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kelvin-and-price-were-contesting-for-an-election-in-the-year-2016-kelvin-lost-the-election-and-prince-won-the-election-thursday-of-the-second-week-of-December-After-how-many-days-will-prince-win-th

Question Number 62919 by otchereabdullai@gmail.com last updated on 26/Jun/19 $$\mathrm{kelvin}\:\mathrm{and}\:\mathrm{price}\:\mathrm{were}\:\mathrm{contesting}\:\mathrm{for}\:\mathrm{an} \\ $$$$\mathrm{election}\:\mathrm{in}\:\mathrm{the}\:\mathrm{year}\:\mathrm{2016},\:\mathrm{kelvin}\:\mathrm{lost}\:\mathrm{the} \\ $$$$\mathrm{election}\:\mathrm{and}\:\:\mathrm{prince}\:\mathrm{won}\:\mathrm{the}\:\mathrm{election}\:\mathrm{thursday} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{second}\:\mathrm{week}\:\mathrm{of}\:\mathrm{December}.\:\mathrm{After} \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{days}\:\mathrm{will}\:\mathrm{prince}\:\mathrm{win}\:\mathrm{the}\:\mathrm{election} \\ $$$$\mathrm{again}\:\mathrm{on}\:\mathrm{thursday}\:\mathrm{if}\:\mathrm{the}\:\mathrm{eletion}\:\mathrm{is}\:\mathrm{postponed}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{first}\:\mathrm{week}\:\mathrm{of}\:\mathrm{january}.\:\mathrm{suppose}\:\left(\mathrm{kelvin}\:\mathrm{continious}\right. \\ $$$$\mathrm{to}\:\mathrm{loose}\:\mathrm{the}\:\mathrm{eletion}\:\mathrm{again}\:\mathrm{in}\:\mathrm{the}\:\mathrm{next}\:\mathrm{four} \\…

if-we-have-DE-d-2-x-t-dt-2-sinx-then-find-x-t-1-x-t-acosht-bsinht-2-x-t-a-bt-3-x-t-ae-t-be-2t-4-x-t-acost-bsint-

Question Number 128430 by sachin1221 last updated on 07/Jan/21 $$\boldsymbol{{if}}\:\boldsymbol{{we}}\:\boldsymbol{{have}}\:\boldsymbol{{DE}} \\ $$$$\frac{\boldsymbol{{d}}^{\mathrm{2}} \boldsymbol{{x}}\left({t}\right)}{\boldsymbol{{dt}}^{\mathrm{2}} }\:=\:−\boldsymbol{{sinx}} \\ $$$$\boldsymbol{{then}}\:\boldsymbol{{find}}\:\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right) \\ $$$$\mathrm{1}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{acosht}}+\boldsymbol{{bsinht}} \\ $$$$\mathrm{2}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{a}}+\boldsymbol{{bt}} \\ $$$$\mathrm{3}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{ae}}^{\boldsymbol{{t}}} \:+\:\boldsymbol{{be}}^{\mathrm{2}\boldsymbol{{t}}} \\ $$$$\mathrm{4}.\:\boldsymbol{{x}}\left(\boldsymbol{{t}}\right)=\:\boldsymbol{{acost}}\:+\:\boldsymbol{{bsint}}…

f-x-x-1-x-1-on-1-F-x-

Question Number 128370 by mathocean1 last updated on 06/Jan/21 $$\left.{f}\left({x}\right)=\left({x}−\mathrm{1}\right)\sqrt{{x}−\mathrm{1}}\:{on}\:\:\right]\mathrm{1};+\infty\left[\right. \\ $$$${F}\left({x}\right)=? \\ $$ Answered by mathmax by abdo last updated on 06/Jan/21 $$\mathrm{if}\:\mathrm{you}\:\mathrm{want}\:\mathrm{derivative}\:\mathrm{f}^{'} \left(\mathrm{x}\right)=\sqrt{\mathrm{x}−\mathrm{1}}+\left(\mathrm{x}−\mathrm{1}\right)×\frac{\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{x}−\mathrm{1}}}…

function-g-is-defined-in-0-pi-4-by-g-x-sinx-cos-3-x-1-Determinate-a-b-R-such-that-g-x-a-cos-4-x-b-cos-2-x-2-Deduct-the-primitive-G-of-the-function-t-x-1-cos-4-x-such-t

Question Number 128349 by mathocean1 last updated on 06/Jan/21 $${function}\:{g}\:{is}\:{defined}\:{in}\:\left[\mathrm{0};\frac{\pi}{\mathrm{4}}\right] \\ $$$${by}\:{g}\left({x}\right)=\frac{{sinx}}{{cos}^{\mathrm{3}} {x}}. \\ $$$$\mathrm{1}.\:{Determinate}\:{a};{b}\:\in\mathbb{R}\:{such}\:{that} \\ $$$${g}'\left({x}\right)=\frac{{a}}{{cos}^{\mathrm{4}} {x}}\:+\:\frac{{b}}{{cos}^{\mathrm{2}} {x}}. \\ $$$$\mathrm{2}.{Deduct}\:{the}\:{primitive}\:{G}\:{of}\:{the}\: \\ $$$${function}\:{t}\left({x}\right)=\frac{\mathrm{1}}{{cos}^{\mathrm{4}} {x}}\:\:{such}\:{that} \\…