Question Number 126253 by mohammad17 last updated on 18/Dec/20 Answered by physicstutes last updated on 18/Dec/20 $$\mathrm{Exactly} \\ $$$$\:{a}\:+\:{ar}\:+\:{ar}^{\mathrm{2}} \:+…+{ar}^{{n}−\mathrm{1}} \:=\:\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}{ar}^{{n}−\mathrm{1}} \:=\:\frac{{a}\left(\mathrm{1}−{r}^{{n}} \right)}{\mathrm{1}−{r}}…
Question Number 126250 by mohammad17 last updated on 18/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 126251 by mohammad17 last updated on 18/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 126238 by mohammad17 last updated on 18/Dec/20 Answered by Olaf last updated on 18/Dec/20 $$\Omega\:=\:\int_{\mathrm{0}} ^{\mathrm{1}} \int_{{y}^{\mathrm{2}} } ^{\mathrm{1}} \frac{{e}^{{x}} }{\:\sqrt{{x}}}{dxdy} \\ $$$$\mathrm{Let}\:{u}\:=\:\sqrt{{x}}…
Question Number 126231 by mohammad17 last updated on 18/Dec/20 $${prove}\:{that}\::{Im}\left({iz}\right)={Re}\left({z}\right) \\ $$ Answered by floor(10²Eta[1]) last updated on 18/Dec/20 $$\mathrm{z}=\mathrm{a}+\mathrm{bi}\Rightarrow\mathrm{iz}=\mathrm{ai}−\mathrm{b} \\ $$$$\mathrm{Im}\left(\mathrm{iz}\right)=\mathrm{a} \\ $$$$\mathrm{Re}\left(\mathrm{z}\right)=\mathrm{a} \\…
Question Number 126226 by Tinku Tara last updated on 18/Dec/20 $$\mathrm{v2}.\mathrm{245} \\ $$$$\mathrm{Editor}\:\mathrm{allow}\:\mathrm{to}\:\mathrm{post}\:\mathrm{content}\:\mathrm{using} \\ $$$$\mathrm{following} \\ $$$$\mathrm{Font}\underline{\:\mathrm{abc}}\:\underset{\mathrm{test}} {\underbrace{\mathrm{ab}..\mathrm{xyz}}}\:\:\:\:\frac{\mathrm{200}×\cancel{\mathrm{10}}}{\cancel{\mathrm{10}}}\:\:\Sigma\mathrm{bc} \\ $$$$\mathrm{table}\:\begin{array}{|c|c|}{\mathrm{2}}&\hline{\mathrm{4}}\\{\mathrm{3}}&\hline{\mathrm{5}}\\\hline\end{array} \\ $$$$\mathrm{also}\:\mathrm{you}\:\mathrm{write}\:\mathrm{posts}\:\mathrm{using}\:\mathrm{any} \\ $$$$\mathrm{laguage}\:\mathrm{font}\:\mathrm{supported}\:\mathrm{in}-\mathrm{app}. \\…
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Question Number 126206 by amns last updated on 18/Dec/20 $${If}\:\:\:\left({n}\:>\:{m}\right),\: \\ $$$$\mathrm{then}\:\frac{{a}^{{m}} }{{a}^{{n}} }\:=\:{a}^{?} \\ $$ Commented by amns last updated on 18/Dec/20 $$\mathrm{Is}\:\mathrm{the}\:\mathrm{ans}.\:{a}^{\frac{\mathrm{1}}{{n}\:−\:{m}}} \:\:\:?…
Question Number 191723 by SANOGO last updated on 29/Apr/23 $$\int_{\mathrm{0}} ^{\mathrm{2}\pi} \mathrm{3}{sintcost}\:{dt} \\ $$ Answered by mehdee42 last updated on 29/Apr/23 $$\left.{I}=\frac{\mathrm{3}}{\mathrm{2}}{sin}^{\mathrm{2}} {t}\:\right]_{\mathrm{0}} ^{\mathrm{2}\pi} \:=\mathrm{0}…
Question Number 126181 by aurpeyz last updated on 18/Dec/20 $${evaluate}\:{the}\:{integral}\:{of} \\ $$$$\int_{\mathrm{0}} ^{\pi} {dx}\int_{\mathrm{1}} ^{\mathrm{2}} {dy}\delta\left({sin}\mathrm{2}{x}\right)\delta\left({x}^{\mathrm{2}} −{y}^{\mathrm{2}} \right) \\ $$ Commented by aurpeyz last updated…