Question Number 127521 by mohammad17 last updated on 30/Dec/20 $$\underset{\mathrm{0}} {\int}^{\:\mathrm{2}} \sqrt[{\mathrm{3}}]{\mathrm{4}{x}−{x}^{\mathrm{3}} }{dx} \\ $$ Answered by Dwaipayan Shikari last updated on 30/Dec/20 $$\int_{\mathrm{0}} ^{\mathrm{2}}…
Question Number 127512 by mohammad17 last updated on 30/Dec/20 Commented by sts last updated on 30/Dec/20 $$ \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 127508 by mohammad17 last updated on 30/Dec/20 Commented by mohammad17 last updated on 30/Dec/20 $${such}\:{that}\:\beta\:{beta}\:{function} \\ $$ Answered by Ar Brandon last updated…
Question Number 193037 by DAVONG last updated on 02/Jun/23 Answered by Subhi last updated on 02/Jun/23 $${DC}^{\mathrm{2}} ={DB}.{AD} \\ $$$$\mathrm{20}^{\mathrm{2}} ={DB}.\left(\mathrm{9}+{DB}\right) \\ $$$${DB}^{\mathrm{2}} +\mathrm{9}{DB}−\mathrm{400}=\mathrm{0} \\…
Question Number 127490 by ZiYangLee last updated on 30/Dec/20 Commented by mr W last updated on 30/Dec/20 $${Q}\mathrm{45}. \\ $$$$\frac{{dx}}{{dt}}=\mathrm{3}{t}^{\mathrm{2}} \\ $$$$\frac{{dy}}{{dt}}=\mathrm{2}{t} \\ $$$$\frac{{dy}}{{dx}}=\frac{\frac{{dy}}{{dt}}}{\frac{{dx}}{{dt}}}=\frac{\mathrm{2}{t}}{\mathrm{3}{t}^{\mathrm{2}} }=\frac{\mathrm{2}}{\mathrm{3}{t}}…
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Question Number 127477 by ZiYangLee last updated on 30/Dec/20 $$\mathrm{If}\:{y}=\frac{\mathrm{1}}{{x}\left(\mathrm{1}−{x}\right)}, \\ $$$$\mathrm{show}\:\mathrm{that}\:\frac{{d}^{{n}} {y}}{{dx}^{{n}} }={n}!\left[\frac{\left(−\mathrm{1}\right)^{{n}} }{{x}^{{n}+\mathrm{1}} }+\frac{\mathrm{1}}{\left(\mathrm{1}−{x}\right)^{{n}+\mathrm{1}} }\right] \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 192992 by gatocomcirrose last updated on 01/Jun/23 $$\begin{cases}{\mathrm{2x}+\mathrm{3y}\equiv\mathrm{1}\left(\mathrm{mod26}\right)}\\{\mathrm{7x}+\mathrm{8y}\equiv\mathrm{2}\left(\mathrm{mod26}\right)}\end{cases} \\ $$$$ \\ $$ Answered by MM42 last updated on 01/Jun/23 $$\mathrm{2}{x}+\mathrm{3}{y}=\mathrm{26}{k}+\mathrm{1}\:\:\&\:\mathrm{7}{x}+\mathrm{8}{y}=\mathrm{26}{k}'+\mathrm{2} \\ $$$$\Rightarrow\mathrm{5}{x}=\mathrm{26}{k}''−\mathrm{2}\Rightarrow{x}\overset{\mathrm{26}} {\equiv}\mathrm{10}\:\checkmark…