Question Number 126127 by mohammad17 last updated on 17/Dec/20 Commented by mohammad17 last updated on 17/Dec/20 $${help}\:{me}\:{sir} \\ $$ Answered by mahdipoor last updated on…
Question Number 126124 by ZiYangLee last updated on 17/Dec/20 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{2}^{{n}} +\mathrm{2}>{n}^{\mathrm{2}\:} \mathrm{for}\:{n}\in\mathbb{N}\:\mathrm{by} \\ $$$$\mathrm{mathematical}\:\mathrm{induction}. \\ $$ Commented by talminator2856791 last updated on 17/Dec/20 $$\:\mathrm{i}\:\mathrm{was}\:\mathrm{having}\:\mathrm{the}\:\mathrm{time}\:\mathrm{of}\:\mathrm{my}\:\mathrm{life}\:\mathrm{till}\:\mathrm{i}\:\mathrm{read}\:“\mathrm{by}\:\mathrm{mathematical}\:\mathrm{induction}''! \\…
Question Number 191652 by 073 last updated on 28/Apr/23 Commented by 073 last updated on 28/Apr/23 $$\mathrm{solution}???? \\ $$ Answered by aleks041103 last updated on…
Question Number 126114 by zakirullah last updated on 17/Dec/20 Answered by talminator2856791 last updated on 17/Dec/20 $$\:\mathrm{quantity}\:\frac{\:\:\:\frac{\mathrm{100\%}}{\mathrm{20\%}}\:×\:\mathrm{90}\:\:\:\:\:}{\mathrm{48}}\:\mathrm{kg} \\ $$$$\:=\:\mathrm{9}.\mathrm{375}\:\mathrm{kg} \\ $$ Commented by zakirullah last…
Question Number 126117 by zakirullah last updated on 17/Dec/20 Answered by talminator2856791 last updated on 17/Dec/20 $$\mathrm{8\%} \\ $$ Commented by zakirullah last updated on…
Question Number 60577 by naka3546 last updated on 22/May/19 $$\mathrm{2}\sqrt{\mathrm{1}\:+\:\mathrm{3}\sqrt{\mathrm{1}\:+\:\mathrm{5}\sqrt{\mathrm{1}\:+\:\mathrm{7}\sqrt{\mathrm{1}\:+\:\mathrm{11}\sqrt{\mathrm{1}\:+\:\mathrm{13}\sqrt{\mathrm{1}\:+\:\mathrm{17}\sqrt{…}}}}}}}\:\:=\:\:{x} \\ $$$${x}\:\:=\:\:? \\ $$ Commented by ajfour last updated on 22/May/19 $$\mathrm{Is}\:\mathrm{there}\:\mathrm{such}\:\mathrm{a}\:\mathrm{question}\:\mathrm{in}\:\mathrm{a}\:\mathrm{book}? \\ $$ Answered…
Question Number 191651 by 073 last updated on 28/Apr/23 Commented by 073 last updated on 28/Apr/23 $$\mathrm{solution}\:\mathrm{please}??? \\ $$ Answered by aleks041103 last updated on…
Question Number 191640 by vishal1234 last updated on 28/Apr/23 $${x}^{\mathrm{3}} −\mathrm{1}\:=\:\left({x}−\mathrm{1}\right)\:\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right) \\ $$$$\Rightarrow\:{x}\:=\:\mathrm{1}\:{and}\:{x}\:=\:\frac{−\mathrm{1}\pm\sqrt{\mathrm{3}}\:{i}}{\mathrm{2}} \\ $$$$\Rightarrow\:{w}\:=\:−\frac{\mathrm{1}}{\mathrm{2}}\:+\:\frac{\sqrt{\mathrm{3}}{i}\:}{\mathrm{2}}\:{and}\:{w}^{\mathrm{2}} \:=\:−\frac{\mathrm{1}}{\mathrm{2}}\:−\:\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:{i} \\ $$$$\Rightarrow\:{w}^{\mathrm{3}} \:=\:\mathrm{1} \\ $$$${similarly}\:{x}^{\mathrm{3}} \:+\:\mathrm{1}=\:\mathrm{0} \\ $$$$\Rightarrow\:{x}\:=\:−\mathrm{1}\:{and}\:{x}\:=−{w}^{\mathrm{2}}…
Question Number 126098 by ZiYangLee last updated on 17/Dec/20 $$\mathrm{Prove}\:\mathrm{that}\: \\ $$$$\mathrm{27}\left(\mathrm{sin}^{\mathrm{4}} \alpha+\mathrm{2cos}^{\mathrm{4}} \alpha\right)\geqslant\mathrm{16}\left(\mathrm{sin2}\alpha\right)^{\mathrm{2}} \\ $$ Answered by MJS_new last updated on 17/Dec/20 $$\mathrm{sin}\:\mathrm{2}\alpha\:=\mathrm{2sin}\:\alpha\:\mathrm{cos}\:\alpha \\…
Question Number 126097 by amns last updated on 17/Dec/20 Commented by amns last updated on 17/Dec/20 $$\mathrm{I}\:\mathrm{need}\:\mathrm{someone}'\mathrm{s}\:\mathrm{help}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{it}!!! \\ $$ Answered by Dwaipayan Shikari last updated…