Question Number 196406 by qaz last updated on 24/Aug/23 $$\underset{{n},{m}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}+{m}} {nm}}{\left({n}+{m}\right)^{\mathrm{2}} }=? \\ $$ Answered by witcher3 last updated on 26/Aug/23 $$=−\underset{\mathrm{n},\mathrm{m}} {\sum}\int_{\mathrm{0}}…
Question Number 196429 by SANOGO last updated on 24/Aug/23 Answered by Frix last updated on 24/Aug/23 $$\mathrm{ln}\:\left(\underset{{k}=\mathrm{1}} {\overset{\infty} {\prod}}\:\left(\sqrt[{{n}}]{\mathrm{e}}\left(\frac{\mathrm{2}}{\pi}\right)^{\frac{\mathrm{1}}{{k}^{\mathrm{2}} }} \right)\right)\:=\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\:\left(\frac{\mathrm{ln}\:\mathrm{2}\:−\mathrm{ln}\:\pi}{{k}^{\mathrm{2}} }+\frac{\mathrm{1}}{{n}}\right)\:= \\…
Question Number 196398 by tri26112004 last updated on 24/Aug/23 $${y}={f}\left({x}\right) \\ $$$${Give}:\:{xy}−{y}'={x}^{\mathrm{2}} \\ $$$${Find}\:{y}=¿ \\ $$ Commented by mr W last updated on 24/Aug/23 $${d}.{e}.\:{of}\:{type}\:{y}'+{p}\left({x}\right){y}={q}\left({x}\right)…
Question Number 196423 by aaaspots last updated on 24/Aug/23 $$ \\ $$Consider a complex 4×4 full-rank matrix H. The QR decomposition and singular value decomposition…
Question Number 196388 by sonukgindia last updated on 24/Aug/23 Answered by AST last updated on 24/Aug/23 $$\phi\left(\mathrm{20}\right)=\phi\left(\mathrm{4}\right)\phi\left(\mathrm{5}\right)=\left(\mathrm{2}^{\mathrm{2}} −\mathrm{2}\right)\left(\mathrm{5}−\mathrm{1}\right)=\mathrm{8} \\ $$ Answered by BaliramKumar last updated…
Question Number 196419 by Rodier97 last updated on 25/Aug/23 $$\:\:{calcul}\:\:{lim}_{{x}\rightarrow+\infty} \:\left(\mathrm{1}+\frac{\mathrm{1}}{{f}\left({x}\right)}\right)^{{f}\left({x}\right)} \\ $$ Commented by MM42 last updated on 24/Aug/23 $${f}\left(\infty\right)\:? \\ $$ Answered by…
Question Number 196347 by bbbbbbbb last updated on 23/Aug/23 $$\left(\mathrm{1}\overset{\left(\mathrm{2}\overset{\mathrm{21}} {\mathrm{0}}\right)} {\mathrm{9}}\right)\:\boldsymbol{\mathrm{factorial}}\:\boldsymbol{\mathrm{plz}}\:\boldsymbol{\mathrm{hepl}}\:\boldsymbol{\mathrm{me}}\:\boldsymbol{\mathrm{so}}\:\boldsymbol{\mathrm{soon}} \\ $$ Commented by mr W last updated on 23/Aug/23 $${so}\:{soon}\:{as}\:{the}\:{light}? \\ $$$${in}\:{each}\:{of}\:{your}\:{questions}\:{you}\:{request}…
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