Question Number 127203 by naka3546 last updated on 27/Dec/20 $$\int\:\:\frac{{dx}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{26}}}\:\:=\:\:\centerdot\centerdot\centerdot\:\:? \\ $$$${Please}\:\:{show}\:\:{your}\:\:{workings}\:\:! \\ $$ Commented by liberty last updated on 27/Dec/20 $$\:\int\:\frac{{dx}}{\:\sqrt{\left({x}+\mathrm{1}\right)^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} }}\:…
Question Number 127198 by bramlexs22 last updated on 27/Dec/20 $$\:\:{Should}\:{auld}\:{acquaintance}\:{be}\:{forgot} \\ $$$${and}\:{never}\:{brought}\:{to}\:{mine}? \\ $$$${Should}\:{auld}\:{aquaintance}\:{be}\:{forgot} \\ $$$${and}\:{days}\:{of}\:{auld}\:{lang}\:{syne}? \\ $$$$ \\ $$$${For}\:{auld}\:{lang}\:{syne},\:{my}\:{dear} \\ $$$${for}\:{auld}\:{lang}\:{syne}\: \\ $$$${we}'{ll}\:{take}\:{a}\:{cup}\:{o}'\:{kindness}\:{yet} \\…
Question Number 192732 by mokys last updated on 25/May/23 $${let}\:{the}\:{closed}\:{interval}\:\left[{a},{b}\right]\:{be}\:{the}\:{domain}\:{of}\:{the}\:{function}\:{f}\: \\ $$$${find}\:{the}\:{domain}\:{of}\:{f}\left({x}−\mathrm{3}\right)\:{and}\:{f}\left({x}+\mathrm{3}\right)\:?\:\: \\ $$ Answered by MM42 last updated on 25/May/23 $${a}\leqslant{x}−\mathrm{3}\leqslant{b}\Rightarrow{a}+\mathrm{3}\leqslant{x}\leqslant{b}+\mathrm{3}\Rightarrow{D}_{{f}−\mathrm{3}} =\left[{a}+\mathrm{3},{b}+\mathrm{3}\right] \\ $$$${a}\leqslant{x}+\mathrm{3}\leqslant{b}\Rightarrow{a}−\mathrm{3}\leqslant{x}\leqslant{b}−\mathrm{3}\Rightarrow{D}_{{f}+\mathrm{3}}…
Question Number 127196 by mohammad17 last updated on 27/Dec/20 Commented by mohammad17 last updated on 27/Dec/20 $${find}\:{the}\:{ordenery}\:{differention}\:{equation}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 127182 by danielasebhofoh last updated on 27/Dec/20 Answered by Dwaipayan Shikari last updated on 27/Dec/20 $$\int_{\mathrm{0}} ^{\mathrm{1}} {e}^{\frac{{i}\pi{x}}{\mathrm{2}}} {dx}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{i}^{{x}} ={e}^{\frac{{i}\pi{x}}{\mathrm{2}}} \\ $$$$=\frac{\mathrm{2}}{\pi{i}}\left({e}^{\frac{{i}\pi}{\mathrm{2}}} −\mathrm{1}\right)=\frac{\mathrm{2}}{\pi{i}}\left({i}−\mathrm{1}\right)=\frac{\mathrm{2}}{\pi}−\frac{\mathrm{2}}{\pi{i}}=\frac{\mathrm{2}}{\pi}\left(\mathrm{1}+{i}\right)…
Question Number 192707 by otchereabdullai@gmail.com last updated on 25/May/23 $$\:{Is}\:{been}\:{a}\:{while}\:{we}\:{hear}\:{from} \\ $$$$\:{Mr}.\:{W}\:\left({prof}\right)\:{hope}\:{he}\:{is}\:{fine}\:{by}\:{Gods} \\ $$$${grace} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 127158 by Jamshidbek last updated on 27/Dec/20 Commented by mr W last updated on 27/Dec/20 $${x}=\phi={golden}\:{ratio}\approx\mathrm{1}.\mathrm{618} \\ $$ Answered by mindispower last updated…
Question Number 61622 by naka3546 last updated on 05/Jun/19 $${If}\:\:\:\sqrt{{x}\:\sqrt{\left({x}+\mathrm{1}\right)\:\sqrt{\left({x}+\mathrm{2}\right)\:\sqrt{\left({x}+\mathrm{3}\right)\:\sqrt{…}}}}}\:\:\:=\:\:\:\mathrm{2019} \\ $$$${so}\:\:\sqrt{{x}\:+\:\sqrt{\left({x}+\mathrm{1}\right)\:+\:\:\sqrt{\left({x}+\mathrm{2}\right)\:+\:\:\sqrt{\left({x}+\mathrm{3}\right)\:+\:\:\sqrt{…}}}}}\:\:\:=\:\:\:? \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 192689 by sciencestudentW last updated on 24/May/23 $${a}\:{plant}\:{grow}\:{up}\:\mathrm{1}.\mathrm{67}{cm}\:{in}\:{the}\:{first}\:{week} \\ $$$${after}\:{that}\:{it}\:{grow}\:{up}\:\mathrm{4\%}\:{grow}\:{up}\:{more} \\ $$$${than}\:{the}\:{first}\:{week}\:{every}\:{week},\:{how}\:{much} \\ $$$${will}\:{grow}\:{up}\:{in}\:\mathrm{11}{th}\:{week}? \\ $$ Commented by sciencestudentW last updated on 24/May/23…
Question Number 61613 by naka3546 last updated on 05/Jun/19 $${S}\:\:=\:\:\mathrm{1}\:+\:\frac{\mathrm{3}}{\mathrm{2018}}\:+\:\frac{\mathrm{5}}{\mathrm{2018}^{\mathrm{2}} }\:+\:\frac{\mathrm{7}}{\mathrm{2018}^{\mathrm{3}} }\:+\:… \\ $$$$\mathrm{4}{S}\:−\:{S}^{\mathrm{2}} \:\:=\:\:? \\ $$ Commented by maxmathsup by imad last updated on…