Question Number 129527 by MathSh last updated on 16/Jan/21 $${f}\left({x}\right)=\begin{cases}{\mathrm{5}−{x}\:;\:{x}\geqslant\mathrm{2}}\\{{x}^{\mathrm{2}} +\mathrm{3}\:;\:{x}<\mathrm{2}}\end{cases}\:\:\:{if}, \\ $$$${find}:\:{f}\left(\mathrm{2}\right)+{f}\left(\mathrm{0}\right)=? \\ $$ Commented by bramlexs22 last updated on 16/Jan/21 $$=\:\mathrm{3}\:+\:\mathrm{3}\:=\:\mathrm{6} \\ $$…
Question Number 129517 by abdurehime last updated on 16/Jan/21 $$\mathrm{tnks}\:\mathrm{sir} \\ $$ Commented by mr W last updated on 16/Jan/21 $${please}\:{don}'{t}\:{open}\:{a}\:{new}\:{thread}\:{if} \\ $$$${you}\:{just}\:{want}\:{to}\:{give}\:{comment}\:{in} \\ $$$${an}\:{existing}\:{thread}!…
Question Number 129502 by MathSh last updated on 16/Jan/21 $$\mathrm{2}^{{x}} ={a} \\ $$$$\mathrm{3}^{{x}} ={b}^{−\mathrm{1}} \\ $$$$\mathrm{54}^{{x}} =? \\ $$ Answered by bramlexs22 last updated on…
Question Number 129496 by zakirullah last updated on 16/Jan/21 Commented by zakirullah last updated on 16/Jan/21 $$\:\:\:\:\left(\mathrm{3}^{\mathrm{2n}+\mathrm{2}} \:−\mathrm{8n}−\mathrm{9}\right)\:\mathrm{is}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{64} \\ $$$$\:\:\:\:\:\:\mathrm{by}\:\mathrm{mathematical}\:\mathrm{induction}\:\mathrm{prove} \\ $$$$\:\:\:\:\:\:\mathrm{cos}\alpha+\mathrm{cos}\left(\alpha+\beta\right)+\mathrm{cos}\left(\alpha+\mathrm{2}\beta\right)+……….+ \\ $$$$\:\:\:\:\:\:\mathrm{cos}\left(\alpha+\left(\mathrm{n}−\mathrm{1}\right)\beta\right)=\:\mathrm{cos}\left(\alpha+\frac{\left(\mathrm{n}−\mathrm{1}\right)\beta}{\mathrm{2}}\right)×\frac{\mathrm{sin}\left(\mathrm{n}\beta/\mathrm{2}\right)}{\mathrm{sin}\left(\beta\mathrm{2}\right)} \\…
Question Number 129481 by talminator2856791 last updated on 16/Jan/21 $$\:\mathrm{what}\:\mathrm{does}\:\mathrm{premium}\:\mathrm{unlock}? \\ $$ Commented by Tinku Tara last updated on 16/Jan/21 $$\mathrm{Without}\:\mathrm{premium}\:\mathrm{app}\:\mathrm{name}\:\mathrm{watermark} \\ $$$$\mathrm{is}\:\mathrm{printed}\:\mathrm{on}\:\mathrm{generated}\:\mathrm{images}.\: \\ $$$$\mathrm{That}\:\mathrm{is}\:\mathrm{all}.…
Question Number 129446 by Eric002 last updated on 15/Jan/21 $${find}\:{the}\:{fourier}\:{transform}\:{of}\:{signum} \\ $$$${function} \\ $$ Answered by Olaf last updated on 16/Jan/21 $$\mathrm{sgn}\left({x}\right)\:=\:\begin{cases}{−\mathrm{1},\:{x}\:<\:\mathrm{1}}\\{\mathrm{0},\:{x}\:=\:\mathrm{0}}\\{+\mathrm{1},\:{x}\:>\:\mathrm{1}}\end{cases}\: \\ $$$$\widehat {\mathrm{sgn}}\left({f}\right)\:=\:\underset{{T}\rightarrow\infty,\alpha\rightarrow\mathrm{0}}…
Question Number 63904 by naka3546 last updated on 11/Jul/19 Commented by Prithwish sen last updated on 13/Jul/19 $$\frac{\mathrm{6}^{\mathrm{k}} }{\left(\mathrm{3}^{\mathrm{k}} −\mathrm{2}^{\mathrm{k}} \right)\left(\mathrm{3}^{\mathrm{k}+\mathrm{1}} −\mathrm{2}^{\mathrm{k}+\mathrm{1}} \right)}\:=\:\frac{\mathrm{3}^{\mathrm{k}} }{\mathrm{3}^{\mathrm{k}} −\mathrm{2}^{\mathrm{k}}…
Question Number 63900 by Rio Michael last updated on 10/Jul/19 Commented by Rio Michael last updated on 10/Jul/19 $${Inthe}\:{Diagram}\:{above}\:{ABCD}\:{and}\:{CDEF}\:{are}\:{parrallelograms} \\ $$$${which}\:{lie}\:{in}\:{thesame}\:{plane}. \\ $$$${A}\overset{\rightarrow} {{B}}=\boldsymbol{{p}}\:,\:{B}\overset{\rightarrow} {{C}}=\boldsymbol{{q}}\:\:{and}\:{C}\overset{\rightarrow}…
Question Number 129430 by MathSh last updated on 15/Jan/21 $$\mathrm{0}<{x}<\mathrm{1}\:\:\:{if}, \\ $$$${Compare}\:{it}: \\ $$$$\frac{\mathrm{1}}{{x}−\mathrm{1}}\:;\:\frac{{x}}{{x}−\mathrm{1}}\:;\:\frac{\mathrm{1}}{\mathrm{1}−{x}}\:;\:\frac{{x}}{\mathrm{1}−{x}}\:;\:\frac{{x}}{\mathrm{2}{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 129435 by Tinku Tara last updated on 15/Jan/21 $$\mathrm{For}\:\mathrm{any}\:\mathrm{app}\:\mathrm{related}\:\mathrm{question}\:\mathrm{please}\:\mathrm{write}\:\mathrm{in} \\ $$$$\mathrm{English}.\:\mathrm{Thank}\:\:\mathrm{You}. \\ $$$$\mathrm{You}\:\mathrm{can}\:\mathrm{also}\:\mathrm{send}\:\mathrm{us}\:\mathrm{an}\:\mathrm{email} \\ $$ Commented by mr W last updated on 16/Jan/21…