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Category: Mensuration

Question-91568

Question Number 91568 by jagoll last updated on 01/May/20 Answered by MJS last updated on 01/May/20 $$\mathrm{pipe}\:\mathrm{A}:\:\frac{\mathrm{1}}{\mathrm{20}}\:\mathrm{per}\:\mathrm{hour} \\ $$$$\mathrm{pipe}\:\mathrm{B}:\:\frac{\mathrm{1}}{\mathrm{30}}\:\mathrm{per}\:\mathrm{hour} \\ $$$$\mathrm{pipe}\:\mathrm{C}:\:−\frac{\mathrm{1}}{\mathrm{36}}\:\mathrm{per}\:\mathrm{hour} \\ $$$$\mathrm{8}:\mathrm{00}\:=\mathrm{0} \\ $$$$\mathrm{9}:\mathrm{30}\:=\frac{\mathrm{3}}{\mathrm{2}}…

The-hands-of-a-clock-have-length-3cm-and-5cm-Calculate-the-distance-between-the-tips-of-the-hand-at-4-0-clock-

Question Number 25895 by Mr eaay last updated on 16/Dec/17 $${The}\:{hands}\:{of}\:{a}\:{clock}\:{have}\:{length}\:\mathrm{3}{cm}\: \\ $$$${and}\:\mathrm{5}{cm}.{Calculate}\:{the}\:{distance}\:{between} \\ $$$${the}\:{tips}\:{of}\:{the}\:{hand}\:{at}\:\mathrm{4}\:“\mathrm{0}''\:{clock}. \\ $$ Answered by mrW1 last updated on 16/Dec/17 $${angle}\:{between}\:{the}\:{hands}:…

Question-25871

Question Number 25871 by ajfour last updated on 16/Dec/17 Commented by ajfour last updated on 16/Dec/17 $$\bigtriangleup{ABC}\:{is}\:{equilateral}\:{and}\:{G}\:{its} \\ $$$${centroid}.\:{Parabolas}\:{AGB},\:{BGC}, \\ $$$${and}\:{CGA}\:{each}\:{have}\:{their}\:{vertices} \\ $$$${at}\:{G}.\:{Find}\:{ratio}\:{of}\:{area}\:{in}\:{brown} \\ $$$${to}\:{the}\:{area}\:{of}\:{the}\:\bigtriangleup{ABC}\:.…

Question-156508

Question Number 156508 by cortano last updated on 12/Oct/21 Answered by JDamian last updated on 12/Oct/21 $$\frac{{A}_{{triangle}} }{{A}_{\boldsymbol{{rectangle}}} }\:? \\ $$$${A}_{{triangle}} =\sqrt{{s}\left({s}−{a}\right)\left({s}−{b}\right)\left({s}−{c}\right)} \\ $$$${a}=\mathrm{6}+\mathrm{7}=\mathrm{13} \\…

Question-90904

Question Number 90904 by  M±th+et+s last updated on 26/Apr/20 Commented by  M±th+et+s last updated on 26/Apr/20 $${For}\:\mathrm{0}<{x}<\frac{\pi}{\mathrm{2}}\:,\:{tangents}\:{to}\:{graphs}\:{of} \\ $$$${y}={cos}\left({x}\right)\:{and}\:{y}={tan}\left({x}\right)\:{are}\:{exteded}\:{to} \\ $$$${meet}\:{the}\:{x}−{axis}\:{from}\:{the}\:{point}\:{of}\: \\ $$$${intersection}. \\ $$$${find}\:{a}:{b}\:.…