Question Number 81874 by zainal tanjung last updated on 16/Feb/20 $$\mathrm{If}\:{A}=\begin{bmatrix}{\:\:\mathrm{1}}&{−\mathrm{5}}&{\:\:\:\mathrm{7}}\\{\:\:\mathrm{0}}&{\:\:\:\:\mathrm{7}}&{\:\:\:\mathrm{9}}\\{\mathrm{11}}&{\:\:\:\:\mathrm{8}}&{\:\:\:\mathrm{9}}\end{bmatrix}\:\mathrm{then}\:\mathrm{trace}\:\mathrm{of}\: \\ $$$$\mathrm{matrix}\:{A}\:\mathrm{is} \\ $$ Commented by jagoll last updated on 16/Feb/20 $${trc}\:\left({A}\right)=\mathrm{17} \\ $$…
Question Number 81873 by zainal tanjung last updated on 16/Feb/20 $$\begin{vmatrix}{\mathrm{sin}^{\mathrm{2}} {x}}&{\mathrm{cos}^{\mathrm{2}} {x}}&{\mathrm{1}}\\{\mathrm{cos}^{\mathrm{2}} {x}}&{\mathrm{sin}^{\mathrm{2}} {x}}&{\mathrm{1}}\\{−\mathrm{10}}&{\:\:\mathrm{12}}&{\mathrm{2}}\end{vmatrix}= \\ $$ Commented by john santu last updated on 16/Feb/20…
Question Number 81872 by zainal tanjung last updated on 16/Feb/20 $$\mathrm{If}\:\mathrm{every}\:\mathrm{element}\:\mathrm{of}\:\mathrm{a}\:\mathrm{third}\:\mathrm{order} \\ $$$$\mathrm{determinant}\:\mathrm{of}\:\mathrm{value}\:\bigtriangleup\:\mathrm{is}\:\mathrm{multiplied}\:\mathrm{by} \\ $$$$\mathrm{5},\:\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{new}\:\mathrm{determinant}\:\mathrm{is} \\ $$ Answered by MJS last updated on 16/Feb/20 $$\mathrm{5}^{\mathrm{3}}…
Question Number 81731 by zainal tanjung last updated on 15/Feb/20 $$\mathrm{If}\:\:{a},\:{b},\:{c}\:\mathrm{are}\:\mathrm{in}\:\mathrm{AP};\:\:{p},\:{q},\:{r}\:\mathrm{are}\:\mathrm{in}\:\mathrm{HP}\: \\ $$$$\mathrm{and}\:\:{ap},\:{bq},\:{cr}\:\:\mathrm{are}\:\mathrm{in}\:\mathrm{GP},\:\mathrm{then}\:\frac{{p}}{{r}}+\frac{{r}}{{p}} \\ $$$$\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$ Commented by jagoll last updated on 15/Feb/20 $$\left({i}\right)\:{a},{b},{c}\:{in}\:{AP}\:\Rightarrow\:\mathrm{2}{b}\:=\:{a}+{c}…
Question Number 81724 by zainal tanjung last updated on 14/Feb/20 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{in}\:\mathrm{which}\:\mathrm{an} \\ $$$$\mathrm{examiner}\:\mathrm{can}\:\mathrm{assign}\:\mathrm{30}\:\mathrm{marks}\:\mathrm{to}\:\mathrm{8} \\ $$$$\mathrm{questions},\:\mathrm{giving}\:\mathrm{not}\:\mathrm{less}\:\mathrm{than}\:\mathrm{2}\:\mathrm{marks} \\ $$$$\mathrm{to}\:\mathrm{any}\:\mathrm{question}\:\mathrm{is} \\ $$ Commented by Tony Lin last updated…
Question Number 81725 by zainal tanjung last updated on 14/Feb/20 $$\mathrm{If}\:\:\mathrm{7}\:\mathrm{points}\:\mathrm{out}\:\mathrm{of}\:\mathrm{12}\:\mathrm{are}\:\mathrm{in}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{straight}\:\mathrm{line},\:\mathrm{then}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of} \\ $$$$\mathrm{triangles}\:\mathrm{formed}\:\mathrm{is} \\ $$ Commented by Tony Lin last updated on 14/Feb/20…
Question Number 81672 by zainal tanjung last updated on 14/Feb/20 $$\mathrm{If}\:{x}\:\in\:{R},\:\mathrm{the}\:\mathrm{least}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{expression}\:\frac{{x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{5}}{{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{1}}\:\mathrm{is} \\ $$ Commented by Kunal12588 last updated on 14/Feb/20 $${y}=\frac{\left({x}−\mathrm{5}\right)\left({x}−\mathrm{1}\right)}{\left({x}+\mathrm{1}\right)^{\mathrm{2}}…
Question Number 81664 by zainal tanjung last updated on 14/Feb/20 $$\underset{−\pi/\mathrm{4}} {\overset{\pi/\mathrm{4}} {\int}}\:{e}^{−{x}} \:\mathrm{sin}\:{x}\:{dx}\:= \\ $$ Commented by zainal tanjung last updated on 14/Feb/20 $$…
Question Number 81663 by zainal tanjung last updated on 14/Feb/20 $$\:\underset{\:\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\:{x}\:\left(\mathrm{1}−{x}\right)^{{n}} \:{dx}\:= \\ $$ Commented by Tony Lin last updated on 14/Feb/20 $${B}\left({p},\:{q}\right)=\int_{\mathrm{0}}…
Question Number 81648 by Zainal Arifin last updated on 14/Feb/20 $$\mathrm{A}\:\mathrm{team}\:\mathrm{of}\:\mathrm{8}\:\mathrm{couples},\:\left(\mathrm{husband}\:\mathrm{and}\:\mathrm{wife}\right) \\ $$$$\mathrm{attend}\:\mathrm{a}\:\mathrm{lucky}\:\mathrm{draw}\:\mathrm{in}\:\mathrm{which}\:\mathrm{4}\:\mathrm{persons} \\ $$$$\mathrm{picked}\:\mathrm{up}\:\mathrm{for}\:\mathrm{a}\:\mathrm{prize}.\:\mathrm{Then}\:\mathrm{the}\:\mathrm{probability} \\ $$$$\mathrm{that}\:\mathrm{there}\:\mathrm{is}\:\mathrm{at}\:\mathrm{least}\:\mathrm{one}\:\mathrm{couple}\:\mathrm{is} \\ $$ Commented by mr W last updated…