Question Number 72603 by aliesam last updated on 30/Oct/19 Answered by mr W last updated on 30/Oct/19 Commented by aliesam last updated on 30/Oct/19 $${thank}\:{you}\:{sir}…
Question Number 72434 by aliesam last updated on 28/Oct/19 Answered by mind is power last updated on 28/Oct/19 $$\frac{\mathrm{c}}{\mathrm{sin}\left(\mathrm{x}\right)}=\frac{\mathrm{d}}{\mathrm{sin}\left(\mathrm{y}\right)}=\frac{\mathrm{BD}}{\mathrm{sin}\left(\mathrm{40}\right)} \\ $$$$\mathrm{BD}^{\mathrm{2}} =\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} −\mathrm{2abcos}\left(\mathrm{40}\right) \\…
Question Number 6893 by Tawakalitu. last updated on 01/Aug/16 Commented by Rasheed Soomro last updated on 02/Aug/16 $$\bullet{Surface}\:{area}\:{of}\:{sphere}=\mathrm{4}\pi{r}^{\mathrm{2}} \\ $$$$\:{Radius}\:{of}\:{the}\:\:{sphere}\:=\frac{\mathrm{12}}{\mathrm{2}}=\mathrm{6}\:{cm} \\ $$$${Surface}\:{area}\:{of}\:{sphere}=\mathrm{4}\pi\left(\mathrm{6}\right)^{\mathrm{2}} =\mathrm{144}\pi……….\left({i}\right) \\ $$$$…
Question Number 6880 by Tawakalitu. last updated on 01/Aug/16 $${A}\:{cone}\:{of}\:{height}\:\mathrm{10}\:{cm}\:{and}\:{base}\:{radius}\:\mathrm{3}\:{cm}\:{is}\:{held}\:{vertex}\: \\ $$$${down}\:{and}\:{is}\:{filled}\:{with}\:{sand}\:.\:{A}\:{hole}\:{in}\:{the}\:{bottom}\:{of}\:{the}\:{cone} \\ $$$${allows}\:{the}\:{sand}\:{to}\:{escape}\:{at}\:{a}\:{steady}\:{rate}\:{of}\:\mathrm{0}.\mathrm{5}\:{cm}^{\mathrm{3}} /{s}.\:{find}\:{the} \\ $$$${rate}\:{that}\:{the}\:{depth}\:{is}\:{decreasing}\:{when}\:{the}\:{depth}\:{is}\:\mathrm{2}\:{cm}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 72414 by aliesam last updated on 28/Oct/19 Commented by aliesam last updated on 28/Oct/19 $${a},{b}\:{and}\:{d}\:{are}\:{centres}\:{of}\:{three}\:{circles}\: \\ $$$${find}\: \\ $$$$\frac{{AC}}{{AB}} \\ $$ Answered by…
Question Number 6810 by Tawakalitu. last updated on 28/Jul/16 $${Up}\:{to}\:{which}\:{prime}\:{number}\:{should}\:\:\:\mathrm{9}\:\:\:{divide}\:\:\:\mathrm{9631}\:\:\:{to}\:{ensure}\:{that} \\ $$$${this}\:{number}\:{is}\:{a}\:{prime}\:{number}\:{or}\:{a}\:{composite}\:{number}\:? \\ $$ Commented by Rasheed Soomro last updated on 29/Jul/16 $$\mathrm{97} \\ $$$${The}\:{largest}\:{prime}\:{number}\:{not}\:{greater}\:{than}\:\sqrt{\mathrm{9631}}…
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Question Number 6430 by sanusihammed last updated on 27/Jun/16 $${An}\:{oil}\:{can}\:{is}\:{to}\:{be}\:{made}\:{in}\:{form}\:{of}\:{a}\:{right}\:{circular}\:{cylinder}\:{that}\:{be} \\ $$$${inscribed}\:{in}\:{a}\:{sphere}\:{of}\:{radius}\:{R}.\:{obtain}\:{the}\:{maximum}\: \\ $$$${volume}\:{of}\:{the}\:{can}. \\ $$ Commented by sanusihammed last updated on 27/Jun/16 $${Thanks}\:{so}\:{much}\:{sir}.\: \\…
Question Number 6334 by sanusihammed last updated on 24/Jun/16 Commented by nburiburu last updated on 24/Jun/16 $${basically}\:{you}\:\:{need}\:{to}\:{find}\:{first}\:{the}\:{common}\:{area}. \\ $$$${To}\:{do}\:{it},\:{let}\:{be}\:{M}\:{and}\:{N}\:{the}\:{intersection}\:{of}\:{both}\:{circles}\:{and}\:{O}\:{and}\:{P}\:\:{the}\:{centres}\:{of}\:{circle}\:{with}\:{radius}\:{b}\:{and}\:{a}\:,\:{respectively}. \\ $$$${the}\:{area}\:{couldbefound}\:{doing} \\ $$$${Area}.{circ}.{sector}\:\left({NOM}\right)\:+\:{Area}.{circ}.{sector}\:\left({MPO}\right)+{Area}.{circ}.{sector}\left({OPN}\right)\:−\:{Area}\bigtriangleup{MPO}\:−\:{Area}\bigtriangleup{OPN} \\ $$$${and}\:{for}\:{this}\:{is}\:{necessary}\:{to}\:{know}\:{two}\:\:{central}\:{angles}…
Question Number 6234 by sanusihammed last updated on 19/Jun/16 Terms of Service Privacy Policy Contact: info@tinkutara.com