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dx-x-5-1-

Question Number 212896 by MrGaster last updated on 26/Oct/24 dxx51 Commented by Frix last updated on 26/Oct/24 $${x}^{\mathrm{5}} −\mathrm{1}=\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} +\frac{\mathrm{1}−\sqrt{\mathrm{5}}}{\mathrm{2}}{x}+\mathrm{1}\right)\left({x}^{\mathrm{2}} +\frac{\mathrm{1}+\sqrt{\mathrm{5}}}{\mathrm{2}}{x}+\mathrm{1}\right) \

i-generalized-Bessel-function-s-Laplace-Transform-L-TJ-z-s-s-2-1-s-2-1-s-0-R-L-T-Y-z-cot-pi-s-s-2-1-s-2-1-csc-pi-s-s-2-1

Question Number 212765 by issac last updated on 23/Oct/24 igeneralizedBesselfunctionsLaplaceTransformL.TJν(z)=(s+s2+1)νs2+1,s[0,),νR$$\mathrm{L}.\mathrm{T}\:{Y}_{\nu} \left({z}\right)=\frac{\mathrm{cot}\left(\pi\nu\right)\left({s}+\sqrt{{s}^{\mathrm{2}} +\mathrm{1}}\right)^{−\nu} }{\:\sqrt{{s}^{\mathrm{2}} +\mathrm{1}}}−\frac{\mathrm{csc}\left(\pi\nu\right)\left({s}+\sqrt{{s}^{\mathrm{2}} +\mathrm{1}}\right)^{\nu}…