(\boldsymbol{\mathrm{R}}\mathrm{ayon}\:\boldsymbol{\mathrm{R}}\mathrm{2}\right)\:/ \\ $$$$\:\:\:\:\:\mathrm{demi}−\mathrm{cercle}\:\:\boldsymbol{\mathrm{C}}\left(\boldsymbol{\mathrm{A}},\boldsymbol{\mathrm{B}},\boldsymbol{\mathrm{C}}\right)…
Question Number 194796 by sniper237 last updated on 15/Jul/23 $${A}\:\mathrm{1}{m}^{\mathrm{2}} \:{rectangle}\:{which}\:{length}\:{is}\: \\ $$$${less}\:{than}\:\mathrm{1}\:{is}\:\:{a}\:{square}.\:{Why}? \\ $$ Answered by Frix last updated on 15/Jul/23 $$\mathrm{It}'\mathrm{s}\:\mathrm{obviously}\:\mathrm{false} \\ $$$${l}×{w}=\mathrm{1}…
Question Number 194713 by Mingma last updated on 14/Jul/23 Commented by Frix last updated on 15/Jul/23 $$\frac{{A}}{{B}}=\mathrm{2} \\ $$ Commented by Mingma last updated on…
Question Number 194463 by Mingma last updated on 08/Jul/23 Answered by mr W last updated on 08/Jul/23 Commented by Mingma last updated on 08/Jul/23 How did you calculate 1%?…
Question Number 194464 by Mingma last updated on 08/Jul/23 Answered by mr W last updated on 08/Jul/23 Commented by mr W last updated on 08/Jul/23…
Question Number 194384 by Mingma last updated on 05/Jul/23 Commented by Bharathi last updated on 05/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194127 by Rupesh123 last updated on 28/Jun/23 Answered by MM42 last updated on 28/Jun/23 $${AC}={CE}\Rightarrow<{CAE}=\mathrm{45}\Rightarrow{BH}={AH} \\ $$$$\frac{{BH}}{\mathrm{8}}=\frac{{HF}}{\mathrm{6}}\Rightarrow\mathrm{3}{BH}=\mathrm{4}\left(\mathrm{6}−{BH}\right) \\ $$$$\Rightarrow{BH}=\frac{\mathrm{24}}{\mathrm{7}}\Rightarrow{S}=\frac{\mathrm{72}}{\mathrm{7}}\: \\ $$$$ \\ $$…
Question Number 194201 by Shlock last updated on 30/Jun/23 Commented by BaliramKumar last updated on 30/Jun/23 $$\frac{\mathrm{3}\left(\mathrm{3}\sqrt{\mathrm{2}}\:−\:\mathrm{2}\right)}{\mathrm{7}} \\ $$ Commented by Rupesh123 last updated on…
Question Number 194073 by Rupesh123 last updated on 27/Jun/23 Answered by BaliramKumar last updated on 27/Jun/23 $$\mathrm{10}\pi \\ $$ Answered by mr W last updated…
Question Number 194067 by Rupesh123 last updated on 27/Jun/23 Answered by som(math1967) last updated on 27/Jun/23 $$\:{x}^{\mathrm{2}} +\mathrm{10}^{\mathrm{2}} =\mathrm{2}\left(\mathrm{10}−{x}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{x}^{\mathrm{2}} −\mathrm{40}{x}+\mathrm{100}=\mathrm{0} \\ $$$$\:{x}=\mathrm{10}\left(\mathrm{2}−\sqrt{\mathrm{3}}\right) \\…