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Category: Mensuration

Question-15765

Question Number 15765 by ajfour last updated on 13/Jun/17 Commented by ajfour last updated on 13/Jun/17 $${Q}.\mathrm{15736}\:\:\:\left({alternate}\:{solution}\right) \\ $$$${Area}\:\Delta{APF}\:\:=\frac{\mathrm{1}}{\mathrm{2}}\left({Area}\:\Delta{ABP}\right) \\ $$$$ \\ $$$${Maximum}\:{area}\:{of}\:\Delta{APF} \\ $$$$\:=\frac{\mathrm{1}}{\mathrm{2}}\left({maximum}\:{Area}\:{of}\:\Delta{ABP}\right)…

Question-15667

Question Number 15667 by tawa tawa last updated on 12/Jun/17 Commented by mrW1 last updated on 12/Jun/17 $$\mathrm{diagram}\:\mathrm{is}\:\mathrm{not}\:\mathrm{to}\:\mathrm{understand}.\:\mathrm{please} \\ $$$$\mathrm{give}\:\mathrm{a}\:\mathrm{clear}\:\mathrm{diagram}. \\ $$ Commented by tawa…

Question-146667

Question Number 146667 by puissant last updated on 14/Jul/21 Answered by Olaf_Thorendsen last updated on 14/Jul/21 $$\mathrm{1}. \\ $$$$\mathrm{U}_{\mathrm{C}} \left({t}\right)\:=\:\mathrm{U}_{\mathrm{R}} \left({t}\right)\:=\:\mathrm{RI}_{\mathrm{R}} \left({t}\right)\:=\:\mathrm{R}\left(\mathrm{I}−\mathrm{I}_{\mathrm{C}} \left({t}\right)\right) \\ $$$$\mathrm{Q}_{\mathrm{C}}…

Question-15558

Question Number 15558 by ajfour last updated on 11/Jun/17 Commented by ajfour last updated on 11/Jun/17 $$\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{areas}}\:\:\boldsymbol{\mathrm{I}},\:\boldsymbol{\mathrm{II}},\:\boldsymbol{\mathrm{III}},\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{IV}} \\ $$$$\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{terms}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{b}}. \\ $$$$\boldsymbol{\mathrm{Curve}}\:\boldsymbol{\mathrm{APD}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{semicircle}}.\:\boldsymbol{\mathrm{ABCD}} \\ $$$$\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{rectangle}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{side}}\:\boldsymbol{\mathrm{a}}>\boldsymbol{\mathrm{b}}/\mathrm{2}\:. \\ $$…