Question Number 130197 by mohammad17 last updated on 23/Jan/21 $${find}\:{the}\:{outliers}\:{for}\:{the}\:{following}\:{function} \\ $$$$ \\ $$$$\left(\mathrm{1}\right){f}\left({z}\right)=\frac{{e}^{{z}} }{{z}^{\mathrm{2}} }\:\:\:\:\:\:,\:\:\:\left(\mathrm{2}\right){f}\left({z}\right)=\frac{{sinz}}{{z}} \\ $$$$ \\ $$$$\left(\mathrm{3}\right){f}\left({z}\right)=\frac{\mathrm{1}−{cosz}}{{sinz}^{\mathrm{2}} }\:\:\:\:,\left(\mathrm{4}\right){f}\left({z}\right)={ln}\mid{z}\mid \\ $$$$ \\ $$$$…
Question Number 130188 by SEKRET last updated on 23/Jan/21 Answered by Lordose last updated on 23/Jan/21 $$ \\ $$$$\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{x}^{\frac{\mathrm{5}}{\mathrm{4}}−\mathrm{1}} }{\left(\mathrm{1}+\mathrm{x}\right)^{\frac{\mathrm{5}}{\mathrm{4}}+\frac{\mathrm{3}}{\mathrm{4}}} }\mathrm{dx}\:=\:\boldsymbol{\beta}\left(\frac{\mathrm{5}}{\mathrm{4}},\frac{\mathrm{3}}{\mathrm{4}}\right)\:=\:\frac{\boldsymbol{\Gamma}\left(\frac{\mathrm{5}}{\mathrm{4}}\right)\boldsymbol{\Gamma}\left(\frac{\mathrm{3}}{\mathrm{4}}\right)}{\boldsymbol{\Gamma}\left(\mathrm{2}\right)}\:=\:\frac{\boldsymbol{\pi}}{\mathrm{2}\sqrt{\mathrm{2}}}\:\:\:\:\:\:\:\:\:\:\:\: \\ $$…
Question Number 130186 by mohammad17 last updated on 23/Jan/21 $${if}\:{Z}\:{is}\:{any}\:{boint}\:{on}\:{the}\:{circle}\:\mid{Z}−\mathrm{1}\mid=\mathrm{1} \\ $$$$ \\ $$$${prove}\:{that}\:{arg}\left({Z}−\mathrm{1}\right)=\mathrm{2}{arg}\left({Z}\right)=\frac{\mathrm{2}}{\mathrm{3}}{arg}\left({Z}^{\mathrm{2}} −{Z}\right) \\ $$ Commented by mohammad17 last updated on 23/Jan/21 $$?????…
Question Number 130173 by mohammad17 last updated on 23/Jan/21 Commented by mohammad17 last updated on 23/Jan/21 $$????? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 130168 by Adel last updated on 23/Jan/21 $$\mathrm{log}\underset{\mathrm{X}} {\mathrm{2}}\centerdot\mathrm{log}\:\underset{\mathrm{2X}} {\mathrm{2}}=\mathrm{log}\:\underset{\mathrm{4X}} {\mathrm{2}}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{X}=? \\ $$ Commented by liberty last updated on 23/Jan/21 $$\mathrm{do}\:\mathrm{you}\:\mathrm{meant}\:\mathrm{log}\:_{{x}} \left(\mathrm{2}\right).\mathrm{log}\:_{\mathrm{2}{x}} \left(\mathrm{2}\right)\:=\:\mathrm{log}\:_{\mathrm{4}{x}}…
Question Number 64601 by LPM last updated on 19/Jul/19 $$\:\:\:\:\:\mathrm{10}^{{x}} ={x}^{\mathrm{1000}} \:\Rightarrow\:{x}\:=? \\ $$ Answered by mr W last updated on 19/Jul/19 $${x}^{\mathrm{1000}} =\mathrm{10}^{{x}} \\…
Question Number 130129 by Khalmohmmad last updated on 22/Jan/21 Commented by mr W last updated on 22/Jan/21 $${impossible}! \\ $$ Terms of Service Privacy Policy…
Question Number 130127 by mohammad17 last updated on 22/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130102 by mohammad17 last updated on 22/Jan/21 $${if}\:{U}\left({x},{y}\right)=\mathrm{2}{x}−{x}^{\mathrm{3}} +\mathrm{3}{xy}^{\mathrm{2}} \:{construct}\:{a}\:{complex}\: \\ $$$${analytical}\:{function},\:{the}\:{expression} \\ $$$${of}\:{which}\:{is}\:{the}\:{true}\:{part}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130104 by mohammad17 last updated on 22/Jan/21 $${find}\:{the}\:{key}\:{value}\:\left[{Arg}\left({z}\right)\right]{for}\:\left(\mathrm{2}+{i}\right)^{\mathrm{1}−{i}} \\ $$ Answered by Olaf last updated on 22/Jan/21 $${z}\:=\:\left(\mathrm{2}+{i}\right)^{\mathrm{1}−{i}} \\ $$$$\mathrm{Z}\:=\:\mathrm{ln}{z}\:=\:\left(\mathrm{1}−{i}\right)\mathrm{ln}\left(\mathrm{2}+{i}\right) \\ $$$$\mathrm{Z}\:=\:\left(\mathrm{1}−{i}\right)\mathrm{ln}\left(\sqrt{\mathrm{5}}{e}^{{i}\mathrm{arctan}\frac{\mathrm{1}}{\mathrm{2}}} \right)…