Category: Mensuration

Question Number 9764 by tawakalitu last updated on 01/Jan/17 Answered by sandy_suhendra last updated on 01/Jan/17 Commented by sandy_suhendra last updated on 01/Jan/17 $$\mathrm{OM}=\mathrm{OK}=\mathrm{5}\:\mathrm{cm} \\…

Question Number 140597 by bramlexs22 last updated on 10/May/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{circle}\:\mathrm{which} \\ $$$$\mathrm{passes}\:\mathrm{through}\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{2},\mathrm{0}\right)\:\mathrm{and} \\ $$$$\mathrm{whose}\:\mathrm{center}\:\mathrm{is}\:\mathrm{the}\:\mathrm{limit}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{point}\:\mathrm{of}\:\mathrm{intersection}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{lines}\:\mathrm{3x}+\mathrm{5y}=\mathrm{1}\:\mathrm{and}\:\left(\mathrm{2}+\mathrm{c}\right)\mathrm{x}+\mathrm{5c}^{\mathrm{2}} \mathrm{y}=\mathrm{1} \\ $$$$\mathrm{as}\:\mathrm{c}\rightarrow\mathrm{1}\:. \\ $$ Answered by…

Question Number 74994 by aliesam last updated on 05/Dec/19 Commented by mind is power last updated on 05/Dec/19 Commented by mind is power last updated…

Question Number 74904 by necxxx last updated on 03/Dec/19 Commented by mr W last updated on 03/Dec/19 $${no}\:{unique}\:{solution} \\ $$ Terms of Service Privacy Policy…

Question Number 9298 by tawakalitu last updated on 29/Nov/16 Answered by mrW last updated on 29/Nov/16 $$\mathrm{radius}\:\mathrm{r}=\left(\mathrm{7}+\mathrm{3}\right)/\mathrm{2}=\mathrm{5}\:\mathrm{cm} \\ $$$$\mathrm{height}\:\mathrm{of}\:\mathrm{segment}\:\mathrm{h}=\mathrm{3}\:\mathrm{cm} \\ $$$$\mathrm{area}\:\mathrm{of}\:\mathrm{segment}\:=\:\mathrm{r}^{\mathrm{2}} \mathrm{cos}\:^{−\mathrm{1}} \left(\frac{\mathrm{r}−\mathrm{h}}{\mathrm{r}}\right)−\left(\mathrm{r}−\mathrm{h}\right)\sqrt{\mathrm{2rh}−\mathrm{h}^{\mathrm{2}} } \\…