Question Number 193175 by Humble last updated on 06/Jun/23 $${please}\:{solve}\:{for}\:{x}\:{if} \\ $$$$\mathrm{2}{x}^{\mathrm{2}} =\mathrm{2}^{{x}} \\ $$ Answered by Frix last updated on 06/Jun/23 $$\mathrm{Obviously}\:{x}=\mathrm{1} \\ $$…
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Question Number 193170 by aba last updated on 05/Jun/23 $$\mathrm{solve}\::\:\mathrm{7}^{\mathrm{x}} =−\mathrm{2} \\ $$ Answered by Frix last updated on 06/Jun/23 $$−\mathrm{2}=\mathrm{2e}^{\mathrm{i}\pi\left(\mathrm{2}{n}+\mathrm{1}\right)} \forall{n}\in\mathbb{Z} \\ $$$$\mathrm{7}^{{x}} =\mathrm{2e}^{\mathrm{i}\pi\left(\mathrm{2}{n}+\mathrm{1}\right)}…
Question Number 131037 by mohammad17 last updated on 31/Jan/21 Commented by mathmax by abdo last updated on 31/Jan/21 $$\left.\mathrm{48}\right)\mathrm{use}\:\mathrm{the}\:\mathrm{same}\:\mathrm{method}… \\ $$ Answered by mathmax by…
Question Number 131027 by Algoritm last updated on 31/Jan/21 Answered by mathmax by abdo last updated on 31/Jan/21 $$\mathrm{cos}^{\mathrm{2m}} \mathrm{x}\:=\left(\frac{\mathrm{e}^{\mathrm{ix}} +\mathrm{e}^{−\mathrm{ix}} }{\mathrm{2}}\right)^{\mathrm{2m}} \:=\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2m}} }\sum_{\mathrm{k}=\mathrm{0}} ^{\mathrm{2m}}…
Question Number 131021 by mohammad17 last updated on 31/Jan/21 $${solve} \\ $$$$ \\ $$$$\left(\mathrm{1}\right):\left(\mathrm{1}+{i}\right)^{{i}} \\ $$$$ \\ $$$$\left(\mathrm{2}\right):\:{log}\left(\mathrm{1}+{i}\right)^{\pi{i}} \\ $$ Answered by Dwaipayan Shikari last…
Question Number 131012 by mohammad17 last updated on 31/Jan/21 Commented by mohammad17 last updated on 31/Jan/21 $${help}\:{me}\:{sir} \\ $$ Answered by mr W last updated…
Question Number 131007 by Study last updated on 31/Jan/21 $$\frac{{d}}{{dx}}\left(\infty\right)=?\:\:\:\:\:{or}\:\:\:\left(\infty\right)'=? \\ $$ Answered by Boucatchou last updated on 31/Jan/21 $$\infty\:{is}\:{unknown},\:{so}\:\:{they}\:\:{can}'{t}\:\:{do}\:\:{such}\:\:{operations}.. \\ $$ Answered by MJS_new…
Question Number 131006 by Study last updated on 31/Jan/21 $${if}\:{a}_{\mathrm{1}} =\frac{\mathrm{4}{n}+\mathrm{3}}{\mathrm{2}{n}−\mathrm{1}}\:\:\:\:\:\:,\:\:\:{a}_{\mathrm{10}} =\frac{\mathrm{6}{n}+\mathrm{5}}{\mathrm{2}{n}−\mathrm{1}}\:\:\:\:;\:\:\:{a}_{\mathrm{30}} =? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 131004 by Algoritm last updated on 31/Jan/21 Commented by Algoritm last updated on 31/Jan/21 $$\mathrm{prove}\:\mathrm{that} \\ $$ Terms of Service Privacy Policy Contact:…