Question Number 125969 by nico last updated on 16/Dec/20 Commented by nico last updated on 16/Dec/20 $${help}… \\ $$ Answered by MJS_new last updated on…
Question Number 191484 by MATHEMATICSAM last updated on 24/Apr/23 $$\left({x}\:+\:\sqrt{\mathrm{1}\:+\:{x}^{\mathrm{2}} }\right)\left({y}\:+\:\sqrt{\mathrm{1}\:+\:{y}^{\mathrm{2}} }\right)\:=\:\mathrm{1} \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\left({x}\:+\:{y}\right)^{\mathrm{2}} \:? \\ $$ Answered by witcher3 last updated on 24/Apr/23 $$\mathrm{ln}\left(\mathrm{x}+\sqrt{\mathrm{1}+\mathrm{x}^{\mathrm{2}}…
Question Number 125944 by Algoritm last updated on 15/Dec/20 Commented by JDamian last updated on 15/Dec/20 $${What}\:{is}\:{a}_{{n}} ? \\ $$ Commented by Algoritm last updated…
Question Number 60398 by Kunal12588 last updated on 20/May/19 $${I}\:{am}\:{very}\:{sorry}\:{mr}\:{W}\:{sir}\:{for}\:{taking}\:{your}\: \\ $$$${valuable}\:{time} \\ $$$${thank}\:{you}\:{very}\:{much}\:{i}\:{got}\:{my}\:{mistake}. \\ $$$${I}\:{will}\:{work}\:{on}\:{my}\:{basics}\:{thank}\:{you} \\ $$$${and}\:{I}\:{am}\:{very}\:{sorry}. \\ $$ Commented by mr W last…
Question Number 60386 by Kunal12588 last updated on 20/May/19 $$\underset{{x}\rightarrow\mathrm{0}} {{lim}}\frac{{sin}\left(\pi{cos}^{\mathrm{2}} {x}\right)}{{x}^{\mathrm{2}} } \\ $$$${why}\:{it}\:{can}\:{not}\:{be}\:{solved}\:{this}\:{way} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {{lim}}\:\frac{{sin}\left(\pi{cos}^{\mathrm{2}} {x}\right)}{{x}^{\mathrm{2}} } \\ $$$$=\underset{{x}\rightarrow\mathrm{0}} {{lim}}\:\frac{{sin}\left(\pi{cos}^{\mathrm{2}} {x}\right)}{\pi{cos}^{\mathrm{2}} {x}}×\underset{{x}\rightarrow\mathrm{0}}…
Question Number 60370 by ANTARES VY last updated on 20/May/19 Answered by math1967 last updated on 20/May/19 $$\mathrm{0} \\ $$ Answered by tanmay last updated…
Question Number 125905 by MathSh last updated on 15/Dec/20 $${Calculate}\:{the}\:{correlation} \\ $$$${coefficient}\:{and}\:{construct} \\ $$$${the}\:{regression}\:{equation}: \\ $$$$\boldsymbol{{X}}_{\boldsymbol{{i}}} :\:\mathrm{11};\mathrm{11};\mathrm{9};\mathrm{12};\mathrm{13};\mathrm{14};\mathrm{11} \\ $$$$\boldsymbol{{Y}}_{\boldsymbol{{i}}} :\:\mathrm{13};\mathrm{14};\mathrm{12};\mathrm{16};\mathrm{17};\mathrm{17};\mathrm{15} \\ $$ Terms of Service…
Question Number 191435 by Matica last updated on 24/Apr/23 $$\:{It}\:{is}\:{given}\:{that}\:{I}_{\mathrm{1}} =\int{xg}\left[{x}\left(\mathrm{1}−{x}\right)\right]{dx}\:,\: \\ $$$${I}_{\mathrm{2}} =\:\int{g}\left[{x}\left(\mathrm{1}−{x}\right)\right]{dx}.\:{Find}\:\frac{{I}_{\mathrm{2}} }{{I}_{\mathrm{1}} }.\:{Thanks}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 60362 by ANTARES VY last updated on 20/May/19 Commented by ANTARES VY last updated on 20/May/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125882 by harckinwunmy last updated on 14/Dec/20 $$\mathrm{suppose}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{set}\:\mathrm{of}\left\{\mathrm{3}>\mid\mathrm{c}+\mathrm{1}\mid\&\mid\mathrm{d}−\mathrm{1}\mid<\mathrm{10}\right\} \\ $$$$\mathrm{is}\:\mathrm{x}<\mathrm{c}+\mathrm{d}<\mathrm{y},\:\mathrm{then}\:\left(\mathrm{x},\mathrm{y}\right)=? \\ $$ Commented by talminator2856791 last updated on 15/Dec/20 $$\:\left(−\mathrm{12};\:\mathrm{11}\right)? \\ $$ Commented…