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Question Number 128716 by shaker last updated on 09/Jan/21 Commented by Dwaipayan Shikari last updated on 09/Jan/21 $${Diverges}\:\:\rightarrow\infty \\ $$ Terms of Service Privacy Policy…
Question Number 63154 by Rio Michael last updated on 29/Jun/19 $${Given}\:{that}\:\alpha\:{and}\:\beta\:{are}\:{the}\:{roots}\:{oc}\:{the}\:{equation}\:{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0} \\ $$$$.\:{Show}\:{that}\:\:\:\lambda\mu{b}^{\mathrm{2}} =\:{ac}\left(\lambda\:+\:\mu\right)^{\mathrm{2}} ,\:{where}\:\frac{\alpha}{\beta}=\:\frac{\lambda}{\mu}. \\ $$ Commented by Prithwish sen last updated on…
Question Number 128660 by help last updated on 09/Jan/21 Commented by harckinwunmy last updated on 09/Jan/21 $${ff} \\ $$ Answered by liberty last updated on…
Question Number 128574 by mohammad17 last updated on 08/Jan/21 $${Does}\:{the}\:{function}\:{f}\left({z}\right)=\frac{\mathrm{3}{z}^{\mathrm{4}} −\mathrm{2}{z}^{\mathrm{3}} +\mathrm{8}{z}^{\mathrm{2}} −\mathrm{2}{z}+\mathrm{5}}{{z}−{i}}\: \\ $$$$ \\ $$$${continuous}\:{at}\:{z}={i}\:? \\ $$ Answered by MJS_new last updated on…
Question Number 62982 by ANTARES VY last updated on 27/Jun/19 $$\frac{\boldsymbol{\mathrm{tg}}\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)−\mathrm{1}}{\boldsymbol{\mathrm{ctg}}\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)}=\mathrm{2}\boldsymbol{\mathrm{sin}}\left(\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)\:\:\boldsymbol{\mathrm{x}}\in\left(\mathrm{180}°;\mathrm{540}°\right) \\ $$$$ \\ $$ Answered by MJS last updated on 27/Jun/19 $$\frac{\mathrm{1}}{\mathrm{cot}}=\mathrm{tan} \\ $$$$\mathrm{tan}^{\mathrm{2}}…
Question Number 128518 by shaker last updated on 08/Jan/21 Commented by bramlexs22 last updated on 08/Jan/21 $$\mathrm{3}^{\frac{\mathrm{1}}{\mathrm{n}}} \:=\:\mathrm{u}\:\Rightarrow\:\mathrm{3}^{\frac{\mathrm{1}}{\mathrm{n}}} \:+\:\mathrm{3}^{−\frac{\mathrm{1}}{\mathrm{n}}} \:=\:\frac{\mathrm{u}^{\mathrm{2}} +\mathrm{1}}{\mathrm{u}} \\ $$$$\mathrm{x}\:=\:\frac{\mathrm{u}^{\mathrm{2}} +\mathrm{1}}{\mathrm{2u}}\:\Rightarrow\:\mathrm{x}+\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}} }\:=\:\frac{\mathrm{u}^{\mathrm{2}}…
Question Number 128477 by Fikret last updated on 07/Jan/21 $${x}^{\mathrm{2}} +\mathrm{6}{y}=\mathrm{9} \\ $$$${y}^{\mathrm{2}} +\mathrm{8}{x}=\mathrm{16} \\ $$$${x}=? \\ $$ Commented by mr W last updated on…
Question Number 128464 by n0y0n last updated on 07/Jan/21 $$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin92}°\right)=\:? \\ $$ Commented by mr W last updated on 07/Jan/21 $$\mathrm{88}° \\ $$ Answered…
Question Number 62925 by otchereabdullai@gmail.com last updated on 26/Jun/19 $$\mathrm{Three}\:\mathrm{friends}\:,\:\mathrm{Boakye}\:,\:\mathrm{kwame}\:\mathrm{and}\: \\ $$$$\mathrm{kojo}\:\mathrm{thinking}\:\mathrm{that}\:\mathrm{they}\:\mathrm{are}\:\mathrm{decieving}\: \\ $$$$\mathrm{their}\:\mathrm{parents}\:\mathrm{decided}\:\mathrm{to}\:\mathrm{take}\:\mathrm{turns}\:\mathrm{to}\: \\ $$$$\mathrm{run}\:\mathrm{away}\:\mathrm{from}\:\mathrm{their}\:\mathrm{parent}\:. \\ $$$$\mathrm{Boakye}\:\mathrm{run}\:\mathrm{away}\:\mathrm{on}\:\mathrm{monday}\:\mathrm{of}\:\mathrm{the}\:\mathrm{first} \\ $$$$\mathrm{week}.\:\mathrm{After}\:\mathrm{how}\:\mathrm{many}\:\:\mathrm{weeks}\:\mathrm{will}\: \\ $$$$\mathrm{he}\:\mathrm{run}\:\mathrm{again}\:\mathrm{on}\:\mathrm{monday}? \\ $$ Answered…