Question Number 60347 by ANTARES VY last updated on 20/May/19 Commented by ANTARES VY last updated on 20/May/19 $$\boldsymbol{\mathrm{calculate}} \\ $$ Answered by mr W…
Question Number 125881 by aurpeyz last updated on 14/Dec/20 $${find}\:{the}\:{greatest}\:{coeeficient}\:{of} \\ $$$$\left(\mathrm{1}+\frac{{x}}{\mathrm{2}}\right)^{−\mathrm{2}} \\ $$$${i}\:{have}\:{applied}\:{Q}.\mathrm{125697}\:{but}\:{i}\:{got}\:{two} \\ $$$${negative}\:{values}\:{of}\:{n}\:{after}\:{i}\:{have} \\ $$$${made}\:{k}=\mathrm{2}{n}\:{for}\:{positive}\:{coefficient}. \\ $$$$ \\ $$$${I}\:{believe}\:{it}\:{should}\:{have}\:{a}\:{greatest} \\ $$$${coeeficient}\:{since}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{{k}} {decreases}\:{as}…
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Question Number 191409 by null last updated on 23/Apr/23 Answered by senestro last updated on 24/Apr/23 $$−\frac{{x}}{\mathrm{6}\left(\mathrm{1}+{x}^{\mathrm{3}} \right)^{\mathrm{2}} }+\frac{{x}}{\mathrm{18}\left(\mathrm{1}+{x}^{\mathrm{3}} \right)}+\frac{\mathrm{1}}{\mathrm{9}}\mathrm{ln}\:\left(\frac{\left(\mathrm{1}+{x}\right)^{\mathrm{3}} }{\mathrm{1}+{x}^{\mathrm{3}} }\right)+\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}{arctan}\left(\frac{\mathrm{2}{x}−\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right)+{C} \\ $$ Terms…
Question Number 191410 by otchereabdullai last updated on 23/Apr/23 $$\:{Three}\:{villages}\:{A},\:{B}\:{and}\:{C}\:{are}\:{on}\:{a}\: \\ $$$$\:{straight}\:{road}\:{and}\:{B}\:{is}\:{the}\:{mid}-{way} \\ $$$${between}\:{A}\:{and}\:{C}.\:{A}\:{motor}\:{cyclist} \\ $$$${moving}\:{with}\:{a}\:{uniform}\:{acceleration} \\ $$$${passes}\:{A},\:{B}\:{and}\:{C}.\:{The}\:{speeds}\:{with}\: \\ $$$${which}\:{the}\:{motorcyclist}\:{passes}\:{A}\:{and}\: \\ $$$${C}\:{are}\:\mathrm{20}{ms}^{−\mathrm{1}} \:{and}\:\mathrm{40}{ms}^{−} \:{respectively}. \\…
Question Number 125867 by joki last updated on 14/Dec/20 $$\mathrm{partial}\:\mathrm{fraction}\:\mathrm{with}\:\mathrm{detail}\:\mathrm{step}\:\mathrm{by}\:\mathrm{step}\:\mathrm{from} \\ $$$$\frac{\mathrm{4x}^{\mathrm{3}} +\mathrm{x}^{\mathrm{2}} +\mathrm{1}}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{2}\right)^{\mathrm{3}} } \\ $$ Answered by mathmax by abdo last updated…
Question Number 191397 by sonukgindia last updated on 23/Apr/23 Commented by a.lgnaoui last updated on 24/Apr/23 Answered by a.lgnaoui last updated on 24/Apr/23 $$\mathrm{totale}\:\mathrm{40}\:\mathrm{triangles} \\…
Question Number 125862 by mathdave last updated on 14/Dec/20 Answered by bramlexs22 last updated on 14/Dec/20 $$\sqrt{\frac{\mathrm{7}^{\mathrm{2012}} \left(\mathrm{49}−\mathrm{1}\right)}{\mathrm{12}}}\:=\:\sqrt{\mathrm{7}^{\mathrm{2012}} ×\mathrm{4}} \\ $$$$\:=\:\mathrm{2}×\mathrm{7}^{\mathrm{1006}} \:=\:{a}×\mathrm{7}^{{b}} \\ $$$${a}=\mathrm{2}\:\wedge\:{b}=\mathrm{1006} \\…
Question Number 191399 by sonukgindia last updated on 23/Apr/23 Commented by a.lgnaoui last updated on 24/Apr/23 Answered by a.lgnaoui last updated on 24/Apr/23 $$\mathrm{totale}\:\mathrm{28}×\mathrm{2}=\mathrm{56} \\…
Question Number 125848 by zarminaawan last updated on 14/Dec/20 $$\left.\mathrm{1}\right)\:\:\:\:\:{f}\left({x}\right)=\mathrm{2}{x}^{\mathrm{3}} −\mathrm{5}{x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{5}\:\:\:\:\:\left[−\mathrm{1},\mathrm{2}\right] \\ $$$$\left.\mathrm{2}\right)\:\:\:\:\:{h}\left({x}\right)={x}^{\mathrm{4}} +{x}−\mathrm{3}\:\:\:\:\:\:\:\:\left[−\mathrm{2},\mathrm{0}\right] \\ $$$${check}\:{the}\:{given}\:{function}\:{have}\:{at}\:{least}\:{one}\:{sol}\:{over}\:{the}\:{given}\:{intervals}\:{by}\:{using}\:{intermediate}\:{value}\:{theorem} \\ $$ Terms of Service Privacy Policy Contact:…