Question Number 65446 by LPM last updated on 30/Jul/19 $$\:\:\:\:\mathrm{10}^{\mathrm{x}} \:=\:\mathrm{x}^{\mathrm{1000}} \:\Rightarrow\:\mathrm{x}=? \\ $$ Commented by MJS last updated on 30/Jul/19 $${a}^{{x}} ={x}^{{b}} \\ $$$${x}\mathrm{ln}\:{a}\:={b}\mathrm{ln}\:{x}…
Question Number 130970 by naka3546 last updated on 31/Jan/21 $$\mathrm{2023}^{\mathrm{2021}^{\mathrm{2019}} } \:\:\mathrm{mod}\:\:\mathrm{1000}\:\:=\:\:{x} \\ $$$$\sqrt{\frac{{x}}{\mathrm{9}}\:+\:\sqrt[{\mathrm{8}}]{{x}\:+\mathrm{89}}}\:\:=\:\:{y} \\ $$$${x}\:+\:{y}\:\:=\:\:\:? \\ $$ Commented by AlagaIbile last updated on 31/Jan/21…
Question Number 130946 by help last updated on 30/Jan/21 Answered by mathmax by abdo last updated on 30/Jan/21 $$\mathrm{u}_{\mathrm{n}} =\frac{\sqrt{\mathrm{n}^{\mathrm{4}} −\mathrm{2n}^{\mathrm{3}} }−\mathrm{n}^{\mathrm{2}} }{\mathrm{n}+\mathrm{2}}\:\Rightarrow\mathrm{u}_{\mathrm{n}} =\frac{\sqrt{\mathrm{n}^{\mathrm{4}} \left(\mathrm{1}−\frac{\mathrm{2}}{\mathrm{n}}\right)}−\mathrm{n}^{\mathrm{2}}…
Question Number 130943 by help last updated on 30/Jan/21 Commented by Dwaipayan Shikari last updated on 30/Jan/21 $$\mathrm{0} \\ $$ Commented by help last updated…
Question Number 130933 by mohammad17 last updated on 30/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 130927 by greg_ed last updated on 30/Jan/21 $$\mathrm{hi},\:\mathrm{mr}\:\mathrm{tinku}\:\mathrm{tara}\:! \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{app},\:\mathrm{i}\:\mathrm{can}'\mathrm{t}\:\mathrm{see}\:\mathrm{the}\:\mathrm{button}\:\mathrm{to}\:\mathrm{cut}\: \\ $$$$\mathrm{some}\:\mathrm{sentences}.\: \\ $$$$\mathrm{please},\:\mathrm{add}\:\mathrm{it}\:! \\ $$ Commented by Tinku Tara last updated on…
Question Number 130924 by Tabassuma last updated on 30/Jan/21 Commented by mr W last updated on 30/Jan/21 $$=\mathrm{6} \\ $$$${see}\:{Q}\mathrm{74970} \\ $$ Terms of Service…
Question Number 130921 by pticantor last updated on 30/Jan/21 $$\boldsymbol{{let}}\:\boldsymbol{{q}}\in\mathbb{R}/\:\mid\boldsymbol{{q}}\mid<\mathrm{1} \\ $$$$\: \\ $$$$\boldsymbol{{show}}\:\boldsymbol{{that}} \\ $$$$\underset{\boldsymbol{{k}}=\mathrm{0}} {\overset{+\infty} {\sum}}\boldsymbol{{k}}^{\mathrm{2}} \boldsymbol{{q}}^{\boldsymbol{{k}}} =\frac{\boldsymbol{{q}}^{\mathrm{2}} +\boldsymbol{{q}}}{\left(\mathrm{1}−\boldsymbol{{q}}\right)^{\mathrm{3}} } \\ $$ Answered…
Question Number 130897 by mohammad17 last updated on 30/Jan/21 Commented by malwan last updated on 30/Jan/21 من اين انت اخي محمد؟ Commented by mohammad17 last updated on 30/Jan/21 $$\:{Im}\:{from}\:{iraq}…
Question Number 65359 by 237174/13/1 last updated on 29/Jul/19 $$\phi\phi \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com