Question Number 12743 by tawa last updated on 30/Apr/17 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{eqilateral}\:\mathrm{triangle}\:\mathrm{whose}\:\mathrm{inscribed}\:\mathrm{circle}\:\mathrm{has}\:\mathrm{a}\:\mathrm{radius}\:\mathrm{2} \\ $$ Answered by mrW1 last updated on 30/Apr/17 $${OC}=\mathrm{2} \\ $$$${OB}=\mathrm{4}={DO} \\ $$$${CB}=\mathrm{2}\sqrt{\mathrm{3}} \\…
Question Number 12329 by tawa last updated on 19/Apr/17 Commented by mrW1 last updated on 19/Apr/17 $${if}\:{the}\:{rope}\:{is}\:{only}\:\mathrm{15}{m}\:{long},\:{the} \\ $$$${distance}\:{between}\:{the}\:{towers}\:{must} \\ $$$${be}\:{zero}! \\ $$ Commented by…
Question Number 143332 by bramlexs22 last updated on 13/Jun/21 Commented by soumyasaha last updated on 13/Jun/21 $$\:\mathrm{x}\:=\:\sqrt{\frac{\mathrm{3}+\sqrt{\mathrm{5}}}{\mathrm{2}}} \\ $$ Commented by mr W last updated…
Question Number 77272 by jagoll last updated on 05/Jan/20 $$\mathrm{given}\:\mathrm{T}.\mathrm{ABCD}\:\mathrm{is}\:\mathrm{pyramid}\: \\ $$$$\mathrm{with}\:\mathrm{AB}\:=\:\mathrm{BC}\:=\:\mathrm{8}\:\mathrm{and}\:\mathrm{AT}\:=\:\mathrm{6} \\ $$$$\:.\:\mathrm{P}\:\mathrm{is}\:\mathrm{midpoint}\:\mathrm{BC},\:\mathrm{Q}\:\mathrm{is}\:\mathrm{midpoint}\:\mathrm{AT}. \\ $$$$\mathrm{If}\:\alpha\:\mathrm{is}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{between}\:\mathrm{TP}\:\mathrm{and} \\ $$$$\mathrm{PQ}\:\mathrm{then}\:\mathrm{cos}\:\alpha\:\mathrm{is}\:… \\ $$ Commented by john santu last…
Question Number 76964 by peter frank last updated on 01/Jan/20 $${solve}\:{Differential}\:\:{equation} \\ $$$${x}^{\mathrm{2}} \frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }−\mathrm{4}{x}\frac{{dy}}{{dx}}+\mathrm{3}{y}={x}^{\mathrm{3}} +\mathrm{2}{x}+\mathrm{5} \\ $$ Answered by mind is power last…
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Question Number 76663 by aliesam last updated on 29/Dec/19 Answered by benjo 1/2 santuyy last updated on 29/Dec/19 $$\mathrm{2}^{\mathrm{3}{n}\:} \:? \\ $$ Answered by mind…
Question Number 10846 by Saham last updated on 27/Feb/17 $$\mathrm{Two}\:\mathrm{parallel}\:\mathrm{chords}\:\mathrm{of}\:\mathrm{length}\:\mathrm{24}\:\mathrm{cm}\:\mathrm{and}\:\mathrm{10}\:\mathrm{cm}\:\mathrm{which}\:\mathrm{lies}\:\mathrm{on}\:\mathrm{opposite} \\ $$$$\mathrm{sides}\:\mathrm{of}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{are}\:\mathrm{17}\:\mathrm{cm}\:\mathrm{apart}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle} \\ $$$$\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{whole}\:\mathrm{number}. \\ $$ Answered by mrW1 last updated on 27/Feb/17 $${r}^{\mathrm{2}} =\left(\frac{{l}}{\mathrm{2}}\right)^{\mathrm{2}}…
Question Number 75955 by benjo last updated on 21/Dec/19 $${help}\:{me}\: \\ $$$$ \\ $$ Answered by benjo last updated on 21/Dec/19 Answered by mr W…
Question Number 141198 by ajfour last updated on 16/May/21 Commented by ajfour last updated on 17/May/21 $${Material}\:{volume}\:{of}\:{sphere} \\ $$$${minus}\:{ellipsoid}\:{is}\:\frac{\mathrm{4}}{\mathrm{3}}\pi{c}\:. \\ $$$${Find}\:{radius}\:{of}\:{sphere}\:{R}. \\ $$$${The}\:{ellipsoid}'{s}\:{radii}\:{are} \\ $$$$\:\:\:{r}_{\mathrm{1}}…