Question Number 88681 by NicolasXd last updated on 12/Apr/20 $$\mathrm{If}\:\:{f}\left({x}\right)\:\mathrm{is}\:\mathrm{a}\:\mathrm{periodic}\:\mathrm{function},\:\mathrm{with} \\ $$$$\mathrm{period}\:{T},\:\mathrm{then} \\ $$ Commented by jagoll last updated on 12/Apr/20 $${then}\:\underset{\mathrm{0}} {\overset{{nT}} {\int}}\:{f}\left({x}+{mT}\right)\:{dx}\:=\:{n}\:\underset{\mathrm{0}} {\overset{{T}}…
Question Number 22871 by keshavnimgade85@gmail.com last updated on 23/Oct/17 $$\mathrm{If}\:\:{f}\left({n}\right)=\frac{\mathrm{1}}{{n}}\left[\left({n}+\mathrm{1}\right)\left({n}+\mathrm{2}\right)\left({n}+\mathrm{3}\right)…\left({n}+{n}\right)\right]^{\mathrm{1}/{n}} , \\ $$$$\mathrm{then}\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}{f}\left({n}\right)\:= \\ $$ Answered by ajfour last updated on 23/Oct/17 $${f}\left({n}\right)=\left[\left(\mathrm{1}+\frac{\mathrm{1}}{{n}}\right)\left(\mathrm{1}+\frac{\mathrm{2}}{{n}}\right)…\left(\mathrm{1}+\frac{{n}}{{n}}\right)\right]^{\mathrm{1}/{n}} \\…
Question Number 22745 by Sahib singh last updated on 22/Oct/17 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solutions}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{equation}\:\:\mathrm{log}_{\mathrm{101}} \mathrm{log}_{\mathrm{7}} \left(\sqrt{{x}+\mathrm{7}}+\sqrt{{x}}\right)=\mathrm{0}\:\mathrm{is} \\ $$ Answered by mrW1 last updated on 22/Oct/17 $$\mathrm{log}_{\mathrm{101}}…
Question Number 88210 by bagjamath last updated on 09/Apr/20 $$\mathrm{If}\:{f}\left({x}\right)=\begin{cases}{\mathrm{1}−{x},\:\:\:\:\:\:\:\:\:\mathrm{0}\leqslant{x}\leqslant\mathrm{1}}\\{\mathrm{0},\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}\leqslant{x}\leqslant\mathrm{2}\:\:\:\:}\\{\left(\mathrm{2}−{x}\right)^{\mathrm{2}} ,\:\:\:\mathrm{2}\leqslant{x}\leqslant\mathrm{3}}\end{cases}\:\mathrm{and}\: \\ $$$$\phi\left({x}\right)=\underset{\:\mathrm{0}} {\overset{\mathrm{x}} {\int}}\:{f}\left({t}\right)\:{dt}.\:\mathrm{Then}\:\mathrm{for}\:\mathrm{any}\:{x}\:\in\:\left[\mathrm{2},\:\mathrm{3}\right],\: \\ $$$$\phi\left({x}\right)\:= \\ $$ Answered by MJS last updated on…
Question Number 88198 by topman2020 last updated on 08/Apr/20 $$\mathrm{Factorize}\:\:−{r}^{\mathrm{2}} +{p}^{\mathrm{2}} +{q}^{\mathrm{2}} −\mathrm{2}{pq}\:. \\ $$ Answered by TANMAY PANACEA. last updated on 08/Apr/20 $$\left({p}−{q}\right)^{\mathrm{2}} −{r}^{\mathrm{2}}…
Question Number 22470 by paddu1234 last updated on 18/Oct/17 $$\mathrm{If}\:{f}\left({x}\right)= \\ $$$$\begin{vmatrix}{\mathrm{1}}&{{x}}&{{x}+\mathrm{1}}\\{\mathrm{2}{x}}&{{x}\left({x}−\mathrm{1}\right)}&{\left({x}+\mathrm{1}\right){x}}\\{\mathrm{3}{x}\left({x}−\mathrm{1}\right)}&{\mathrm{2}\left({x}−\mathrm{1}\right)\left({x}−\mathrm{2}\right)}&{\left({x}+\mathrm{1}\right)\:{x}\left({x}−\mathrm{1}\right)}\end{vmatrix}, \\ $$$$\mathrm{then}\:{f}\left(\mathrm{100}\right)\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 87275 by unknown last updated on 03/Apr/20 $$\mathrm{If}\:\:\mathrm{the}\:\mathrm{equations}\:{x}^{\mathrm{2}} +{ax}+{b}=\mathrm{0}\:\mathrm{and}\: \\ $$$${x}^{\mathrm{2}} +{bx}+{a}=\mathrm{0}\:\mathrm{have}\:\mathrm{a}\:\mathrm{common}\:\mathrm{root}, \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{numerical}\:\mathrm{value}\:\mathrm{of}\:{a}+{b}\:\mathrm{is} \\ $$ Answered by Rio Michael last updated on…
Question Number 87274 by unknown last updated on 03/Apr/20 $$\mathrm{If}\:\:\mathrm{the}\:\mathrm{equations}\:{x}^{\mathrm{2}} +{ax}+{b}=\mathrm{0}\:\mathrm{and}\: \\ $$$${x}^{\mathrm{2}} +{bx}+{a}=\mathrm{0}\:\mathrm{have}\:\mathrm{a}\:\mathrm{common}\:\mathrm{root}, \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{numerical}\:\mathrm{value}\:\mathrm{of}\:{a}+{b}\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 87272 by unknown last updated on 03/Apr/20 $$\mathrm{If}\:\:\mathrm{the}\:\mathrm{equations}\:{x}^{\mathrm{2}} +{ax}+{b}=\mathrm{0}\:\mathrm{and}\: \\ $$$${x}^{\mathrm{2}} +{bx}+{a}=\mathrm{0}\:\mathrm{have}\:\mathrm{a}\:\mathrm{common}\:\mathrm{root}, \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{numerical}\:\mathrm{value}\:\mathrm{of}\:{a}+{b}\:\mathrm{is} \\ $$ Answered by $@ty@m123 last updated on 03/Apr/20…
Question Number 87273 by unknown last updated on 03/Apr/20 $$\mathrm{If}\:\:\mathrm{the}\:\mathrm{equations}\:{x}^{\mathrm{2}} +{ax}+{b}=\mathrm{0}\:\mathrm{and}\: \\ $$$${x}^{\mathrm{2}} +{bx}+{a}=\mathrm{0}\:\mathrm{have}\:\mathrm{a}\:\mathrm{common}\:\mathrm{root}, \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{numerical}\:\mathrm{value}\:\mathrm{of}\:{a}+{b}\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com