Question Number 126175 by naka3546 last updated on 17/Dec/20 $${Prove}\:\:{that} \\ $$$$\:\:\:\:\:\:{a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} \:+\:{c}^{\mathrm{2}} \:+\:\mathrm{6}\:\geqslant\:\mathrm{3}\left({a}\:+\:{b}\:+\:{c}\right) \\ $$$${a},\:{b},\:{c}\:\in\:\mathbb{R}^{+} \\ $$ Commented by PRITHWISH SEN 2 last…
Question Number 60635 by naka3546 last updated on 23/May/19 Answered by MJS last updated on 23/May/19 $$\mathrm{we}\:\mathrm{have}\:\mathrm{6}^{\mathrm{6}} =\mathrm{46656}\:\mathrm{possible}\:\mathrm{results} \\ $$$$\mathrm{33}= \\ $$$$\mathrm{666663}\:\Rightarrow\:\mathrm{6}\:\mathrm{permutations} \\ $$$$\mathrm{666654}\:\Rightarrow\:\mathrm{30}\:\mathrm{permutations} \\…
Question Number 60636 by naka3546 last updated on 23/May/19 $${Number}\:\:{of}\:\:{different}\:\:{permutation}\:\:{of}\:\:\:{MISSISSIPI}\:\:\:{is}\:\:… \\ $$ Answered by tanmay last updated on 23/May/19 $${I}=\mathrm{4}\:\:{M}=\mathrm{1}\:\:{P}=\mathrm{1}\:\:{S}=\mathrm{4} \\ $$$$\frac{\mathrm{10}!}{\mathrm{4}!×\mathrm{4}!} \\ $$$$ \\…
Question Number 126164 by Kunal12588 last updated on 17/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 126160 by A8;15: last updated on 17/Dec/20 Commented by mr W last updated on 17/Dec/20 $$\Rightarrow\:{see}\:{Q}\mathrm{126130} \\ $$ Terms of Service Privacy Policy…
Question Number 60620 by naka3546 last updated on 22/May/19 $$\mathrm{4}^{{x}} \:+\:\mathrm{9}^{{x}} \:+\:\mathrm{25}^{{x}} \:\:=\:\:\mathrm{6}^{{x}} \:+\:\mathrm{10}^{{x}} \:+\:\mathrm{15}^{{x}} \\ $$$${x}\:\:=\:\:? \\ $$ Answered by fjdjdcjv last updated on…
Question Number 60611 by aliesam last updated on 22/May/19 $${prove}\:{that}\:\underset{−\infty} {\overset{\infty} {\int}}{x}^{\mathrm{2}} {e}^{−{x}^{\mathrm{2}} } {cos}\left({x}^{\mathrm{2}} \right){sin}\left({x}^{\mathrm{2}} \right)\:{dx}\:=\:\frac{\sqrt{\pi}{sin}\left(\frac{\mathrm{3}}{\mathrm{2}}{tan}^{−\mathrm{1}} \left(\mathrm{2}\right)\right)}{\mathrm{4}\:\sqrt[{\mathrm{4}}]{\mathrm{125}}} \\ $$$${anyone}\:{can}\:{help}\:{me}\:{with}\:{this}\:{please} \\ $$$$ \\ $$ Answered…
Question Number 126144 by Ndala last updated on 17/Dec/20 $${if}:\:{a}+{b}={c} \\ $$$${Prove}\:{that}:\:{a}^{\frac{\mathrm{2}}{\mathrm{3}}} +{b}^{\frac{\mathrm{2}}{\mathrm{3}}} >{c}^{\frac{\mathrm{2}}{\mathrm{3}}} \\ $$$$. \\ $$$$\mathrm{H}{elp}\:{me},\:{please}! \\ $$ Answered by MJS_new last updated…
Question Number 191668 by SEKRET last updated on 28/Apr/23 $$\:\:\:\:\int\:\:\frac{\sqrt{\boldsymbol{\mathrm{x}}}}{\:\sqrt{\left(\mathrm{1}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} \right)^{\mathrm{3}} }}\boldsymbol{\mathrm{dx}}\:\:\:\:=\:\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 126130 by Algoritm last updated on 17/Dec/20 Commented by talminator2856791 last updated on 17/Dec/20 $$\:\mathrm{this}\:\mathrm{looks}\:\mathrm{like}\:\mathrm{physics}\:\mathrm{question} \\ $$ Answered by mr W last updated…