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lim-n-1-2-n-2-1-2-2-n-2-2-3-2-n-2-3-n-2-n-2-n-n-3-

Question Number 212595 by MrGaster last updated on 18/Oct/24 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{1}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{2}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{2}}+\frac{\mathrm{3}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{3}}+\ldots+\frac{{n}^{\mathrm{2}} }{{n}^{\mathrm{2}} +{n}}−\frac{{n}}{\mathrm{3}}\right)=? \\ $$ Answered by Berbere last…

Question-212584

Question Number 212584 by MrGaster last updated on 18/Oct/24 Commented by mr W last updated on 18/Oct/24 $${it}\:{seems}\:{that}\:{you}\:{are}\:{using}\:{machine} \\ $$$${translation}\:{for}\:{your}\:{posts}.\:{can}\:{you} \\ $$$${please}\:{recheck}\:{the}\:{translation} \\ $$$${and}\:{fix}\:{the}\:{mistakes}\:{in}\:{them}\:{before} \\…

llim-n-i-1-n-1-i-n-3-1-

Question Number 212545 by MrGaster last updated on 17/Oct/24 $$\underset{{n}\rightarrow\infty} {\mathrm{llim}}\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\sqrt{\mathrm{1}+\frac{{i}}{{n}^{\mathrm{3}} }}−\mathrm{1}\right)=? \\ $$ Answered by lepuissantcedricjunior last updated on 17/Oct/24 $$\underset{\boldsymbol{{n}}\rightarrow+\infty} {\mathrm{lim}}\underset{\boldsymbol{{i}}=\mathrm{1}}…

Have-you-ever-wondered-why-the-sum-ofd-igits-in-decimal-system-is-a-multiple-of-3a-nd-the-sum-of-digits-in-decimal-system-isa-multiple-of-9-Prove-the-abovei-propertes-

Question Number 212579 by MrGaster last updated on 18/Oct/24 $$\mathrm{Have}\:\mathrm{you}\:\mathrm{ever}\:\mathrm{wondered}\:\mathrm{why}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{ofd} \\ $$$$\mathrm{igits}\:\mathrm{in}\:\mathrm{decimal}\:\mathrm{system}\:\mathrm{is}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{3a} \\ $$$$\mathrm{nd}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{digits}\:\mathrm{in}\:\mathrm{decimal}\:\mathrm{system}\: \\ $$$$\mathrm{isa}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{9}\:\mathrm{Prove}\:\mathrm{the}\:\mathrm{abovei} \\ $$$$\mathrm{propertes}. \\ $$ Terms of Service Privacy Policy…

certificate-x-2n-1-Can-always-be-x-1-be-divisible-

Question Number 212513 by MrGaster last updated on 16/Oct/24 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{certificate}: \\ $$$$\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}{n}} −\mathrm{1} \\ $$$$\mathrm{Can}\:\mathrm{always}\:\mathrm{be}\:{x}+\mathrm{1}\:\mathrm{be}\:\mathrm{divisible}\:\:\:\:\:\:\:\:\: \\ $$ Answered by A5T last updated on 16/Oct/24 $${x}\equiv−\mathrm{1}\left({mod}\:{x}+\mathrm{1}\right)\Rightarrow{x}^{\mathrm{2}{n}}…