Question Number 53501 by 0955083339 last updated on 22/Jan/19 $$\mathrm{If}\:\left({x}−\mathrm{5}\right)\:\mathrm{is}\:\mathrm{a}\:\mathrm{factor}\:\mathrm{of}\:\:\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{px}−\mathrm{2}{p}=\mathrm{0}, \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\:{p}\:\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 53386 by gunawan last updated on 21/Jan/19 $$\underset{\:\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\:\:\frac{{dx}}{{e}^{{x}} +\:{e}^{−{x}} }\:=\:\mathrm{tan}^{−\mathrm{1}} {e}−\:\frac{\pi}{\mathrm{4}} \\ $$ Commented by Tinkutara last updated on 21/Jan/19 $$=\int\frac{{e}^{{x}}…
Question Number 53385 by gunawan last updated on 21/Jan/19 $$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{integral}\:\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\frac{{x}\:{dx}}{\mathrm{1}+\mathrm{cos}\:\alpha\:\mathrm{sin}\:\alpha}\:, \\ $$$$\mathrm{0}<\:\alpha<\pi\:\:\:\mathrm{is} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 21/Jan/19 $$\frac{\mathrm{1}}{\mathrm{1}+{sin}\alpha{cos}\alpha}×\mid\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\mid_{\mathrm{0}}…
Question Number 53383 by gunawan last updated on 21/Jan/19 $$\mathrm{If}\:\int\frac{\mathrm{1}}{\left(\mathrm{sin}\:{x}+\mathrm{4}\right)\left(\mathrm{sin}\:{x}−\mathrm{1}\right)}{dx} \\ $$$$\:\:\:\:\:\:\:\:\:=\:{A}\frac{\mathrm{1}}{\mathrm{tan}\:\frac{{x}}{\mathrm{2}}−\mathrm{1}}+{B}\:\mathrm{tan}^{−\mathrm{1}} \left({f}\left({x}\right)\right)+{C},\:\mathrm{then} \\ $$ Commented by maxmathsup by imad last updated on 21/Jan/19 $${let}\:{A}\:=\int\:\:\:\:\frac{{dx}}{\left({sinx}+\mathrm{4}\right)\left({sinx}−\mathrm{1}\right)}\:\Rightarrow{A}\:=_{{tan}\left(\frac{{x}}{\mathrm{2}}\right)={t}}…
Question Number 53384 by gunawan last updated on 21/Jan/19 $$\:\underset{\:\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\left(\mathrm{1}+{e}^{−{x}^{\mathrm{2}} } \right)\:{dx}\:= \\ $$ Commented by Abdo msup. last updated on 21/Jan/19 $${we}\:{have}\:{e}^{{u}}…
Question Number 53381 by gunawan last updated on 21/Jan/19 $$\int\:\frac{\mathrm{1}}{\left[\left({x}−\mathrm{1}\right)^{\mathrm{3}} \left({x}+\mathrm{2}\right)^{\mathrm{5}} \right]^{\mathrm{1}/\mathrm{4}} }\:{dx}\:= \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 21/Jan/19 $$\int\frac{{dx}}{\left({x}−\mathrm{1}\right)^{\frac{\mathrm{3}}{\mathrm{4}}} \left({x}+\mathrm{2}\right)^{\frac{\mathrm{5}}{\mathrm{4}}} }…
Question Number 53382 by gunawan last updated on 21/Jan/19 $$\int\:\mathrm{cos}^{\mathrm{3}} {x}\:{e}^{\mathrm{log}\:\left(\mathrm{sin}\:{x}\right)} {dx}\:= \\ $$ Answered by math1967 last updated on 21/Jan/19 $$\int\left(\mathrm{1}−{sin}^{\mathrm{2}} {x}\right){cosxe}^{{ln}\left({sinx}\right)} {dx} \\…
Question Number 53359 by gunawan last updated on 20/Jan/19 $$\int\:\:\frac{{x}^{\mathrm{3}} −\mathrm{1}}{{x}^{\mathrm{3}} +{x}}\:{dx}\:= \\ $$ Answered by Smail last updated on 21/Jan/19 $${I}=\int\frac{{x}^{\mathrm{3}} +{x}−{x}−\mathrm{1}}{{x}^{\mathrm{3}} +{x}}{dx}=\int\left(\mathrm{1}−\frac{{x}+\mathrm{1}}{{x}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}\right){dx}…
Question Number 53358 by gunawan last updated on 20/Jan/19 $$\int\:\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{sin}^{\mathrm{3}} {x}\:\mathrm{cos}\:{x}}}\:{dx}\:= \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 21/Jan/19 $$\int\frac{{dx}}{\:\sqrt{{sin}^{\mathrm{3}} {xcosx}}} \\ $$$$\int\frac{{dx}}{\:\sqrt{\frac{{sin}^{\mathrm{3}} {x}}{{cos}^{\mathrm{3}}…
Question Number 53357 by gunawan last updated on 20/Jan/19 $$\int\:\:\frac{\left({x}^{\mathrm{4}} −{x}\right)^{\mathrm{1}/\mathrm{4}} }{{x}^{\mathrm{5}} }\:{dx}\:= \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 21/Jan/19 $$\int\frac{\left\{{x}^{\mathrm{4}} \left(\mathrm{1}−\frac{\mathrm{1}}{{x}^{\mathrm{3}} }\right)\right\}^{\frac{\mathrm{1}}{\mathrm{4}}}…