Question Number 194085 by 073 last updated on 27/Jun/23 $$\mathrm{f}\left(\mathrm{x}\right)−\mathrm{f}\left(\mathrm{x}−\mathrm{1}\right)=\mathrm{x}+\mathrm{1} \\ $$$$\mathrm{f}'\left(\mathrm{6}\right)=? \\ $$$$\mathrm{solution}?? \\ $$ Answered by qaz last updated on 27/Jun/23 $${f}\left({x}\right)={ax}^{\mathrm{2}} +{bx}+{c}…
Question Number 194034 by MrGHK last updated on 26/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194017 by MrGHK last updated on 26/Jun/23 Answered by witcher3 last updated on 26/Jun/23 $$\forall\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\in\left[\mathrm{0},\mathrm{1}\right]^{\mathrm{3}} ,\left(\mathrm{xyz}\right)^{\mathrm{4}} \leqslant\mathrm{1} \\ $$$$\frac{\mathrm{x}^{\mathrm{4}} \mathrm{y}^{\mathrm{6}} \mathrm{z}^{\mathrm{8}} }{\mathrm{1}−\mathrm{x}^{\mathrm{4}} \mathrm{y}^{\mathrm{4}}…
Question Number 193984 by TUN last updated on 25/Jun/23 $${Know}\:{f}\left({x}^{−\mathrm{1}} \right)={f}^{\:−\mathrm{1}} \left({x}\right) \\ $$$${Find}\:{f}\left({x}\right)¿ \\ $$ Commented by aleks041103 last updated on 25/Jun/23 $${does}\:{f}^{\:−\mathrm{1}} \left({x}\right)\:{mean}\:\frac{\mathrm{1}}{{f}\left({x}\right)}\:{or}\:{inverse}\:{of}\:{f}?…
Question Number 193987 by Biteshwar last updated on 25/Jun/23 Answered by MATHEMATICSAM last updated on 25/Jun/23 $$\boldsymbol{\mathrm{Very}}\:\boldsymbol{\mathrm{huge}}\:\boldsymbol{\mathrm{amount}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{questions}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 193971 by mnjuly1970 last updated on 24/Jun/23 $$ \\ $$$$\:\:\:\:\:\:{y}=\:\lfloor\:{x}^{\:\mathrm{2}} \:\rfloor\:+\:\lfloor\:{x}\:\rfloor\:\: \\ $$$$\:\: \\ $$$$\:\:\:\:\:\:\:\Rightarrow\:\:{R}_{{y}} \:=?\:\:\:\:\:\:\:{Range} \\ $$ Answered by MM42 last updated…
Question Number 193949 by sonukgindia last updated on 23/Jun/23 Answered by aleks041103 last updated on 23/Jun/23 $$\mathrm{8}^{{x}} −\mathrm{8}{x}={f}\left({x}\right) \\ $$$${f}\:'\left({x}\right)={ln}\left(\mathrm{8}\right)\mathrm{8}^{{x}} −\mathrm{8};\:{f}\:'\left({x}_{\mathrm{0}} \right)=\mathrm{0} \\ $$$${f}\:''\left({x}\right)={ln}\left(\mathrm{8}\right)^{\mathrm{2}} \mathrm{8}^{{x}}…
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Question Number 193938 by yaslm last updated on 23/Jun/23 Answered by BaliramKumar last updated on 23/Jun/23 $$\mathrm{15}° \\ $$ Commented by yaslm last updated on…
Question Number 193866 by liuxinnan last updated on 21/Jun/23 $${prove} \\ $$$$\:\:\underset{{i}=\mathrm{1}} {\overset{+\infty} {\sum}}\frac{\mathrm{1}}{{n}^{{i}} }=\frac{\mathrm{1}}{{n}−\mathrm{1}}\:\:\:\:\:\:{n}\in\mathbb{N}^{\ast} \\ $$$${and}\:{if}\:{n}>\mathrm{0}\wedge\:{n}\in\mathbb{R} \\ $$$${is}\:{it}\:{right}? \\ $$ Answered by AST last…