Question Number 64331 by Chi Mes Try last updated on 16/Jul/19 $$\underset{−\mathrm{1}} {\overset{\mathrm{1}} {\int}}\:\mathrm{sin}^{\mathrm{11}} {x}\:{dx}\:= \\ $$ Commented by mr W last updated on 16/Jul/19…
Question Number 64332 by Chi Mes Try last updated on 16/Jul/19 $$\underset{\pi/\mathrm{6}} {\overset{\pi/\mathrm{3}} {\int}}\:\:\frac{\mathrm{1}}{\mathrm{sin}\:\mathrm{2}{x}}\:{dx}\:= \\ $$ Commented by mathmax by abdo last updated on 16/Jul/19…
Question Number 64329 by Chi Mes Try last updated on 16/Jul/19 $$\mathrm{If}\:{I}=\underset{\:\mathrm{3}} {\overset{\mathrm{4}} {\int}}\:\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{log}\:{x}}}\:{dx}\:,\:\mathrm{then}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64330 by Chi Mes Try last updated on 16/Jul/19 $$\mathrm{If}\:\underset{\:\mathrm{0}} {\overset{\infty} {\int}}\:{e}^{−{x}} \mathrm{sin}\:^{{n}} {x}\:{dx}\:=\:\frac{\mathrm{24}}{\mathrm{125}},\:\mathrm{then}\:{n}= \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 64328 by Chi Mes Try last updated on 16/Jul/19 $$\mathrm{Let}\:\:{f}\::\:{R}\rightarrow{R},\:{g}\::\:{R}\rightarrow{R}\:\:\mathrm{be}\:\mathrm{continuous} \\ $$$$\mathrm{functions}.\:\mathrm{Then} \\ $$$$\underset{−\pi/\mathrm{2}} {\overset{\pi/\mathrm{2}} {\int}}\:\left[\:{f}\left({x}\right)+{f}\left(−{x}\right)\:\right]\:\left[\:{g}\left({x}\right)\left({g}\left(−{x}\right)\:\right]\:{dx}\:=\right. \\ $$ Terms of Service Privacy Policy…
Question Number 64327 by Chi Mes Try last updated on 16/Jul/19 $$\frac{{d}}{{dx}}\:\:\left(\:\underset{{f}\left({x}\right)} {\overset{{g}\left({x}\right)} {\int}}\:\phi\left({t}\right)\:{dt}\:\right)\:= \\ $$ Commented by mathmax by abdo last updated on 16/Jul/19…
Question Number 64269 by Chi Mes Try last updated on 16/Jul/19 $$\underset{−\pi} {\overset{\pi} {\int}}\:\left[\mathrm{cos}\:{px}−\mathrm{sin}\:{qx}\right]^{\mathrm{2}} {dx},\:\mathrm{where}\:{p},\:{q}\:\mathrm{are}\: \\ $$$$\mathrm{integers}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$ Answered by Tanmay chaudhury last updated…
Question Number 64268 by Chi Mes Try last updated on 16/Jul/19 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{1}^{\mathrm{99}} +\mathrm{2}^{\mathrm{99}} +…+\:{n}^{\mathrm{99}} }{{n}^{\mathrm{100}} }\:= \\ $$ Commented by Prithwish sen last updated…
Question Number 64266 by Chi Mes Try last updated on 16/Jul/19 $$\:\underset{\mathrm{1}/{e}} {\overset{{e}} {\int}}\:\mid\:\mathrm{log}\:{x}\:\mid\:{dx}\:= \\ $$ Answered by ajfour last updated on 16/Jul/19 $${I}=−\int_{\mathrm{1}/{e}} ^{\:\:\mathrm{1}}…
Question Number 64267 by Chi Mes Try last updated on 16/Jul/19 $$\mathrm{If}\:\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\frac{\mathrm{1}}{{a}+{b}\:\mathrm{cos}\:{x}}\:{dx},\:{a}>\mathrm{0}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\frac{\pi}{\:\sqrt{{a}^{\mathrm{2}} −{b}^{\mathrm{2}} }}\:, \\ $$$$\mathrm{then}\:\underset{\:\mathrm{0}} {\overset{\pi} {\int}}\:\:\:\frac{\mathrm{1}}{\left({a}+{b}\:\mathrm{cos}\:{x}\right)^{\mathrm{2}} }\:{dx}\:= \\ $$ Commented by…