Category: Mensuration

Question Number 88997 by jagoll last updated on 14/Apr/20 Commented by john santu last updated on 14/Apr/20 $$\mathrm{4}{R}+\mathrm{2}{R}\sqrt{\mathrm{2}}\:=\:\mathrm{8}\sqrt{\mathrm{2}} \\ $$$${R}\left(\mathrm{2}+\sqrt{\mathrm{2}}\right)\:=\:\mathrm{4}\sqrt{\mathrm{2}} \\ $$$${R}\:=\:\frac{\mathrm{4}\sqrt{\mathrm{2}}}{\mathrm{2}+\sqrt{\mathrm{2}}}\:×\:\frac{\mathrm{2}−\sqrt{\mathrm{2}}}{\mathrm{2}−\sqrt{\mathrm{2}}}\: \\ $$$${R}=\:\frac{\mathrm{8}\sqrt{\mathrm{2}}−\mathrm{8}}{\mathrm{4}−\mathrm{2}}\:=\:\mathrm{4}\sqrt{\mathrm{2}}\:−\mathrm{4}\:{dm} \\…

Question Number 154353 by liberty last updated on 17/Sep/21 Commented by mr W last updated on 17/Sep/21 $${r}=\mathrm{2}\sqrt{\mathrm{3}}\:\mathrm{sin}\:\theta \\ $$$$\mathrm{2}{r}\:\mathrm{cos}\:\theta=\mathrm{3} \\ $$$$\mathrm{4}\sqrt{\mathrm{3}}\:\mathrm{sin}\:\theta\:\mathrm{cos}\:\theta=\mathrm{3} \\ $$$$\mathrm{sin}\:\mathrm{2}\theta=\frac{\sqrt{\mathrm{3}}}{\mathrm{2}} \\…

Question Number 154321 by DELETED last updated on 17/Sep/21 Answered by DELETED last updated on 17/Sep/21 $$\bullet\mathrm{pK}_{\mathrm{1}} =\mathrm{6},\mathrm{08}\:\rightarrow−\mathrm{log}\:\mathrm{K}_{\mathrm{1}} =−\mathrm{log}\:\mathrm{10}^{−\mathrm{6},\mathrm{08}} \\ $$$$\rightarrow\mathrm{K}_{\mathrm{1}} =\mathrm{10}^{−\mathrm{6},\mathrm{08}} \\ $$$$\bullet\mathrm{pK}_{\mathrm{2}} =\mathrm{9},\mathrm{28}\:\rightarrow−\mathrm{log}\:\mathrm{K}_{\mathrm{2}}…

Question Number 154172 by iloveisrael last updated on 15/Sep/21 Commented by EDWIN88 last updated on 15/Sep/21 $$\mathrm{90}°+\mathrm{46}°−\mathrm{53}°=\mathrm{90}°−\mathrm{7}°=\mathrm{83}° \\ $$ Terms of Service Privacy Policy Contact:…

Question Number 88301 by byaw last updated on 09/Apr/20 $${A}\:{circle}\:{touches}\:{the}\:{four}\:{sides} \\ $$$${of}\:{quadrilateral}\:{ABCD}.\:\mathrm{Show}/\mathrm{prove} \\ $$$$\mathrm{that}\:\mathrm{A}{B}+{CD}={BC}+{DA}. \\ $$$$\mathrm{Please}\:\mathrm{help}. \\ $$ Commented by mr W last updated on…