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Let-f-R-R-g-R-R-be-continuous-functions-Then-pi-2-pi-2-f-x-f-x-g-x-g-x-dx-

Question Number 64328 by Chi Mes Try last updated on 16/Jul/19 $$\mathrm{Let}\:\:{f}\::\:{R}\rightarrow{R},\:{g}\::\:{R}\rightarrow{R}\:\:\mathrm{be}\:\mathrm{continuous} \\ $$$$\mathrm{functions}.\:\mathrm{Then} \\ $$$$\underset{−\pi/\mathrm{2}} {\overset{\pi/\mathrm{2}} {\int}}\:\left[\:{f}\left({x}\right)+{f}\left(−{x}\right)\:\right]\:\left[\:{g}\left({x}\right)\left({g}\left(−{x}\right)\:\right]\:{dx}\:=\right. \\ $$ Terms of Service Privacy Policy…

If-0-pi-1-a-b-cos-x-dx-a-gt-0-is-equal-to-pi-a-2-b-2-then-0-pi-1-a-b-cos-x-2-dx-

Question Number 64267 by Chi Mes Try last updated on 16/Jul/19 $$\mathrm{If}\:\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\frac{\mathrm{1}}{{a}+{b}\:\mathrm{cos}\:{x}}\:{dx},\:{a}>\mathrm{0}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\frac{\pi}{\:\sqrt{{a}^{\mathrm{2}} −{b}^{\mathrm{2}} }}\:, \\ $$$$\mathrm{then}\:\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\:\frac{\mathrm{1}}{\left({a}+{b}\:\mathrm{cos}\:{x}\right)^{\mathrm{2}} }\:{dx}\:= \\ $$ Commented by…

Solution-of-the-equation-2-x-dx-x-x-2-1-pi-12-is-x-

Question Number 64225 by mmkkmm000m last updated on 16/Jul/19 $$\mathrm{Solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\underset{\:\sqrt{\mathrm{2}}} {\overset{{x}} {\int}}\:\:\:\frac{{dx}}{{x}\:\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}\:=\:\frac{\pi}{\mathrm{12}}\:\:\mathrm{is}\:\:{x}\:=\:\_\_\_\_\_. \\ $$ Answered by ajfour last updated on 16/Jul/19 $$\mathrm{cos}^{−\mathrm{1}}…