Question Number 191626 by yaba1 last updated on 27/Apr/23 Answered by a.lgnaoui last updated on 28/Apr/23 $$\:\:\:\mathrm{Calcul}\:\mathrm{de}\:\mathrm{Resistance}\:\mathrm{dans}\:\mathrm{les}\:\mathrm{4}\:\mathrm{circuits} \\ $$$$\bullet\mathrm{1}\boldsymbol{\mathrm{a}}\:\:\:\boldsymbol{\mathrm{U}}=\boldsymbol{\mathrm{RI}}\:\:\:\mathrm{avec}\:\:\frac{\mathrm{1}}{\mathrm{R}}=\frac{\mathrm{1}}{\mathrm{R1}}+\frac{\mathrm{1}}{\mathrm{R2}}+\frac{\mathrm{1}}{\mathrm{R3}} \\ $$$$\:\:\:\:\:=\frac{\mathrm{R1}+\mathrm{R2}}{\mathrm{R1}×\mathrm{R2}}+\frac{\mathrm{1}}{\mathrm{R3}}=\frac{\left(\mathrm{R1}×\mathrm{R3}+\mathrm{R2}×\mathrm{R3}+\mathrm{R1}×\mathrm{R2}\right)}{\mathrm{R1}×\mathrm{R2}×\mathrm{R3}} \\ $$$$\:\:\:\:\:\boldsymbol{\mathrm{R}}=\frac{\mathrm{R1}×\mathrm{R2}×\mathrm{R3}}{\mathrm{R1}×\mathrm{R2}+\mathrm{R2}×\mathrm{R3}+\mathrm{R1}×\mathrm{R3}} \\ $$$$…
Question Number 126082 by amns last updated on 17/Dec/20 $$\boldsymbol{\mathrm{There}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{only}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{three}}\:-\:\boldsymbol{\mathrm{digit}}\:\boldsymbol{\mathrm{number}}\:\boldsymbol{\mathrm{which}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{square}} \\ $$$$\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{also}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{cube}}.\:\boldsymbol{\mathrm{Now}}\:\boldsymbol{\mathrm{can}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{tell}}\:\boldsymbol{\mathrm{me}}\:\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{number}}? \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\left[{Help}\:{me}\right] \\ $$ Commented by mr…
Question Number 126079 by amns last updated on 17/Dec/20 $$\boldsymbol{\mathrm{If}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{product}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{three}}\:\boldsymbol{\mathrm{consecutive}}\:\boldsymbol{\mathrm{prime}}\:\boldsymbol{\mathrm{numbers}}\:\boldsymbol{\mathrm{is}}\:\mathrm{7}\:\boldsymbol{\mathrm{times}} \\ $$$$\boldsymbol{\mathrm{their}}\:\boldsymbol{\mathrm{sum}},\:\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{prime}}\:\boldsymbol{\mathrm{number}}\:\boldsymbol{\mathrm{three}}? \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\left[{Ans}.\:{will}\:{be}\:{commented}\:{by}\:{me}\:{after}\:{someone}\:{tried}\:{to}\:{ans}.\:{it}\right] \\ $$ Commented by som(math1967)…
Question Number 126078 by amns last updated on 17/Dec/20 $$\boldsymbol{\mathrm{Tell}}\:\boldsymbol{\mathrm{me}} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\:−\:\frac{\mathrm{1}}{\mathrm{12}}\:−\:\frac{\mathrm{1}}{\mathrm{20}}\:−\:\frac{\mathrm{1}}{\mathrm{30}}\:−\:\frac{\mathrm{1}}{\mathrm{42}}\:−\:…..\:−\:\frac{\mathrm{1}}{\mathrm{210}}\:=\:? \\ $$ Commented by Dwaipayan Shikari last updated on 17/Dec/20 $$\frac{\mathrm{7}}{\mathrm{30}} \\ $$…
Question Number 191611 by vishal1234 last updated on 27/Apr/23 $${if}\:{x}^{\mathrm{2}} −{x}+\mathrm{1}\:=\:\mathrm{0}\:{and}\:\alpha\:{and}\:\beta\:{are}\:{thd}\:{roots} \\ $$$${of}\:{this}\:{equation}\:{then}\:{evaluate}\:\frac{\alpha^{\mathrm{100}} +\beta^{\mathrm{100}} }{\alpha^{\mathrm{100}} −\beta^{\mathrm{100}} } \\ $$ Answered by mehdee42 last updated on…
Question Number 126046 by zakirullah last updated on 16/Dec/20 Commented by zakirullah last updated on 16/Dec/20 $$\boldsymbol{{please}}\:\boldsymbol{{help}}? \\ $$$$\:\:\:\boldsymbol{{A}}\:\boldsymbol{{quantity}}\:\boldsymbol{{of}}\:\boldsymbol{{tea}}\:\boldsymbol{{is}}\:\boldsymbol{{sold}}\:\boldsymbol{{at}}\:\boldsymbol{{Rs}}\:\mathrm{48}\:\boldsymbol{{per}}\:\boldsymbol{{kg}} \\ $$$$\boldsymbol{{at}}\:\boldsymbol{{a}}\:\boldsymbol{{profit}}\:\boldsymbol{{of}}\:\mathrm{20\%}\:.\:\boldsymbol{{the}}\:\boldsymbol{{total}}\:\boldsymbol{{gain}}\:\boldsymbol{{is}}\:\mathrm{90}. \\ $$$$\boldsymbol{{what}}\:\boldsymbol{{is}}\:\boldsymbol{{the}}\:\boldsymbol{{quantity}}\:\boldsymbol{{of}}\:\boldsymbol{{tea}}? \\ $$…
Question Number 191582 by Matica last updated on 26/Apr/23 $$\:\:{f}\left({x}\right)={x}^{{n}} \:.\:\:{find}\: \\ $$$$\:\:\:{A}={f}\left(\mathrm{1}\right)+\frac{{f}^{'} \left(\mathrm{1}\right)}{\mathrm{1}}+\frac{{f}^{''} \left(\mathrm{1}\right)}{\mathrm{2}}+\frac{{f}^{'''} \left(\mathrm{1}\right)}{\mathrm{3}}+…+\frac{{f}^{\left({n}\right)} \left(\mathrm{1}\right)}{{n}} \\ $$ Answered by aleks041103 last updated on…
Question Number 60510 by aliesam last updated on 21/May/19 Commented by maxmathsup by imad last updated on 21/May/19 $${let}\:{A}\:=\int_{\mathrm{0}} ^{\infty} \:\:\:\:\frac{{cos}\left({xt}\right)}{{ch}\left({t}\right)}\:{dt}\:\Rightarrow\:{A}\:=\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{cos}\left({xt}\right)}{\frac{{e}^{{t}} \:+{e}^{−{t}} }{\mathrm{2}}}\:{dt}…
Question Number 126040 by mohammad17 last updated on 16/Dec/20 Commented by mohammad17 last updated on 17/Dec/20 $$? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 191579 by 073 last updated on 26/Apr/23 $$\mathrm{f}\left(\mathrm{x}\right)=\mid\mathrm{x}\mid \\ $$$$\mathrm{f}^{−\mathrm{1}} \left(\mathrm{x}\right)=? \\ $$$$\mathrm{solution}? \\ $$ Answered by mr W last updated on 26/Apr/23…