Question Number 113808 by deepraj123 last updated on 15/Sep/20 $$\mathrm{In}\:\mathrm{a}\:\bigtriangleup{ABC}\:,\:\angle{B}=\frac{\pi}{\mathrm{3}}\:\mathrm{and}\:\angle{C}=\frac{\pi}{\mathrm{4}}.\:\mathrm{Let} \\ $$$${D}\:\mathrm{divide}\:{BC}\:\mathrm{internally}\:\mathrm{in}\:\mathrm{the}\:\mathrm{ratio} \\ $$$$\mathrm{1}\::\:\mathrm{3}.\:\mathrm{Then}\:\frac{\mathrm{sin}\:\angle{BAD}}{\mathrm{sin}\:\angle{CAD}}\:\mathrm{equals} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 113807 by deepraj123 last updated on 15/Sep/20 $$\mathrm{In}\:\mathrm{any}\:\bigtriangleup{ABC},\:\mathrm{if}\:\mathrm{the}\:\mathrm{angles}\:\mathrm{are}\:\mathrm{in}\: \\ $$$$\mathrm{the}\:\mathrm{ratio}\:\mathrm{1}\::\:\mathrm{2}\::\:\mathrm{3},\:\mathrm{then}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\mathrm{corresponding}\:\mathrm{sides}\:\mathrm{is} \\ $$ Answered by bemath last updated on 15/Sep/20 $$\angle{A}\:=\:{k}\:,\angle{B}=\mathrm{2}{k}\:,\angle{C}=\mathrm{3}{k} \\…
Question Number 48105 by lhfgfgjokf last updated on 19/Nov/18 $$\underset{−\mathrm{1}} {\overset{\mathrm{1}} {\int}}\:\left(\sqrt{\mathrm{1}+{x}+{x}^{\mathrm{2}} }−\:\sqrt{\mathrm{1}−{x}−{x}^{\mathrm{2}} }\:\right){dx}\:= \\ $$ Commented by maxmathsup by imad last updated on 19/Nov/18…
Question Number 113557 by Aina Samuel Temidayo last updated on 14/Sep/20 $$\mathrm{If}\:\mathrm{the}\:\mathrm{numerically}\:\mathrm{smaller}\:\mathrm{root}\:\mathrm{of}\: \\ $$$${x}^{\mathrm{2}} +{mx}=\mathrm{2}\:\mathrm{is}\:\mathrm{more}\:\mathrm{than}\:\mathrm{the}\:\mathrm{other}\:\mathrm{one}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{m}. \\ $$ Answered by mr W last updated…
Question Number 47874 by regineregencia last updated on 16/Nov/18 $$\mathrm{An}\:\mathrm{elevator}\:\mathrm{starts}\:\mathrm{with}\:{m}\:\mathrm{passengers} \\ $$$$\mathrm{and}\:\mathrm{stops}\:\mathrm{at}\:{n}\:\mathrm{floors}\:\left({m}\leqslant{n}\right).\:\mathrm{The}\: \\ $$$$\mathrm{probability}\:\mathrm{that}\:\mathrm{no}\:\mathrm{passengers}\:\mathrm{alight} \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{same}\:\mathrm{floor}\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 47727 by Mawitea Cck last updated on 14/Nov/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:{a}\:\mathrm{for} \\ $$$$\:\:\:\:\:{a}\::\:\mathrm{4}\::\::\:\mathrm{5}\::\:\mathrm{10} \\ $$ Answered by ajfour last updated on 14/Nov/18 $$\Rightarrow\:\frac{{a}}{\mathrm{4}}\:=\:\frac{\mathrm{5}}{\mathrm{10}}\:\:\:\:\:\Rightarrow\:\:\frac{{a}/\mathrm{4}}{\mathrm{1}}=\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\:\:\:\frac{{a}}{\mathrm{4}}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\Rightarrow\:\:{a}=\frac{\mathrm{4}}{\mathrm{2}}\:=\:\mathrm{2}\:.…
Question Number 47593 by shivshant0409 last updated on 12/Nov/18 $$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{statements}\: \\ $$$$\mathrm{are}/\mathrm{is}\:\mathrm{true}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 47581 by EagleEye1 last updated on 11/Nov/18 $$\mathrm{The}\:\mathrm{root}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\frac{\mathrm{2}}{{x}−\mathrm{1}}\:+\:\frac{\mathrm{1}}{{x}+\mathrm{2}}\:+\:\frac{\mathrm{3}{x}\left({x}+\mathrm{1}\right)}{\left({x}−\mathrm{1}\right)\left({x}+\mathrm{2}\right)}\:=\:\mathrm{0}\:\: \\ $$$$\mathrm{among}\:\mathrm{the}\:\mathrm{following}\:\mathrm{is} \\ $$ Commented by maxmathsup by imad last updated on 12/Nov/18…
Question Number 47481 by limite last updated on 10/Nov/18 $$\mathrm{Three}\:\mathrm{six}−\mathrm{faced}\:\mathrm{dice}\:\mathrm{are}\:\mathrm{thrown} \\ $$$$\mathrm{together}.\:\mathrm{The}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sum} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{numbers}\:\mathrm{appearing}\:\mathrm{on}\:\mathrm{the}\:\mathrm{dice} \\ $$$$\mathrm{is}\:\:{k}\:\left(\mathrm{3}\leqslant\:{k}\:\leqslant\:\mathrm{8}\right)\:\mathrm{is} \\ $$ Answered by ajfour last updated on 10/Nov/18…
Question Number 47301 by myear last updated on 08/Nov/18 $$\mathrm{If}\:\mathrm{the}\:\mathrm{equation}\:{x}^{\mathrm{2}} +{px}+{q}\:=\mathrm{0}\:\mathrm{has}\:\mathrm{roots} \\ $$$${a}\:\mathrm{and}\:{b}\:\mathrm{where}\:{p},\:{q}\:\mathrm{are}\:\mathrm{non}−\mathrm{zero}\: \\ $$$$\mathrm{constants}.\:\mathrm{Then} \\ $$ Answered by Kunal12588 last updated on 08/Nov/18 $$\left({x}−{a}\right)\left({x}−{b}\right)={x}^{\mathrm{2}}…