Question Number 62925 by otchereabdullai@gmail.com last updated on 26/Jun/19 $$\mathrm{Three}\:\mathrm{friends}\:,\:\mathrm{Boakye}\:,\:\mathrm{kwame}\:\mathrm{and}\: \\ $$$$\mathrm{kojo}\:\mathrm{thinking}\:\mathrm{that}\:\mathrm{they}\:\mathrm{are}\:\mathrm{decieving}\: \\ $$$$\mathrm{their}\:\mathrm{parents}\:\mathrm{decided}\:\mathrm{to}\:\mathrm{take}\:\mathrm{turns}\:\mathrm{to}\: \\ $$$$\mathrm{run}\:\mathrm{away}\:\mathrm{from}\:\mathrm{their}\:\mathrm{parent}\:. \\ $$$$\mathrm{Boakye}\:\mathrm{run}\:\mathrm{away}\:\mathrm{on}\:\mathrm{monday}\:\mathrm{of}\:\mathrm{the}\:\mathrm{first} \\ $$$$\mathrm{week}.\:\mathrm{After}\:\mathrm{how}\:\mathrm{many}\:\:\mathrm{weeks}\:\mathrm{will}\: \\ $$$$\mathrm{he}\:\mathrm{run}\:\mathrm{again}\:\mathrm{on}\:\mathrm{monday}? \\ $$ Answered…
Question Number 62919 by otchereabdullai@gmail.com last updated on 26/Jun/19 $$\mathrm{kelvin}\:\mathrm{and}\:\mathrm{price}\:\mathrm{were}\:\mathrm{contesting}\:\mathrm{for}\:\mathrm{an} \\ $$$$\mathrm{election}\:\mathrm{in}\:\mathrm{the}\:\mathrm{year}\:\mathrm{2016},\:\mathrm{kelvin}\:\mathrm{lost}\:\mathrm{the} \\ $$$$\mathrm{election}\:\mathrm{and}\:\:\mathrm{prince}\:\mathrm{won}\:\mathrm{the}\:\mathrm{election}\:\mathrm{thursday} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{second}\:\mathrm{week}\:\mathrm{of}\:\mathrm{December}.\:\mathrm{After} \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{days}\:\mathrm{will}\:\mathrm{prince}\:\mathrm{win}\:\mathrm{the}\:\mathrm{election} \\ $$$$\mathrm{again}\:\mathrm{on}\:\mathrm{thursday}\:\mathrm{if}\:\mathrm{the}\:\mathrm{eletion}\:\mathrm{is}\:\mathrm{postponed}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{first}\:\mathrm{week}\:\mathrm{of}\:\mathrm{january}.\:\mathrm{suppose}\:\left(\mathrm{kelvin}\:\mathrm{continious}\right. \\ $$$$\mathrm{to}\:\mathrm{loose}\:\mathrm{the}\:\mathrm{eletion}\:\mathrm{again}\:\mathrm{in}\:\mathrm{the}\:\mathrm{next}\:\mathrm{four} \\…
Question Number 128444 by ZulqarnainHaiderSial last updated on 07/Jan/21 $$\left({x}+{y}\right)\left({x}+{y}\right)=?\:{if}\:{xy}=−\mathrm{3}\:\:{and}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{10} \\ $$ Commented by BHOOPENDRA last updated on 07/Jan/21 $$ \\ $$$$\left({x}+{y}\right)^{\mathrm{2}} ={x}^{\mathrm{2}}…
Question Number 128430 by sachin1221 last updated on 07/Jan/21 $$\boldsymbol{{if}}\:\boldsymbol{{we}}\:\boldsymbol{{have}}\:\boldsymbol{{DE}} \\ $$$$\frac{\boldsymbol{{d}}^{\mathrm{2}} \boldsymbol{{x}}\left({t}\right)}{\boldsymbol{{dt}}^{\mathrm{2}} }\:=\:−\boldsymbol{{sinx}} \\ $$$$\boldsymbol{{then}}\:\boldsymbol{{find}}\:\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right) \\ $$$$\mathrm{1}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{acosht}}+\boldsymbol{{bsinht}} \\ $$$$\mathrm{2}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{a}}+\boldsymbol{{bt}} \\ $$$$\mathrm{3}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{ae}}^{\boldsymbol{{t}}} \:+\:\boldsymbol{{be}}^{\mathrm{2}\boldsymbol{{t}}} \\ $$$$\mathrm{4}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{acost}}\:+\:\boldsymbol{{bsint}}…
Question Number 128422 by Khalmohmmad last updated on 07/Jan/21 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\:\frac{{n}^{{a}} }{{b}^{{n}} }\:\:\:\:\:\:\:{a}>\mathrm{0}\:\:,\:\:{b}>\mathrm{1} \\ $$ Answered by mathmax by abdo last updated on 07/Jan/21 $$\mathrm{let}\:\mathrm{u}_{\mathrm{n}}…
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Question Number 128370 by mathocean1 last updated on 06/Jan/21 $$\left.{f}\left({x}\right)=\left({x}−\mathrm{1}\right)\sqrt{{x}−\mathrm{1}}\:{on}\:\:\right]\mathrm{1};+\infty\left[\right. \\ $$$${F}\left({x}\right)=? \\ $$ Answered by mathmax by abdo last updated on 06/Jan/21 $$\mathrm{if}\:\mathrm{you}\:\mathrm{want}\:\mathrm{derivative}\:\mathrm{f}^{'} \left(\mathrm{x}\right)=\sqrt{\mathrm{x}−\mathrm{1}}+\left(\mathrm{x}−\mathrm{1}\right)×\frac{\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{x}−\mathrm{1}}}…
Question Number 128349 by mathocean1 last updated on 06/Jan/21 $${function}\:{g}\:{is}\:{defined}\:{in}\:\left[\mathrm{0};\frac{\pi}{\mathrm{4}}\right] \\ $$$${by}\:{g}\left({x}\right)=\frac{{sinx}}{{cos}^{\mathrm{3}} {x}}. \\ $$$$\mathrm{1}.\:{Determinate}\:{a};{b}\:\in\mathbb{R}\:{such}\:{that} \\ $$$${g}'\left({x}\right)=\frac{{a}}{{cos}^{\mathrm{4}} {x}}\:+\:\frac{{b}}{{cos}^{\mathrm{2}} {x}}. \\ $$$$\mathrm{2}.{Deduct}\:{the}\:{primitive}\:{G}\:{of}\:{the}\: \\ $$$${function}\:{t}\left({x}\right)=\frac{\mathrm{1}}{{cos}^{\mathrm{4}} {x}}\:\:{such}\:{that} \\…
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Question Number 62759 by naka3546 last updated on 25/Jun/19 $${y}\:\:=\:\:{x}^{{y}} \\ $$$$\frac{{dy}}{{dx}}\:\:=\:\:? \\ $$ Answered by Kunal12588 last updated on 25/Jun/19 $${y}={x}^{{y}} \\ $$$$\Rightarrow{ln}\:{y}\:=\:{y}\:{ln}\:{x} \\…