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The-value-of-1-tan-2-15-1-tan-2-15-is-

Question Number 68352 by mhmd last updated on 09/Sep/19 $$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:\:\frac{\mathrm{1}−\mathrm{tan}^{\mathrm{2}} \mathrm{15}°}{\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \mathrm{15}°}\:\:\mathrm{is} \\ $$ Answered by $@ty@m123 last updated on 09/Sep/19 $$\frac{\mathrm{1}−\mathrm{tan}\:^{\mathrm{2}} \theta}{\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} \theta}=\mathrm{cos}\:\mathrm{2}\theta \\…

If-2x-2-2p-13-x-2-0-is-exactly-divisible-by-x-3-then-the-value-of-p-is-

Question Number 68351 by mhmd last updated on 09/Sep/19 $$\mathrm{If}\:\mathrm{2}{x}^{\mathrm{2}} +\left(\mathrm{2}{p}−\mathrm{13}\right){x}+\mathrm{2}=\mathrm{0}\:\mathrm{is}\:\mathrm{exactly}\:\mathrm{divisible} \\ $$$$\mathrm{by}\:{x}−\mathrm{3},\:\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{p}\:\mathrm{is} \\ $$ Answered by $@ty@m123 last updated on 09/Sep/19 $${f}\left({x}\right)=\mathrm{2}{x}^{\mathrm{2}} +\left(\mathrm{2}{p}−\mathrm{13}\right){x}+\mathrm{2} \\…

If-a-lt-1-and-b-lt-1-then-the-sum-of-the-series-1-1-a-b-1-a-a-2-b-2-1-a-a-2-a-3-b-3-is-

Question Number 68151 by mhmd last updated on 06/Sep/19 $$\mathrm{If}\:\mid{a}\mid<\:\mathrm{1}\:\mathrm{and}\:\mid{b}\mid<\:\mathrm{1},\:\mathrm{then}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{series} \\ $$$$\mathrm{1}+\left(\mathrm{1}+{a}\right){b}+\left(\mathrm{1}+{a}+{a}^{\mathrm{2}} \right){b}^{\mathrm{2}} +\left(\mathrm{1}+{a}+{a}^{\mathrm{2}} +{a}^{\mathrm{3}} \right){b}^{\mathrm{3}} +… \\ $$$$\mathrm{is} \\ $$ Commented by ~ À…

If-determinant-x-n-x-n-2-x-n-3-y-n-y-n-2-y-n-3-z-n-z-n-2-z-n-3-x-y-y-z-z-x-1-x-1-y-1-z-then-n-equals-

Question Number 67836 by gunawan last updated on 01/Sep/19 $$\mathrm{If}\:\begin{vmatrix}{{x}^{{n}} }&{{x}^{{n}+\mathrm{2}} }&{{x}^{{n}+\mathrm{3}} }\\{{y}^{{n}} }&{{y}^{{n}+\mathrm{2}} }&{{y}^{{n}+\mathrm{3}} }\\{{z}^{{n}} }&{{z}^{{n}+\mathrm{2}} }&{{z}^{{n}+\mathrm{3}} }\end{vmatrix} \\ $$$$=\:\left({x}−{y}\right)\left({y}−{z}\right)\left({z}−{x}\right)\left(\frac{\mathrm{1}}{{x}}\:+\:\frac{\mathrm{1}}{{y}}\:+\:\frac{\mathrm{1}}{{z}}\right), \\ $$$$\mathrm{then}\:{n}\:\mathrm{equals} \\ $$…

Question-193391

Question Number 193391 by DAVONG last updated on 12/Jun/23 Answered by aba last updated on 12/Jun/23 $$\left(\mathrm{1}\right)\:\mathrm{log}_{\mathrm{a}} \left(\mathrm{6}\right)−\mathrm{log}_{\mathrm{a}} \left(\mathrm{x}\right)=\frac{\mathrm{1}}{\mathrm{2}}\:\Rightarrow\:\mathrm{log}_{\mathrm{a}} \left(\frac{\mathrm{6}}{\mathrm{x}}\right)=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\:\mathrm{ln}\left(\frac{\mathrm{6}}{\mathrm{x}}\right)=\mathrm{ln}\left(\sqrt{\mathrm{a}}\right)\:\Rightarrow\:\mathrm{x}=\frac{\mathrm{6}}{\:\sqrt{\mathrm{a}}}\:\checkmark \\ $$ Commented…

Question-193345

Question Number 193345 by yaslm last updated on 11/Jun/23 Answered by aleks041103 last updated on 13/Jun/23 $${The}\:{trajectry}\:{of}\:{the}\:{water}\:{is}\:{a}\:{freefall}\:{parabolla} \\ $$$$\Rightarrow{H}=\frac{\mathrm{1}}{\mathrm{2}}{gt}^{\mathrm{2}} \Rightarrow{t}=\sqrt{\frac{\mathrm{2}{H}}{{g}}} \\ $$$${D}={vt}={v}\sqrt{\frac{\mathrm{2}{H}}{{g}}} \\ $$$$\Rightarrow{v}=\sqrt{\frac{{gD}^{\mathrm{2}} }{\mathrm{2}{H}}}…