Question Number 193908 by Rupesh123 last updated on 22/Jun/23 Answered by Subhi last updated on 22/Jun/23 $${put}\:{each}\:{side}\:=\:{l} \\ $$$${BH}\:=\:{AG}\:=\:\frac{{l}}{\mathrm{2}} \\ $$$${G}\hat {{A}K}={M}\hat {{B}H}=\mathrm{120}−\mathrm{90}=\mathrm{30} \\ $$$${HM}\:=\:{GK}\:=\:\frac{{l}}{\mathrm{4}}\:\left({opposite}\:{to}\:{angle}\:\mathrm{30}\:{in}\:{a}\:{right}\:{triangle}\right)…
Question Number 193754 by Mingma last updated on 19/Jun/23 Answered by talminator2856792 last updated on 19/Jun/23 $$\:\:\mathrm{let}\:{R},\:{r}\:\:\mathrm{represent}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{big}\:\mathrm{semicircle}\:\:\: \\ $$$$\:\:\mathrm{and}\:\mathrm{small}\:\mathrm{semicricle},\:\mathrm{respectively}. \\ $$$$\:\:\mathrm{by}\:\mathrm{pythagorean}\:\mathrm{theorem}: \\ $$$$\:\:{R}\:=\:\sqrt{\left(\frac{{r}\sqrt{\mathrm{3}}}{\mathrm{2}}\right)^{\mathrm{2}} \:+\:\left(\mathrm{3}{r}\right)^{\mathrm{2}} \:}…
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Question Number 193448 by Mingma last updated on 14/Jun/23 Answered by cherokeesay last updated on 14/Jun/23 Commented by Mingma last updated on 14/Jun/23 Perfect �� Terms…
Question Number 193398 by Mingma last updated on 12/Jun/23 Answered by Subhi last updated on 13/Jun/23 $$ \\ $$$${put}\:\left({F}\hat {{C}E}\right)={y}=\left({C}\hat {{E}F}\right) \\ $$$$\left({F}\hat {{E}D}\right)=\left({F}\hat {{D}E}\right)=\left({E}\hat…
Question Number 193387 by Mingma last updated on 12/Jun/23 Commented by Frix last updated on 12/Jun/23 $$\mathrm{The}\:\mathrm{circle}\:\mathrm{is}\:\mathrm{the}\:\mathrm{circumcircle}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}: \\ $$$${a}=\mathrm{6} \\ $$$${b}=\mathrm{6}\sqrt{\mathrm{7}} \\ $$$${c}=\mathrm{18} \\ $$$$\Rightarrow…
Question Number 193199 by mnjuly1970 last updated on 07/Jun/23 $$ \\ $$$$\:\:\:{a}_{\mathrm{1}} \:,\:{a}_{\mathrm{2}} \:,…,{a}_{{n}} \:{are}\:\:{mutually}\:{distinct} \\ $$$$\:\:{and}\:{is}\:{a}\:\:\:\:{am}\:\:{sequence}\:. \\ $$$$\:\:\:{if}\:{a}_{\:\mathrm{1}} \:+{a}_{\:\mathrm{2}} \:+…+{a}_{{n}} \:={A} \\ $$$$\:\:\:{and}\:\: \\…
Question Number 193198 by Mingma last updated on 07/Jun/23 Answered by HeferH last updated on 07/Jun/23 Commented by HeferH last updated on 07/Jun/23 $${x}=\mathrm{60}°−\mathrm{30}°=\mathrm{30}° \\…
Question Number 193149 by Mingma last updated on 04/Jun/23 Answered by ajfour last updated on 05/Jun/23 $$\frac{\sqrt{\mathrm{3}}}{\mathrm{4}}{p}^{\mathrm{2}} ={A} \\ $$$${p}={k}\sqrt{{A}}\:\:\:\:{where}\:\:\:{k}^{\mathrm{2}} =\frac{\mathrm{4}}{\:\sqrt{\mathrm{3}}} \\ $$$${q}={k}\sqrt{{B}} \\ $$$${B}=\mathrm{9}{A}…