Question Number 91568 by jagoll last updated on 01/May/20 Answered by MJS last updated on 01/May/20 $$\mathrm{pipe}\:\mathrm{A}:\:\frac{\mathrm{1}}{\mathrm{20}}\:\mathrm{per}\:\mathrm{hour} \\ $$$$\mathrm{pipe}\:\mathrm{B}:\:\frac{\mathrm{1}}{\mathrm{30}}\:\mathrm{per}\:\mathrm{hour} \\ $$$$\mathrm{pipe}\:\mathrm{C}:\:−\frac{\mathrm{1}}{\mathrm{36}}\:\mathrm{per}\:\mathrm{hour} \\ $$$$\mathrm{8}:\mathrm{00}\:=\mathrm{0} \\ $$$$\mathrm{9}:\mathrm{30}\:=\frac{\mathrm{3}}{\mathrm{2}}…
Question Number 25895 by Mr eaay last updated on 16/Dec/17 $${The}\:{hands}\:{of}\:{a}\:{clock}\:{have}\:{length}\:\mathrm{3}{cm}\: \\ $$$${and}\:\mathrm{5}{cm}.{Calculate}\:{the}\:{distance}\:{between} \\ $$$${the}\:{tips}\:{of}\:{the}\:{hand}\:{at}\:\mathrm{4}\:“\mathrm{0}''\:{clock}. \\ $$ Answered by mrW1 last updated on 16/Dec/17 $${angle}\:{between}\:{the}\:{hands}:…
Question Number 25871 by ajfour last updated on 16/Dec/17 Commented by ajfour last updated on 16/Dec/17 $$\bigtriangleup{ABC}\:{is}\:{equilateral}\:{and}\:{G}\:{its} \\ $$$${centroid}.\:{Parabolas}\:{AGB},\:{BGC}, \\ $$$${and}\:{CGA}\:{each}\:{have}\:{their}\:{vertices} \\ $$$${at}\:{G}.\:{Find}\:{ratio}\:{of}\:{area}\:{in}\:{brown} \\ $$$${to}\:{the}\:{area}\:{of}\:{the}\:\bigtriangleup{ABC}\:.…
Question Number 25718 by ajfour last updated on 13/Dec/17 Commented by mrW1 last updated on 13/Dec/17 $${Case}\:\mathrm{1}:\:\theta=\frac{\pi}{\mathrm{2}} \\ $$$${h}_{{i}} =\sqrt{{h}^{\mathrm{2}} +{R}^{\mathrm{2}} } \\ $$$${A}_{{i}} =\frac{\mathrm{2}{R}×{h}_{{i}}…
Question Number 25702 by ajfour last updated on 13/Dec/17 Commented by ajfour last updated on 13/Dec/17 $${solution}\:{to}\:{Q}.\:\mathrm{25700} \\ $$ Answered by ajfour last updated on…
Question Number 156710 by cortano last updated on 14/Oct/21 Commented by mr W last updated on 14/Oct/21 $${question}\:{is}\:{wrong}.\:{no}\:{unique}\:{solution}! \\ $$$${you}\:{can}\:{make}\:{any}\:{length}\:{AD}>\mathrm{3}. \\ $$ Commented by mr…
Question Number 156671 by cortano last updated on 14/Oct/21 Answered by som(math1967) last updated on 14/Oct/21 Commented by som(math1967) last updated on 14/Oct/21 $${cos}\alpha=\frac{\mathrm{10}}{\mathrm{12}}=\frac{\mathrm{5}}{\mathrm{6}} \\…
Question Number 156509 by ARUNG_Brandon_MBU last updated on 12/Oct/21 Commented by mr W last updated on 12/Oct/21 $${both}\:{squares}\:{are}\:{of}\:{equal}\:{size}? \\ $$ Commented by ARUNG_Brandon_MBU last updated…
Question Number 156508 by cortano last updated on 12/Oct/21 Answered by JDamian last updated on 12/Oct/21 $$\frac{{A}_{{triangle}} }{{A}_{\boldsymbol{{rectangle}}} }\:? \\ $$$${A}_{{triangle}} =\sqrt{{s}\left({s}−{a}\right)\left({s}−{b}\right)\left({s}−{c}\right)} \\ $$$${a}=\mathrm{6}+\mathrm{7}=\mathrm{13} \\…
Question Number 90904 by M±th+et+s last updated on 26/Apr/20 Commented by M±th+et+s last updated on 26/Apr/20 $${For}\:\mathrm{0}<{x}<\frac{\pi}{\mathrm{2}}\:,\:{tangents}\:{to}\:{graphs}\:{of} \\ $$$${y}={cos}\left({x}\right)\:{and}\:{y}={tan}\left({x}\right)\:{are}\:{exteded}\:{to} \\ $$$${meet}\:{the}\:{x}−{axis}\:{from}\:{the}\:{point}\:{of}\: \\ $$$${intersection}. \\ $$$${find}\:{a}:{b}\:.…